I am trying to get data from two tables:
$con = getDbConnect();
$edit = $_GET['edit'];
if (mysqli_connect_errno($con)) {
"Failed to connect to MySQL: " . mysqli_connect_error();
} else {
$result = mysqli_query($con, "SELECT * FROM admininfo where email='" . $edit . "'");
$results = mysqli_query($con, "SELECT * FROM adminaccount where email='" . $edit . "'");
while ($admininfo = mysqli_fetch_array($result, $results)) {
You use a single query no matter how many tables you're selecting from, e.g.
SELECT a.*, b.* FROM table1 a, table2 b where a.id = ? AND b.id = ?
Then you fetch what you need from the result, take a look at the docs for that.
-- and, of-course, don't use select *.
Related
So I have this table 'users_photos'. It contains 38k rows with user pictures. Every row contains id, userid and link to the photo. So if a user have 3 pictures, that user id will show in 3 rows in the database.
What I want to do is count the number of users with 1 picture in the database, 2 pictures in the database etc.
UPDATE: I have now the following code
$sql = $mysqli->query("SELECT count(*), count_users from (SELECT u_id, count(*) as count_users FROM users_photos group by u_id) temp group by count_users");
$sql->data_seek(0);
while ($row = $sql->fetch_assoc()) {
echo "".$fetch." = " . $row['count_users'] . "\n<br>";
}
This prints the users that have 1 picture and up to 8. Not how many but only shows that in the database there is users that have 1 picture, 2 pictures etc. Now I need to figure out how to print the total users that have 1 picture etc.
Anyone have any tips? thanks on behalf!
Update Your Query With This
$sql = $mysqli->query("SELECT count(*),u_id as 'count_users' FROM users_photos group by u_id");
Sql Query:
$sql = $mysqli->query("SELECT count(*),u_id as 'count_users' FROM users_photos group by u_id");
You Can Print like this
// After Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT count(*),u_id as 'count_users' FROM users_photos group by u_id";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["id"]. " - count_users" . $row["count_users"]. "<br>";
}
} else {
echo "0 results";
}
You can do something like this:
$con = mysqli_connect("localhost","my_user","my_password","my_db");
$sql = 'SELECT u_id, count(*) AS count_users FROM users_photos GROUP BY u_id';
$result = mysqli_query($con, $sql);
while ($row=mysqli_fetch_assoc($result)) {
echo 'User id: ' . $row['u_id'] . ' Count: ' . $row['count_users'] . '<br>';
}
Keep in mind this is just a basic example. In a real world application there is more to do such as checking for errors.
I am working on a php script that will get the required information and display it in an xml. For some reason my brin isn't work and I don't know how to do the query. The database has two tables that I want to pull information from. Both tables have one thing in common which is 'id_member'. Themes table has a bunch of junk in it - so it has 4 coulms - 'id_member', 'id_theme', 'varible', and 'value'. There are two items in 'varible' that I want to filter (show them and not the rest) "cust_armaus" and "cust_armamo" then value will show the value of course. So in the table Themes it will have id_member listed more than once to show the different varibles. This is what I got that isn't working for me:
<?php
header('Content-Type: text/xml');
$username="database_username";
$password="database_password";
$database="database_name";
mysql_connect('localhost',$username,$password);
#mysql_select_db($database) or die( "Unable to select database");
echo "<?xml version=\"1.0\"?>\n".
"<!DOCTYPE squad SYSTEM \"squad.dtd\">\n".
"<?xml-stylesheet href=\"squad.xsl?\" type=\"text/xsl\"?>\n";
?>
<squad nick="Team Tag">
<name>Team Name</name>
<email>contact#team.com</email>
<web>http://www.team.com</web>
<picture>teamlogo.paa</picture>
<title>This is the Team motto</title>
<?php
// smf_themes -> id_member =
// smf_themes -> variable for cust_armaus & cust_usermo
// smf_themes -> value <- get for cust_armaus & cust_usermo
// smf_members -> real_name = profile_name & name
// smf_members -> email_address = email - NO
$memberSQL = mysql_query("SELECT id_member AS id, real_name FROM smf_members");
$member = mysql_fetch_array($memberSQL);
$armausSQL = mysql_query("SELECT id_member, variable, value AS arma_id FROM smf_themes WHERE id_member='$member[id]' AND variable='cust_armaus'");
$armaid = mysql_fetch_array($armausSQL);
$armamoSQL = mysql_query("SELECT id_member, variable, value AS motto FROM smf_themes WHERE id_member='$member[id]' AND variable='cust_usermo'");
$armamo = mysql_fetch_array($armamoSQL);
$num=mysql_numrows($member, $armaid, $armamo);
mysql_close();
$i=0;
while ($i < $num) {
$profile_id = mysql_result($armaid,$i,"value");
$profile_name = mysql_result($member,$i,"real_name");
$profile_remark = mysql_result($armamo,$i,"value");
$profile_username = mysql_result($member,$i,"real_name");
//$profile_email = mysql_result($result,$i,"email");
//$profile_icq = mysql_result($result,$i,"icq");
echo "<member id=\"$profile_id\" nick=\"$profile_name\">" .
"<name>$profile_name</name>".
"<email>$profile_email</email>".
"<icq>$profile_icq</icq>".
"<remark>$profile_remark</remark>".
"</member>\n";
$i++;
}
?>
</squad>
The mysql interface is deprecated. New development should use either mysqli or PDO.
Assuming you only one one value of the cust_armaus and cust_usermo rows for each smf_members, you could use correlated subqueries in the SELECT list, and return just a single query that returns a single row for each row in smf_members. Something like this:
SELECT m.id_member AS id
, m.real_name
, (SELECT a.value
FROM smf_themes a
WHERE a.id_member = m.id_member
AND a.variable = 'cust_armaus'
ORDER BY a.value LIMIT 1
) AS cust_armaus
, (SELECT u.value
FROM smf_themes u
WHERE u.id_member = m.id_member
AND u.variable = 'cust_usermo'
ORDER BY u.value LIMIT 1
) AS cust_usermo
FROM smf_members m
ORDER BY m.id_member
If the (id_member,variable) tuple is guaranteed to be unique in smf_themes, you could use a simpler outer join:
SELECT m.id_member AS id
, m.real_name
, a.value AS cust_armaus
, u.value AS cust_usermo
FROM smf_members m
LEFT
JOIN smf_themes a
ON a.member_id = m.member_id AND a.variable = 'cust_aramus'
LEFT
JOIN smf_themes u
ON u.member_id = m.member_id AND u.variable = 'cust_usermo'
ORDER BY m.id_member
With either of those queries, you could use code something like this:
$sql = "SELECT ...";
$rs = $mysqli->query($sql)
if (!$rs) {
// handle error
echo 'query failed: (' . $mysqli->errno . ') ' . $mysqli->error;
die;
}
// loop through rows returned
while ( $row = $rs->fetch_assoc() ) {
echo '<member id="' . htmlspecialchars($row['id']) . '"'
. ' nick="' . htmlspecialchars($row['real_name']) . '">'
. '<cust_aramus>' . htmlspecialchars($row['cust_aramus']) . '</cust_aramus>'
. '<cust_usermo>' . htmlspecialchars($row['cust_usermo']) . '</cust_usermo>' ;
}
I have three tables:
I want to display 'Event Details' which shows attending employee details (listo f employee ids from the 'attending_employees table > corresponding employee details form 'employee' table), what team they belong to (from the club_teams table) and the event details from the 'club_events' table).
Currently I am using multiple mysqli queries to display this information however cannot get my head around pulling the data from the database in one query (ie: LEFT JOIN). Your assistance would be greatly appreciated!
Below are the queries i am currently using:
$query = msqli_query($con, "SELECT * FROM attending_employees")or die(mysqli_error($con));
if(mysqli_num_rows($query) > 0){
while($attending = mysqli_fetch_array($query)){
foreach($attending['club_event']){
$eventid = $attending['club_event'];
$query = msqli_query($con, "SELECT * FROM club_events WHERE club_event_id = '$eventid'")or die(mysqli_error($con));
while($event_details = mysqli_fetch_array($query)){
// Echo event details
}
}foreach($attending['employee']){
$empid = $attending['employee'];
$query = msqli_query($con, "SELECT * FROM employees WHERE employee_id = '$empid'")or die(mysqli_error($con));
while($event_employees = mysqli_fetch_array($query)){
// Echo employee details
}
}foreach($attending['team']){
$teamid = $attending['team'];
$query = msqli_query($con, "SELECT * FROM club_teams WHERE clb_team_id = '$teamid'")or die(mysqli_error($con));
while($event_team = mysqli_fetch_array($query)){
// Echo team details
}
}
}
}
This method is highly inefficient and wasteful since its retrieving duplicate data (ie: all repeated 'club_event_id's in the 'attending_employees' table.)
Try this:
$query = msqli_query(
$con,
"SELECT"
. " attending_employees.*"
. ", club_events.*"
. ", employees.*"
. ", club_teams.*"
. " FROM"
. " attending_employees"
. " LEFT JOIN club_events ON club_events.club_event_id = attending_employees.club_event"
. " LEFT JOIN employees ON employees.employee_id = attending_employees.employee"
. " LEFT JOIN club_teams ON club_teams.clb_team_id = attending_employees.team"
) or die(mysqli_error($con));
I'm attempting to select a query to use based on the number of rows returned by a test result.
$id = mysql_real_escape_string(htmlspecialchars($_POST['id']));
$result = "SELECT FROM Notifications WHERE UserID=$id";
$r = e_mysql_query($result);
$row = mysql_fetch_array($r);
$num_results = mysql_num_rows($result);
$result = '';
if ($num_results != 0) {
$result =
"SELECT U.UserID,U.FirstName,U.LastName, " .
" DATE_FORMAT(U.BirthDate,'%m-%d-%Y') AS BirthDate, " .
" N.Email, N.Phone,N.ProviderName, N.SubNotifications " .
" FROM Users U, Notifications N " .
" WHERE U.LocationID=0 " .
" AND N.UserID='$id'";
} else {
$result =
"SELECT UserID, FirstName, LastName," .
" DATE_FORMAT(BirthDate, '%m-%d-%Y') AS BirthDate " .
" FROM Users " .
" WHERE LocationID = 0 " .
" AND UserID ='$id'";
}
echo $result;
e_mysql_result($result); //Bastardized/homegrown PDO
if ($row = mysql_fetch_assoc($result)) {
$retValue['userInfo'] = $row;
...
I'm checking the Notifications table to see if the UserID exists there, if it doesn't it loads what does exist from the Users table, if it does, then it loads everything from the Notifications table.
I'm echoing out the $result and the proper statement is loaded, but it doesn't execute. When I run the concatenated query I get from the PHP preview, it returns just fine.
Before I had to if/else this, I was running the first query, loading everything from the Notifications table, and it was loading just fine. What am I missing?
You can do the whole thing with one query with a LEFT JOIN.
$query= "SELECT U.UserID, U.FirstName,U.LastName, " .
" DATE_FORMAT(U.BirthDate,'%m-%d-%Y') AS BirthDate, " .
" N.Email, N.Phone,N.ProviderName, N.SubNotifications " .
" FROM Users U " .
" LEFT JOIN Notifications N " .
" ON U.UserID = N.UserID " .
" WHERE U.UserID = '$id'";
You are missing execute a query with mysql_query() on all $result
Also change (query variable should be quoted) so change your all variables $id quoted
$result = "SELECT FROM Notifications WHERE UserID=$id";
to
$result = "SELECT FROM Notifications WHERE UserID='$id'";
$r = mysql_query($result);
Note :- mysql_* has been deprecated use mysqli_* or PDO
I have a php code that use a mySQL query in it.
tables users and conversation and main_profile have true values to select after this query but query return nothing.
$sqlQuer =
"SELECT `conversation`.from,`conversation`.text, `main_profile`.nik_name, `users`.id
FROM `conversation`
INNER JOIN `users` ON(`users`.username = `conversation`.to )
INNER JOIN `main_profile` ON(`users`.id = `main_profile`.user_id)
WHERE `conversation`.to = '".$to."'
AND `conversation`.read = '0'";
$result = mysql_query( $sqlQuer) or die (mysql_error());
while($row = mysql_fetch_array($result))
{
echo $row[0] . "#TEXT#" . $row[1]. "#TEXT#" . $row[2] . "#CON#";
$ids[] = $row['id'];
}
any Idea ?
Query was solved with this change that First INNER JOIN changed to LEFT JOIN and second changed to RIGHT JOIN.