Is there any way to catch fatal error using eval()? - php

Question

$code = 'php statement';
// getting perse error
function perse_error_check($code){
if(eval($code) === "true"){
return "no perse error";
}
if(eval($code) === "false"){
return "perse error found";
}
}
// getting fatal error
function fatal_error_check($code){
.......................................
.......................................
}
Can you help me to complete the second function? Actually I am not sure weather it is possible or not.

Answer 1

The following writes the PHP code to another file.
It then uses command line execution to parse the file and check for erros:
/* Put the code to be tested in a separate file: */
$code = '<?php echo "Test"; ?>';
file_put_contents('check.php', $code);
/* Parse that file and store the message from the PHP parser */
$x = exec( 'php -l check.php');
/* Check the message returned from the PHP parser */
if(preg_match('/Errors parsing/i',$x))
{
echo 'The code has errors!';
}
else
{
echo 'The code looks good!';
}
/* delete the file */
unlink('check.php');
The benefit is that the code doesn't run, it just gets parsed. However I assume you would then write that code to a file and use it... so like others mentioned, be VERY careful. Use things like open_basedir (and test it) to restrict access to specific directories, manually check the code before including it in production... etc.

Answer 2

There is a simple way. Put your PHP code in an another file. For an example: index.php and check.php . Put your PHP code in check.php.
Now in index.php write:
$check_data = file_get_contents("yourhosturl/allotherdirectory/check.php");
if(preg_match("/Fatal error/",$check_data)){
echo "fatal error found";
}