Twig extension function read value - php

I'm trying to create a set of simplified functions to let an user create a twig template that will be rendered as a form.
The form, when executed should read self generated data array.
The code below should print a field with name 'hello', when submitted (with example value 'world') create an array key hello and display the binded field with value 'world'.
Example template:
{{configkey('hello', 'Hello Field')}}
The extension function
$func = new Twig_SimpleFunction('configkey', function ($key='example', $label='label') {
echo '<div class="control-group">';
echo '<label class="control-label" for="' . $key . '">' . $label . '</label>';
echo '<div class="controls">';
echo '<input type="text" name="' . $key . '" value="{{config.' . $key . '}}"/>';
echo '</div>';
echo '</div>';
});
$this->_twigEnv->addFunction('configkey',$func);
the output

Thakns everyone for help but i found the solution easier than expected..
$func = new Twig_SimpleFunction('configkey', function ($key='example', $label='label', $value='') {
echo '<div class="control-group">';
echo '<label class="control-label" for="' . $key . '">' . $label . '</label>';
echo '<div class="controls">';
echo '<input type="text" name="' . $key . '" value="' . $value . '"/>';
echo '</div>';
echo '</div>';
});
The call will be
{{configkey('hello', 'Hello Field', config.hello)}}
Do you have a better aproach for the binding just using the key parameter ?

Related

PHP insert array from multiple checked checkbox and text input into mySQL

I have an issue when trying to insert info coming from a form which is generated dynamically in php.
The form consists of of an variable amount of inputs which all consists of four input elements. See below how my form is generated:
<?php $result = mysql_query("SELECT id,name,description FROM todo_q WHERE todo_id = $todo_id AND active = 'y'");
while($todo_q=mysql_fetch_array($result)){
echo '<label>';
echo $todo_q['name'];
echo '</label><br>';
echo '<input type="checkbox" name="value[]" value="y" />';
//echo '<input type="hidden" name="value[]" value="n" />';
echo '<label>';
echo $todo_q['description'];
echo '</label><br>';
echo '<input type="text" id="comment" name="comment[]">';
echo '<input type="hidden" name="user_id[]" value="';
echo $user_id;
echo '" />';
echo '<input type="hidden" name="todo_id[]" value="';
echo $todo_q['id'];
echo '" />';
echo '<HR>';
}?>
And this is how I try to insert the info into mySQL:
$query = "INSERT INTO todo_a (value, comment, user_id, todo_id) VALUES ";
$query_parts = array();
for($x=0; $x<count($_POST["value"]); $x++){
$query_parts[] = "('" . $_POST['value'][$x] . "','" . $_POST['comment'][$x] . "'," . $_POST['user_id'][$x] . "," . $_POST['todo_id'][$x] . ")";
}
$q_parts = $query_parts;
foreach ($q_parts as $q_p){
$insert = ($query .= implode(',', $query_parts));
$result = mysql_query($insert);
}
The problem I have is that when check all checkboxes and comments everything is inserted on the right row in the DB, but if I skip to check one checkbox then it gets messed up...
I would like it the insert a new row if it the checkbox is checked and/or a comment is entered.
Can anybody point me in the right direction?
I tried to put a hidden input to get the value of unchecked checkboxes but i doesn't seem to work.. That why I have commented out the hidden checkbox.
PS. I know I should be using mysqli but this is an older site that I haven't upgraded yet..
You need to add index into input checkbox and comment name like :
$cbIndex = 0;
while($todo_q=mysql_fetch_array($result)){
echo '<label>';
echo $todo_q['name'];
echo '</label><br>';
// Generate checkbox with index of current result
echo '<input type="checkbox" name="value[' . $cbIndex . ']" value="y" />';
// Generate comment with index of current result
echo '<input type="text" id="comment" name="comment[' . $cbIndex . ']">';
echo '<input type="hidden" name="user_id[' . $cbIndex . ']" value="';
echo $user_id;
echo '" />';
echo '<input type="hidden" name="todo_id[' . $cbIndex . ']" value="';
echo $todo_q['id'];
echo '" />';
echo '<HR>';
// Inc of index
$cbIndex++;
}
When you submit your form, only checked checkbox will appear in $_POST["value"] :
foreach ($_POST["value"] as $cbIndex => $cbValue) {
$query_parts[] = "('" . $_POST['value'][$cbIndex] . "','" . $_POST['comment'][$cbIndex] . "'," . $_POST['user_id'][$cbIndex] . "," . $_POST['todo_id'][$cbIndex] . ")";
// or
$query_parts[] = "('" . $cbValue . "','" . $_POST['comment'][$cbIndex] . "'," . $_POST['user_id'][$cbIndex] . "," . $_POST['todo_id'][$cbIndex] . ")";
}
...
Btw, you don't need to store value of checkbox, that will be 'y' all the time.
INFO That will be fine for a test app, but as commented by #Pogrindis and #John Conde, it's not safe code. MySQLi/PDO + prepare statement will avoid SQL injection.

Cant echo multiple values in array

I have something like this in my code:
<?php
foreach ($tomb2[1] as $key => $metaname){
$talalat = $tomb[1][$key];
echo '<p>' . "$metaname\n" . '</p>' . '<br>' . '<input type="text" name="metavalue[]" value="' . "$talalat\n" . '">' . '<br>';
}
?>
<input type="submit" name="Generálás" value="insert" onclick="insert()" />
</form>
I try to echo the several different values, however I get only the last one. Possibly the array contains only the last one. What am I doing wrong?
if you use a post method in form then you have to written $ertekek = $_POST["metavalue"] instead of $_GET["metavalue"] and then use print_r($ertekek)
instead of echo $ertekek;
You have written $talalat = $tomb[1][$key]; instead of $talalat = $tomb2[1][$key];

How do I capture the value in a select list loop in PHP?

I have a gender array as an example, but I am also using longer select list such as states. I want to capture the option value in a PHP varible that the client side user chooses. Then I can use that captured value in an email message.
function genderList() {
$gender = array('M'=>"Male",'F'=>"Female",);
return $gender;
}
$gender = genderList();
$email_form = '<?php $states = statesList(); ?>
<form class="aw-contact-form" method="post" action="' . get_permalink() . '">
<label for="cf_gender">' . $label_gender . '</label>
<select name="gender" id="cf_gender">
<option selected="selected"></option>';
foreach ($gender as $key => $value) {
$email_form .= '<option value="' . $key . '">' . $value . '</option>';
}
$email_form .= '</select>
</form>
return $email_form;
Any help will be greatly appreciated.

PHP displays tags in different order

I have following problem, I have list of products in a database and want to display them in table unfortunately it plays some tricks for me because it displays one td before table even begins.
Here are the PHP functions:
<?php
function displayProduct($code,$url)
{
echo '<form method="post" action="cart_update.php"><input type="hidden" name="code" value="' . $code . '"/>';
echo '<input type="hidden" name="return_url" value="' . $url . '" />';
echo '<input type="hidden" name="type" value="add" /><input type="submit" value="Add" /></form>';
}
function displayItem($obj,$url)
{
echo '<tr>';
echo '<td>' . $obj->menuposition . '</td><td>' . $obj->name . '</td><td>' . '£'.$obj->price . '</td><td>' . displayProduct($obj->code,$url) .'</td>';
echo '</tr>';
if(strlen($obj->description) > 2)
{
echo '<tr><td colspan="4" style="font-size: 10px;">' . $obj->description . '</td></tr>';
}
}
?>
And here is the HTML output that I get:
Could someone help me ?
The echo call from displayProduct happens before the echo call of displayItem occurs.
I can see two solutions.
1: displayProduct should return the things to write and not echo them.
2:
echo '<td>' . $obj->menuposition . '</td><td>' . $obj->name . '</td><td>' . '£'.$obj->price . '</td><td>';
displayProduct($obj->code,$url);
echo '</td>';
displayProduct($code,$url) should return the string instead of printing it out:
function displayProduct($code,$url)
{
$result = '<form method="post" action="cart_update.php"><input type="hidden" name="code" value="' . $code . '"/>';
$result .='<input type="hidden" name="return_url" value="' . $url . '" />';
$result .='<input type="hidden" name="type" value="add" /><input type="submit" value="Add" /></form>';
return $result
}
[Edit] I should read better the questions...
But this still applies:
Also as Adrian stated, you should not echo the lines in "displayProducts", but return a string.

How to echo multiple rows with data based on checkbox input?

Got stuck trying to echo out multiple rows with data based on checkbox input. As of current code it processes data from only one checkbox, no matter how many checkboxes are ticked. Please help!
while ($row = mysql_fetch_assoc($r)) {
$pals .= '<input type="checkbox" name="pal_num[]" value="'
. $row['pal_num'] . '">' . $row['pal_num'] . '<br>';
}
if ($pal == '') {
echo '';
} else {
echo '<form name="get_pal" action="post2.php" method="POST">';
echo $pals;
echo '<input type="submit" name="post" value="Go!">';
echo '</form>';
}
post2.php:
$w = $_POST['pal_num'];
$rrr = mysql_query("SELECT * FROM pl_tab WHERE pal_num" . $w[0]);
while ($row = mysql_fetch_array($rrr)) {
echo '<tr><td>' . '&nbsp' . '</td>';
echo '<td rowspan="5">' . $row['descr'] . '</td>';
echo '<td><b>' . 'Total weight' . '<b></td>';
echo '<td>' . '&nbsp' . '</td><td>' . '&nbsp' . '</td></tr>';
echo '<td>' . '&nbsp' . '</td>';
echo '<td colspan="3">' . '&nbsp' . '</td>';
//this part should multiple based on how many checkboxes are ticked.
echo '<tr><td>' . $row['l_num'] . '</td>';
echo '<td>' . $row['pal_num'] . '</td>';
echo '<td>' . $row['weight 1'] . '</td><td>' . $row['weight 2'] . '</td></tr>';
}
echo "</table>";
}
May be this will work :
$w = "'".implode("','",$_POST['pal_num'])."'";
$rrr = mysql_query("SELECT * FROM pl_tab WHERE pal_num in (".$w.");");
...and may be you forgot a echo "<table>"; before the while :)

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