PHP Multiple file upload and store the names in Database - php

Question

I am PHP beginner and building my own practice project (I have thought it something like used car sale online site)
My problem is very similar to multiple file upload sql/php and Multiple file upload in php
Here are list of my problems
I want to upload image in a directory and store it's name in database. So far below code is working fine (if I upload 1 file). I am trying to add 3 more file input option so that user can upload upto 4 images.
So far trying different codes available in stackoverflow and other online sites, I have been able to atleast upload the multiple files in my directory. But the real problem is that I don't know how I would store the name of the file in database .
(In most of the tutorials and suggestions, I found I should use 1 input file type with multiple attributes or name equals array like file[] and run foreach loop. But I couldn't figure out how would go ahead and get the file name of each input and store it in database.
Below are my code for the reference.
//this is my form.addVehicle.php file to process the form
<?php
define("UPLOAD_DIR", "../uploads/");
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$name = "default.jpg";
if (is_uploaded_file($_FILES["myFile"]['tmp_name'])) {
$myFile = $_FILES["myFile"];
if ($myFile["error"] !== UPLOAD_ERR_OK) {
echo "<p>An error occurred.</p>";
exit;
}
// ensure a safe filename
$name = preg_replace("/[^A-Z0-9._-]/i", "_", $myFile["name"]);
// don't overwrite an existing file
$i = 0;
$parts = pathinfo($name);
while (file_exists(UPLOAD_DIR . $name)) {
$i++;
$name = $parts["filename"] . "-" . $i . "." . $parts["extension"];
}
// preserve file from temporary directory
$success = move_uploaded_file($myFile["tmp_name"],
UPLOAD_DIR . $name);
if (!$success) {
echo "<p>Unable to save file.</p>";
exit;
}
// set proper permissions on the new file
chmod(UPLOAD_DIR . $name, 0644);
}
include_once ('../class/class.Vehicle.php');
$vehicle = new Vehicle(
$_POST['make_id'],
$_POST['yearMade'],
$_POST['mileage'],
$_POST['transmission'],
$_POST['price'],
$_POST['zone_name'],
$name,
$_POST['description']
);
}
?>
//To give a try, tested is_uploaded_file condition four different times with //different file name id like myFile1,myFile2...and path variable as $name1, //$name2...and it works as I want it to be...but I'm sure that' not the correct //way to do it..
//This is my class file with name class.Vehicle.php
include_once('class.pdoDbConnnection.php');
class Vehicle{
private $make_id;
private $yearMade;
private $mileage;
private $transmission;
private $price;
private $zone_name;
private $image_path;
private $description;
public function __construct($make_id, $yearMade, $mileage, $transmission, $price, $zone_name, $image_path, $description){
$this->make_id = $make_id;
$this->yearMade = $yearMade;
$this->mileage = $mileage;
$this->transmission= $transmission;
$this->price = $price;
$this->zone_name = $zone_name;
$this->image_path = $image_path;
$this->description = $description;
try{
$sql = "INSERT INTO cars (car_id, make_id, yearmade, mileage, transmission, price, zone_name,image_path, description) VALUES (?,?,?,?,?,?,?,?,?)";
$pdo = new DBConnection();
$stmt = $pdo->prepare($sql);
$stmt->execute(array(NULL,$this->make_id,$this->yearMade,$this->mileage,$this->transmission,$this->price,$this->zone_name,$this->image_path,$this->description));
}
catch (PDOException $e)
{
echo $e->getMessage();
}
}
}
Here are my mySql table columns (I want to insert file names in the column..while displaying it in the client side, I'm using it this way: <img alt="image" class="img-responsive" src="../uploads/<?php echo $row['image_path'] ?>">
car_id , make_id , zone_id, yearmade, mileage, transmission, price, image_path, image_path1, image_path2, image_path3, description
This is my client side form to add new cars....
..................
<form class="form-horizontal" role="form" method="post" action="../includes/form.addVehicle.php" enctype="multipart/form-data">
.....................
<div class="form-group">
<label for="description" class="col-sm-2 control-label">Upload Image</label>
<div class="col-sm-4">
<input type="file" class="form-control" id="myFile" name="myFile">
</div>
</div>
<div class="form-group">
<label for="description" class="col-sm-2 control-label">Upload Image</label>
<div class="col-sm-4">
<input type="file" class="form-control" id="myFile1" name="myFile2">
</div>
</div>
<div class="form-group">
<label for="description" class="col-sm-2 control-label">Upload Image</label>
<div class="col-sm-4">
<input type="file" class="form-control" id="myFile3" name="myFile3">
</div>
</div>
..............

Answer 1

Finally I ended up with the following code.
P.S. Thanks to #Andy-Brahman insight at Multiple file upload in php
<?php
if(isset($_POST['submit'])){
$uploads_dir = '../test_uploads';
foreach ($_FILES["pictures"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
$tmp_name = $_FILES["pictures"]["tmp_name"][$key];
$name = $_FILES["pictures"]["name"][$key];
// I don't want to overwrite the existing file
$i = 0;
$parts = pathinfo($name);
while (file_exists($uploads_dir . "/" . $name)) {
$i++;
$name = $parts["filename"] . "-" . $i . "." . $parts["extension"];
}
move_uploaded_file($tmp_name, "$uploads_dir/$name");
}
}
// Test to see if I get the uploaded file name which i want to insert into database table column.
echo "<pre>";
print_r($_FILES['pictures']['name'][0]);
echo"</br></br>";
print_r($_FILES['pictures']['name'][1]);
echo"</br></br>";
print_r($_FILES['pictures']['name'][2]);
echo"</br></br>";
print_r($_FILES['pictures']['name'][3]);
echo"</br></br>";
echo "</pre>";
// test succeeds . Now I guess I can do something like $picture0 = $_FILES['pictures']['name'][0]);
// and insert $picture0,$picture1...into database..
// Am I doing everything correctly?
}

Answer 2

I will make example, you just adapt it for yourself.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files[]" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
the PHP goes (file_reciever.php):
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Handle other code here
}
}
}
}
?>