What is the simplest way to split this string using PHP? - php

Question

I have the below string in PHP.
:guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP
I need to create these variables from the string:
$nick = guest
$user = lbjpewueqi
$host = AF8A326D.E0B4A40D.F85DC93A.IP
What is the best function to use to do this?
Ideally I would like to create some sort of function so I can pass to it the string and what part I want returned.
For example:
$string = "guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP";
echo stringToPart($string, nick);
guest
echo stringToPart($string, nick);
lbjpewueqi
echo stringToPart($string, host);
AF8A326D.E0B4A40D.F85DC93A.IP

Answer 1

Another version:
function stringToPart($string, $part) {
if (preg_match('/^:(.*)!(.*)#(.*)/', $string, $matches)) {
$nick = $matches[1];
$user = $matches[2];
$host = $matches[3];
return isset($$part) ? $$part : null;
}
}
More strict than preg_split solutions - it checks separators order.

Answer 2

Maybe this code may helpful for you
$p = '/[:!#]/';
$s = ":guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP";
print_r( preg_split( $p, $s ), 1 );

Answer 3

You can declare a function like this:
$s = ":guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP";
function stringToPart($str, $part) {
$pat['nick'] = '/:(.*)!/';
$pat['user'] = '/.*!(.*)#/';
$pat['host'] = '/#(.*)/';
preg_match($pat[$part], $str, $m);
if (count($m) > 1) return $m[1];
return null;
}
echo stringToPart($s,'nick')."\n";
echo stringToPart($s,'user')."\n";
echo stringToPart($s,'host')."\n";

Answer 4

The below should do what you're looking for.
$pattern = "/[:!#]/";
$subject = ":guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP";
print_r(preg_split($pattern, $subject));
The pattern is specifying what characters to split on so you could in theory have any amount of characters here if there were other instance you needed to account for different strings being passed in.
To return the values instead of just printing then to the screen use this:
$pattern = "/[:!#]/";
$subject = ":guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP";
$result = preg_split($pattern, $subject));
$nick = $result[1];
$user = $result[2];
$host = $result[3];

Answer 5

stringToPart(':guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP','nick');
function stringToPart($string, $type){
$result['nick']= substr($string,strpos($string,':')+1,(strpos($string,'!')-strpos($string,':')-1));
$result['user']= substr($string,strpos($string,'!')+1,(strpos($string,'#')-strpos($string,'!')-1));
$result['host']= substr($string,strpos($string,'#')+1);
return $result[$type];
}

Answer 6

<?php
function stringToPart($string, $key)
{
$matches = null;
$returnValue = preg_match('/:(?P<nick>[^!]*)!(?P<user>.*?)#(?P<host>.*)/', $string, $matches);
if (isset($matches[$key]))
{
return $matches[$key];
} else
{
return NULL;
}
}
$string = ':guest!lbjpewueqi#AF8A326D.E0B4A40D.F85DC93A.IP';
echo stringToPart($string, "nick");
echo "<br />";
echo stringToPart($string, "user");
echo "<br />";
echo stringToPart($string, "host");
echo "<br />";
?>