I'm trying to do this join in laravel query builder but it is throwing and error. I'm using and Mysql DB.
This is my sql:
select c.*, d.* from notas_cabecera c
join notas_detalle d on (c.codigo_nota = d.codigo_nota)
where c.codigo_nota in (select r.codigo_nota from reportes r);
And this is my laravel query:
$lista_reportes = DB::table('notas_cabecera')
->join('notas_detalle', 'notas_cabecera.codigo_nota', '=', 'notas_detalle.codigo_nota')
->whereIn('notas_cabecera.codigo_nota', function($query)
{
$query->select(
DB::table('reportes')->select('reportes.codigo_nota')
);
})
->get();
What I'm doing wrong? please help.
$lista_reportes = DB::table('notas_cabecera')
->join('notas_detalle', 'notas_cabecera.codigo_nota', '=', 'notas_detalle.codigo_nota')
->whereIn('notas_cabecera.codigo_nota', function($query)
{
$query
->select('reportes.codigo_nota')
->from('reportes');
})
->get();
Related
i am having this query with me which needs to be written in the eloquent form on internet not able to find exact solution for my problem.
SELECT
query_id, t1.time, result, platform_id
FROM
query_logs t1
WHERE
t1.time = (SELECT
MAX(time)
FROM
query_logs t2
WHERE
t1.query_id = t2.query_id);
i tried writing it as below i used query_Logs as model to my controller:
$bmdata = Query_Logs::select('query_id', 'time','result','platform_id')
->where('time', function($q){
$q->from('query_logs')
->selectRaw('max(time)')
->where('query_id', '=', 'query_id')
})
->get();
Can you guys help me with the same.
Use this:
$bmdata = Query_Logs::select('query_id', 'time', 'result', 'platform_id')
->where('time', function($q) {
$q->from('query_logs as t2')
->selectRaw('max(time)')
->whereColumn('t2.query_id', '=', 'query_logs.query_id');
})->get();
I have following query that I need to achieve in Laravel eloquent:
SELECT Q.quoteid
FROM `tblquote` Q
INNER JOIN tbladdress A ON A.addressid = Q.addressid
INNER JOIN tblquotecompany QC ON QC.quoteid = Q.quoteid
INNER JOIN tblcompany C ON C.companyid = QC.companyid
WHERE
Q.useremail = 'test#test' or
(Q.ipaddress = '000.00.00.' and A.zipcode = '00000')
I have all relation set up in laravel.
I am trying to achieve this like below:
$this->eloquentQuote->newQuery()
->with(EloquentQuote::RELATION_ADDRESS)
->with(EloquentQuote::RELATION_QUOTE_COMPANIES . '.' . EloquentQuoteCompany::RELATION_COMPANY)
->whereHas(EloquentQuote::RELATION_ADDRESS,
function ($query) use ($userEmail, $userIp, $zipCode) {
/** #var Builder $query */
$query->where([
[EloquentQuote::USER_EMAIL, '=', $userEmail],
])
->orWhere([
[EloquentQuote::IP_ADDRESS, '=', $userIp],
[EloquentAddress::ZIP_CODE, '=', $zipCode],
]);
})->get();
This Eloquent query is giving expected result but taking too much time.
Is there any other way to do that efficiently?
Your help is highly regarded.
I hope the following code will be helpfull for you
$result = DB::table('tblquote')
->join('tbladdress', 'tbladdress.addressid', 'tblquote.addressid')
->join('tblquotecompany', 'tblquotecompany.quoteid', 'tblquote.quoteid')
->join('tblcompany', 'tblcompany.companyid', 'tblquotecompany.companyid')
->where('tblquote.useremail', 'test#test')
->orWhere([['tblquote.ipaddress','000.00.00.'], ['tbladdress.zipcode', '00000']])
->get();
I have this query that successfully run on mysql workbench:
SELECT
any_value(u.username),
any_value(b.name),
any_value(gc.visit_cycle_id),
any_value(gc.group_number),
any_value(dc.total_customer),
count(*) as total_day
FROM
trackgobackenddb.group_cycles gc
LEFT JOIN (
SELECT
any_value(dc.group_cycle_id) as group_cycle_id,
count(*) as total_customer
FROM
trackgobackenddb.destination_cycles dc
GROUP BY dc.group_cycle_id
) dc ON dc.group_cycle_id = gc.id
LEFT JOIN visit_cycles vc ON gc.visit_cycle_id = vc.id
LEFT JOIN users u ON vc.user_id = u.id
LEFT JOIN branches b ON vc.branch_id = b.id
GROUP BY gc.visit_cycle_id, gc.group_number;
How to convert that query so I can use laravel eloquent or query builder?
You can use DB::select to run complex raw SQL
$sql = "";
$data = DB::select($sql);
Here's my untested attempt using the query builder:
DB::table('group_cycles AS gc')
->leftJoin('destination_cycles AS dc', function ($join) {
$join->on('dc.group_cycle_id', '=', 'gc.id')
->select(['dc.group_cycle_id AS group_cycle_id', DB::raw('select count(*) AS total_customer')]);
})
->leftJoin('visit_cycles AS vc', function ($join) {
$join->on('gc.visit_cycle_id', '=', 'vc.id');
})
->leftJoin('users AS u', function ($join) {
$join->on('vc.user_id', '=', 'u.id');
})
->leftJoin('branches AS b', function ($join) {
$join->on('vc.branch_id', '=', 'b.id');
})
->groupBy('gc.visit_cycle_id', 'gc.group_number')
->get();
I have the following MySQL query:
SELECT
*
FROM
news_posts
WHERE
user_id = ?
AND id NOT IN (SELECT
post_id
FROM
user_read
WHERE
user_id = ?)
I want to make it more "eloquent". I've tried the following, but its (obviously) not working:
NewsPost::where('user_id', Auth::id())
->whereNotIn(function ($query) {
$query->DB::table('user_read')
->select('post_id')
->where('user_id', Auth::id());
})->get();
I'm assuming the 'where' method is executing a simple SQL query on 'new_posts' table. Can you try to rewrite this query and let mysql do the filtering for new posts? (search for LEFT OUTER JOIN on mysql)
SELECT *
FROM news_posts a
JOIN user_read b
ON a.id = b.post_id
WHERE a.user_id = ?
AND b.post_id IS NULL;
Thanks for all the replies! Got it working with the following tweaks:
NewsPost::where('user_id', Auth::id())
->whereNotIn('id', function ($query) {
$query->select('post_id')
->from('user_read')
->where('user_id', Auth::id());
})
->get();
I am trying to make the following query in laravel:
SELECT a.name AS subname, a.area_id, b.name, u. id, u.lawyer_id,u.active_search,
FROM subarea a
LEFT JOIN user_subarea u ON u.subarea_id = a.id
AND u.user_id = ?
LEFT JOIN branch b ON a.area_id = b.id
The idea is to obtain the subareas and see if the search is activated by the user.
The user_subarea table might have a record that matches the id of the subarea table where the active_search is equal to 0 or 1. If it doesn't exist I would like the query to return null.
While I was able to achieve this in raw SQL when I try the same with eloquent in Laravel I am not returning any value. I have done the following:
$query = DB::table('subarea')
->join('user_subarea', function($join)
{
$value = \Auth::user()->id;
$join->on( 'subarea.id', '=', 'user_subarea.subarea_id')->where('user_subarea.user_id', '=',$value);
})
->leftJoin('branch', 'subarea.area_id', '=', 'branch.id')
->select('branch.name', 'subarea.name as subarea', 'user_subarea.active_search_lawyer', 'user_subarea.id' )
->get();
Any help will be much appreciated.
I found by myself the answer it was just to add a lefjoin in the first join. It is not in the laravel docs but works too.
$query = DB::table('subarea')
->lefjoin('user_subarea', function($join)
{
$value = \Auth::user()->id;
$join->on( 'subarea.id', '=', 'user_subarea.subarea_id')->where('user_subarea.user_id', '=',$value);
})
->leftJoin('branch', 'subarea.area_id', '=', 'branch.id')
->select('branch.name', 'subarea.name as subarea', 'user_subarea.active_search_lawyer', 'user_subarea.id' )
->get();
Try this one, If you get a problem, please comment.
$value = \Auth::user()->id;
$query = DB::table('subarea')
->where('user_subarea.user_id', '=',$value)
->leftJoin('user_subarea', 'subarea.id', '=', 'user_subarea.subarea_id')
->leftJoin('branch', 'subarea.area_id', '=', 'branch.id')
->select('subarea.name AS subname','subarea.area_id', 'branch.name', 'user_subarea.id','user_subarea.lawyer_id','user_subarea.active_search')
->get();