I have the following form code:
<form action="pdf.php" method="POST" id="pdfform">
<input type="hidden" name="htmlcontent" value="<?php echo $content ?>" >
<li>Download as PDF</li>
</form>
However, what i realise is that the hidden field prints out the content to the HTML page as well, and there are some extra " and > which should not be there.
What i think could be the issue is because the role of the form is to send the html data to a PHP script to convert it to a PDF, the variable $content contains html code, for example: <p>Test 3</p><p><img alt="Cancer" src="http://breakthroughs.cityofhope.org/wp-content/uploads/2013/02/lung-cancer.jpg" style="height:375px; width:500px" /></p>
This could be one of the causes of the issue and the html prints out the extra "> at the end of the value inside the hidden form as well.
Anyone could find out the reason?
Not sure if this is what you want, but have you considered using jquery to set the hidden field? for example (after ensuring you have no single quotes in your $content variable):
<script type='text/javascript'>
$('[name=htmlcontent]').val('<?php echo str_replace("'","`",$content) ?>');
<script>
Related
So I have a PHP code similar to this
<?php
//some code here
?>
<form>
<input />
</form>
And according to this example, I want to get the input's content to use further in PHP and/or insert in the desired input some variables from my PHP code, how can I perform this?
You can post the data to php from a HTML form
<?php
// data is available in php POST array
var_dump($_POST);
// create a var to hold the post data
$sNameOfPostVar = "";
// if posted, set the var to the value of the posted content
if(isset($_POST['NameOfPostVar'])){
$sNameOfPostVar = $_POST['NameOfPostVar'];
}
?>
<!-- current action is blank to send to same page as php script -->
<form method='post' action=''>
<input name='NameOfPostVar' value='<?php echo $sNameOfPostVar;?>' />
</form>
I've a column inside my table to put Html codes, I will use this table for email templating.
I have inside my page, all the templates inside my table, with two buttons, one to remove, and another one to edit.
The edit button shows the code inside a textbox, and to do the preview I did an echo to the code column.
<div class="tempcolumn">
<div><textarea name="ai" rows="15" cols="100" name="code" placeholder="Code">
<?php echo $get_temp; ?></textarea></div>
</div>
Preview
<div class="tempcolumn">
<p><?php echo $get_temp; ?></p>
<div></div>
</div>
To recognize the code and the id i created an hidden input
<input type="hidden" name="temp_id" value="'.$val['template_id'].'">
<input type="hidden" name="temp_code" value="'.$val['text'].'">
The script is working, but when i insert inside the code column some "<" or "=" doesn't work
Is inferfering because it reads the input value like this:
<input type="hidden" name="temp_id" value=" Value here + 'random character that closes the tag' ">
Is there a easier way to do that?
Thanks
You can try;
htmlspecialchars($value)
This will convert html characters to their non-interfering cousins.
See http://docs.php.net/manual/en/function.htmlspecialchars.php as I can't post the equivalents without them becoming characters.
I have this Code:
<div contenteditable="true"><p><?php echo $row[1]; ?></p></div>
Can I take the contents of the div and send them as a POST parameter in order to use them in the PHP. It would be good if I can use: onchange="this.form.submit()".
Thanks!
It is not possible to post contents of div tags, as this is only possible on form elements. The workaround for this would be to use some Javascript that populates a hidden field when a form is submitted, and the hidden field is posted instead.
Observe the following HTML. See that there is an onsubmit event attached to the form element. What we're saying to the browser here is when the form is submitted, first call the Javascript function process, and only submit if said function returns true:
<form method="post" action="process.php" onsubmit="javascript: return process();">
<input type="hidden" id="hidden" name="content" vlaue="<?php echo $row[1] ?>">
<div contenteditable="true" id="content"><p><?php echo $row[1] ?></p></div>
<button type="submit">Post</button>
</form>
This would be your Javascript. What you're doing is getting the innerHTML of the element with the id content and assigning it to the value of the element with the id hidden and return true so the form can be successfully submitted:
<script>
function process() {
document.getElementById("hidden").value = document.getElementById("content").innerHTML;
return true;
}
</script>
And in the process.php file, just output the posted content:
var_dump("Posted content: " . $_POST['content']);
Hope this helps!
I'm pretty new to the whole PHP/HTML deal, and I've run into a problem that I don't know how to fix. It's a pretty simple form that lets you enter data into database. The PHP code is as following:
<?
include("../sqlcontext.php");
$foo = mysql_query("SELECT*FROM users WHERE checksum='".$_COOKIE['userCookie']."'");
if($_COOKIE['userCookie'] == '' || !mysql_num_rows($foo)){
echo 'Du er ikke logget ind :( log ind her';
}
else{
if($_POST['genreKnap']){
$nameGenre = $_POST['nameGenre'];
$textGenre = $_POST['textGenre'];
$succes = mysql_query("INSERT INTO genre VALUES('null','$nameGenre','$textGenre')");
if($succes){
echo 'Yay!';
}else {
echo 'Oh no';
}
}
?>
The form is as following:
<form name="form1" method="post" enctype="text/plain" action="">
<table>
<tr>
<td>Genre navn:</td>
<td><input type="text" name="nameGenre" id="nameGenre" style="width:100%; padding-right: 1px" /></td>
</tr>
<tr>
<td>Genre beskrivelse:</td>
<td><textarea name="textGenre" id="textGenre" style="width:100%; padding-right: 1px"></textarea></td>
</tr>
<tr>
<td></td>
<td><input type="submit" name="genreKnap" id="genreKnap" value="Go!"/></td>
</tr>
</table>
</form>
Whenever I press the submit button, it seems as though it acts as if it was a get method and not a post.
Aha!!!
You are not posting the form correctly.
Set the
action=""
to
action="code.php"
Assuming your php page is called code.php. Just change it to the name/path of the php page and the form will send the data to your php code to process.
When you leave action="" to blank, it posts the data to itself (the same page). It is not acting as GET, it is still acting as POST, but posting to the wrong place. I think you worded the title of the question wrong.
What do you mean it is acting like get instead of post.
Can you not read $_POST variables in your PHP?
remove the 'enctype="text/plain"' in your form code.
enctype="text/plain"
Take that out. It is provided for debugging purposes only and doesn't generate anything that is sane to parse with a machine.
Valid form enctypes:
application/x-www-form-urlencoded: This is the default content type
multipart/form-data
The content type "application/x-www-form-urlencoded" is inefficient
for sending large quantities of binary data or text containing
non-ASCII characters. The content type "multipart/form-data" should be
used for submitting forms that contain files, non-ASCII data, and
binary data.
Source: http://www.w3.org/TR/html401/interact/forms.html#h-17.13.3.4
You're all ignoring the primary question and focusing on irrelevent items.
First of all more than anything he's using a short php opener <? not <?php now not every web server accepts short openers first up check that.
Echo out your $_POST vars and see if they're returning the correct items
echo "POSTS BELOW<br />";
echo $_POST['nameGenre']."<br />";
echo $_POST['textGenre']."<br />";
echo "<br />GETS BELOW<br />";
echo $_GET['nameGenre']."<br />";
echo $_GET['textGenre']."<br />";
Put this block of code directly below your php opener see what data it returns.
Also this if($_POST['genreKnap']){ is generally a bad way of doing it as its user input the safest way is a hidden field <input type="hidden" name="action" id="action" value="dopost" /> and change your if clause to if($_POST['action']=="dopost && isset($_POST['action'])){
Also set your form action="" to the actual page name not blank
Give all that a try and if its still not working we'll try something different
If you are send normal data without any files by the form .
Then enctype is not always needed .
But even if you want to include it
The correct way is :
enctype="multipart/form-data"
Also give a url in the action method of the form : <form action='example.php'>
I hope it solves the problem .
<form id="enter" action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" onsubmit="return validateForm(this);" >
<p>
<input id="submitBtn" name="submitDetails" type="submit" value="Submit Details" onClick="myClickHandler(); return false;" />
</p>
</form>
<script type="text/javascript">
function myClickHandler(){
if(validation()){
showConfirm();
}
}
</script>
<?php
session_start();
$outputDetails = "";
$outputDetails .= "<table id='sessionDetails' border='1'>
<tr>
<th>Number of Sessions:</th>
<th>{$_POST['sessionNum']}</th>
</tr>";
$outputDetails .= "</table>";
echo $outputDetails;
?>
Above is the code for my form. What I am trying to do is that if the user submits the form, then it will go back to its own page. But if the "SessionNum" equals '1', then instead of posting the form to itself, it should post the form or in other words navigate to the "session_marks.php' page but it is not idng this, if sessionNum equals 1 then it still submits form or navigate back to its own page, what am I doing wrong?
Also lets say it displays a number for the sessionNum and then I submit the form and it submits the form back to itself, the number disappears, how do I keep the number displayed when submitting the form to itself?
Thanks
Where is the conditional logic to change the target of the form post? All I see in the form tag is this:
action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>"
This will always set the form's action to be the current PHP file, not any other PHP file. If you want to conditionally post to a different file, you'll need to add conditional logic in there. Something like this (though there may be better ways to do it, keep in mind that I'm very out of practice with PHP):
action="<?php $_POST['sessionNum'] == 1 ? echo 'session_marks.php' : echo htmlentities($_SERVER['PHP_SELF']); ?>"
As for the number disappearing, I don't see any form element with the name sessionNum. If there isn't such a form element, then there will be nothing in $_POST['sessionNum'], so the number will "disappear" because there's no value to be displayed.
If the above is your actual code, session_start(); has to be placed before ANY other output (html, php's echo, print etc...)