I am trying to check if a phone number like this exists in using regex.
(001) 33992292
So, I used
if(preg_match("/[0-9\(\)]+/", $row)){
//is phone number
}
But, the problem with this is that, strings containing numbers get passed as well, like foo134#yahoo.com, so how can I evaluate a phone number and exclude # character is strings all together?
UDPATED
/^(\(\d+\))*\s?(\d+\s*)+$/
you missed start string ^ sign and end string $ sign, what else your regex is wrong
because 5545()4535 will also pass match
You need to use anchors in your regular expression, a proper syntax would be:
if(preg_match('~^\(\d{3}\) *\d{8}$~', $row)) { ... }
Telephone numbers are notorious for people to get wrong - and by people I mean programmers.
For example, these are all "common" ways of writing a phone number:
(001) 33992292
001 33992292
00133992292
001 3399 2292
(001) 3399-2292
A saner approach it to just remove everything that isn't a number and check the length:
$phonenumber = "(001) 33992292";
$phonenumber = preg_replace("/[^0-9,.]/", "", $phonenumber );
if (strlen($phonenumber) == 11) {
// do thing
}
Related
I want to validate users phone numbers when they register in my website. I use this code to do this :
$mobile = mysql_real_escape_string($_POST['mobile']);
//check mobile validity
$options = array('options' => array('min_range' => 0));
if(filter_var($mobile, FILTER_VALIDATE_INT, $options) == FALSE)
{
$_SESSION['warnings']['warning_mobile'] = ENTER_VALID_MOBILE;
}
else
{
$_SESSION['warnings']['warning_mobile'] = '';
$_SESSION['temp_post']['mobile'] = $mobile;
}
As you can see the code check if this number contains valid int digits and if it is everything going ok if not it give me error message .
My problem is : This code does not accept numbers which starts with zero for example (0 555 555 5555 this is invalid number).
Is there a way to allow this code to accept this numbers starting with zero??
Leaving on a side the fact that with a regular expression you could solve this problem easily, there are a couple of things to consider:
$mobile is a string: filter_var($mobile, FILTER_VALIDATE_INT)
will allways return false.
do you want to consider digits only or you need to support numbers containing characters such as spaces, hyphen and plus? e.g. "+1 23-4555-555"
If you need to support "plain numeric" only, take a look to is_numeric. It checks if a variable is a number or a string made only by digits.
About your question:
Is there a way to allow this code to accept this numbers starting with
zero??
Your code doesn't work because $mobile is not an integer, and not because your number starts with 0.
The final suggestion still is to use a regexes, which are the optimal solution for this kind of problems.
This is to test version numbers. They need to contain only numbers, but can have multiple decimal points.
For example:
$a = '1.2.3';
is_numeric($a) returns false, and floatval($a) strips out the extra decimal sections, without returning a useful answer to the test.
Is there any PHP function that would do this?
You can use preg_match():
if(preg_match('~^([0-9]+(\.[0-9]+)*)$~', $string)) {
echo 'ok';
}
The regex pattern matches from the begin ^ to the end $ of the string and checks if it begins with a number and then contains only numbers - optionally separated by single dots - and ends with a number again.
You can use the strcspn function:
$q='1.2.3';
if (strcspn($q, '0123456789') != strlen($q))
echo "true";
else
echo "false";
I purchased a contact form. Great little thing but I need to convert the validation for the phone number to allow for UK number formats - in other words, to allow for spaces.
Right now it validates without spaces and has a minimum length of 8 characters:
if(is_numeric($phone))
{
if(!$phone || strlen($phone) < 8)
{
$error .= "Please enter your phone number without spaces.<br />";
}
}
else
{
$error .= "Please enter numeric characters in the phone number field.<br />";
}
Phone numbers are typically horrible for regex patterns, which is what you will need.
This pattern for example:
$pattern = "/^(\+44\s?7\d{3}|\(?07\d{3}\)?)\s?\d{3}\s?\d{3}$/";
$match = preg_match($pattern,$input);
if ($match != false) {
// We have a valid phone number
} else {
// We have an invalid phone number
}
That pattern will match with +44 included or not e.g.
all these will match:
07222 555555
(07222) 555555
+44 7222 555 555
These won't
7222 555555
+44 07222 555555
(+447222) 555555
There are a load of sites that offer tutorials / cheat sheets etc. for regular expressions try some of these:
http://regexlib.com/Default.aspx
as well as a very good stack overflow post:
A comprehensive regex for phone number validation
So you just want to allow spaces?
Then you could use str_replace() to ignore spaces, right at the beginning:
$phone = str_replace(' ', '', $phone);
The is_numeric function that you're using isn't really even a suitable choice for American phone numbers. For example it accepts hexadecimal numbers like 0xABCDEF, which it should reject.
For simple text matching like this, regular expressions are often the easiest solution. A regular expression specifies a pattern of text. PHP has functions to let you search for or replace regular expression matches in text.
If you define a phone number as a string of at least 7 characters containing only digits and spaces, the corresponding regular expression would be /^[0-9 ]{7,}$/. The text inside the brackets represents a set of characters, the {7,} indicates that we're looking for at least 7 of these characters in a row, and the ^ and $ indicate that our match should start at the beginning of the string and end at the end of the string. The PHP documentation has a section explaining regular expressions in greater detail.
You would use the preg_match function to
ensure the phone number matched:
if (preg_match('/^[0-9 ]{7,}$/', $phone)) {
This matches all UK formats with a wide variety of punctuation:
^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)(?:\d{5}\)?[\s-]?\d{4,5}|\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3})|\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4}|\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}|8(?:00[\s-]?11[\s-]?11|45[\s-]?46[\s-]?4\d))(?:(?:[\s-]?(?:x|ext\.?\s?|\#)\d+)?)$
Extract the various parts using this pattern
^\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)(44)\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)([1-9]\d{1,4}\)?[\s\d-]+)(?:((?:x|ext\.?\s?|\#)\d+)?)$
The country code is in $1 (and is null for national format). The NSN is in $2. The optional extension is in $3.
Remove all non-digits from $2 for further processing. The next step is to make sure the NSN is in a valid range and is a valid length (either 9 or 10 digits, depending on the range).
The list of patterns is too long to reproduce here but is available at:
http://aa-asterisk.org.uk/index.php/Regular_Expressions_for_Validating_and_Formatting_GB_Telephone_Numbers
You could parse the input to an integer, then validate for the correct number of digits;
$mobileNumber = intval($mobileNumber);
if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {
//number has the right number of digits for a UK mobile number
} else {
//number does not have the right number of digits
}
Explained;
$mobileNumber = intval($mobileNumber);
This removes all non numerical characters from the string, and leading zero (eg spaces, brackets, plus signs, decimals etc);
*if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {*
This regular expression then checks that the string contains either 12 or 10 digits which would cover 447712345678 (12 digits) or 7791234567 (10 digits). It is matched in two sub clauses (^\d{12}$) or (^\d{10}$) the carat (^) and dollar ($) represent to match everything from the very beginning (^) and to the very end ($) of the string. the \d represents any digit, and the following {12} means match the previous statement that number of times.
This does not mean that the number is valid, you could use an API like twillio to do additional validation of the numebr https://www.twilio.com/help/faq/sms/does-twilio-check-to-see-if-phone-numbers-can-receive-sms
For example;
$mobileNumber = '+447791234567';
$mobileNumber = intval($mobileNumber); //$mobileNumber is now 447791234567
if (preg_match('/(^\d{12}$)|(^\d{10}$)/',$mobileNumber)==TRUE) {
//$mobileNumber matches (^\d{12}$) and is valid
}
You could also add a check to ensure that number starts with either '07' or '447', required for UK mobiles, like this;
function isValidMobile($aNumber){
$aNumber = intval($aNumber);
return preg_match('/(^\d{12}$)|(^\d{10}$)/', $aNumber) && preg_match('/(^7)|(^447)/', $aNumber);
}
the intval removes leading zero,so the regular expression checks for a leadin 7 or 447.
I have found a solution with javascript according to the standards mentioned [here][1].**its not regex.**if you are using this solution there are three things to take care
validation can be used inside the UK
space cant be added. you need to type in your number without spaces
number has to begin with zero
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script >
var name=window.prompt("Enter cell number");
var sixformat=["013397","013398","013873","015242","015394","015395","015396","016973","016974","017683","017684","017687","019467","019755","019756"];
var twoformat=["01","02","03","05","07","08","09"];
sixdi=name.substring(0,6);
twodi=name.substring(0,2);
document.write("phone number:",name,"<br>");
document.write("phone-number length:",name.length);
if(sixformat.includes(sixdi)&&name.length==11)
{
document.write("<br><h1>valid</h1>");
}
else if(sixdi=="016977"&&name.length==10)
{
document.write("<br><h1>valid<h1>");
}
else if(twoformat.includes(twodi)&&(name.length==11))//011########
{
document.write("<br><h1>valid</h1>");
}
else if(twodi=="01"&&(name.length==10))
{
document.write("<br><h1>valid</h1>");
}
else if(name.substring(0,4)=="0800"&&(name.length==10))
{
document.write("<br><h1>Valid</h1></br>");
}
else
{
document.write("<h1>invalid</h1>");
}
</script>
</body>
</html>
I have encountered a strange IP which has redundant zero values among the octets. Is there anyway to properly validate this as an IP or use regular expression to remove those redundant zeroes?
example is of follows:
218.064.215.239 (take note of the extra zero at the second octet "064").
I do have one working IP validation function but it will not validiate this Ip properly due to the nature of the regular expression unable to accept that extra zero. Following is the code in PHP:
function valid_ip($ip) {
return preg_match("/^([1-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])" .
"(\.([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])){3}$/", $ip);
}
thanks for any help in advance peeps! :D
This will correct them:
$ip = "123.456.007.89";
$octets = explode(".", $ip);
$corrected = array();
foreach ($octets as $octet) {
array_push($corrected, (int)$octet);
}
echo implode(".", $corrected);
You have to accept the zero like this:
^(0?[1-9]|0?[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])(\.(0?[0-9]|0?[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])){3}$
Play with this regular expression on rubular.com.
The 0? I added matches zero or one occurence of 0. So 0?[1-9][0-9] for example matches both 010 and 10 for example.
Change the bare |1 occurrences to |[01]. Are you sure this is not supposed to be interpreted as an octal number, though? Some resolvers do that.
Use ip2long().
You should figure out where those extra zeroes are coming from. Those leading zeroes can't be just dropped. On most platforms they mean that the octet is in octal form instead of decimal. That is: 064 octal equals 52 decimal.
Did you have a go yourself? It's really quite simple.
|1[0-9][0-9]| matches 100-199, as you are now wanting to match 000-199 (as above that it is 200-155) you just need to make a set for the 1 to be 1 or 0.
function valid_ip($ip) {
return preg_match("/^([1-9]|[1-9][0-9]|[01][0-9][0-9]|2[0-4][0-9]|25[0-5])".
"(\.([0-9]|[1-9][0-9]|[01][0-9][0-9]|2[0-4][0-9]|25[0-5])){3}$/", $ip);
}
And that can be refactored down (allowing leading zeroes) to:
function valid_ip($ip) {
return preg_match("/^([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])".
"(\.([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])){3}$/", $ip);
}
Or to strip these unneeded zeros:
function strip_ip($ip) {
return preg_replace( '/0+([^0])(\.|$)/' , '$1$2' , $ip );
}
This question already has answers here:
php validate integer
(7 answers)
Closed 9 years ago.
Hey I'm trying to perform input validation in PHP to ensure that the stock values that are typed in are at least 1 positive integer and from 0-9. Should not contain any special characters.
For example, any of the following values should be valid:
7
0
32
47534
The following SHOULD NOT be valid:
asdf
35/gdf
../34.
etc..
I'm using the following if statement to check for the positive integer value of "$original_stock".
if (preg_match("/^[0-9]$/", $original_stock))
{
$error .="Original stock must be numerical.";
}
Additionally, I have a price field which should be validated as either an int or a double.
If there's an easier alternative to using regex, that's okay too!
Thanks in advance :)
Try this regexp:
/^\d+$/
The issue with your existing regexp is that it only matches strings with exactly one digit.
As for validating an int or a double:
/^\d+\.?\d*$/
Note that that regexp requires that there be at least one digit.
Use:
/^[0-9]+$/
The + means "one or more". Without it, your regex will only match a single digit. Or you could use the simpler variant:
/^\d+$/
For floats, try something like:
/^\d+(\.\d{1,2})?/
This will match one or more digits, optionally followed by a . and one or two digits. (i.e. .12 will not match.)
To save yourself some headaches, you can also use the is_int and is_float functions.
Lastly; note that your check is wrong. preg_match will return 0 if it fails, so you should write it as:
if (!preg_match("/^\+$/", $original_stock)) {
// error
}
(note the !).
You may want to use the
is_int
Don't reinvent a wheel slower than an existing one, use a motorcycle: is_int.
#Assuming $original_stock is a single value...
if (is_int($original_stock)) {
#Valid, do stuff
}
else {
#Invalid, do stuff
}
#Assuming $original_stock is an array...
$valid = true;
foreach ($original_stock as $s) {
if (!is_int($s)) {
$valid = false;
break;
}
}
if ($valid) {...}
else {...}
I just ran into this exact problem and solved it this way using the regex.
I think the problem is your caret ^.
/^[0-9]$/
I moved it inside the class and got the results I needed.
function validate_int($subject)
{
//Pattern is numbers
//if it matches anything but numbers, we want a fail
$pattern = '/[^0-9]/';
$matches = preg_match($pattern, $subject);
if($matches > 0)
return false;
else
return true;
}