Store data after mysql query - php

Question

This is my problem. I have a table in my database in which there are two columns, ID and ANSWER. In this database there are more rows with same ID, so I want to save all the results with this id in an array.
the sql code is:
$sql6 = "SELECT * FROM Answer WHERE userId = :userId and qId = 'q6'";
$stmt6 = $conn->prepare($sql6);
$stmt6->execute(array(':userId' => $_SESSION['SESS_MEMBER_ID']));
now to fatch the results I don't know if I have to use
$result6 = $stmt6->fetch(PDO::FETCH_OBJ);
or
$result6 = $stmt6->fetchAll();
EX.
ID ANSWER
q6 abba
q6 bbaa
i would save in an array like this for example:
$array=("abba","bbaa");
then i would pass this array to a script in javascript.

Answer 1

You can either call $stmt->fetch in a loop, pushing each row onto the resulting array, or you can call fetchAll once -- it returns an array of all the rows. So the following are equivalent:
$array = array();
while ($row = $stmt6->fetch(PDO::FETCH_OBJ)) {
$array[] = $row;
}
and:
$array = $stmt6->fetchAll(PDO::FETCH_OBJ);
If you want an array with just the value of a single column, rather than objects representing the whole row, the loop will be easier:
while ($row = $stmt6->fetch(PDO::FETCH_OBJ)) {
$array[] = $row->q6;
}

Answer 2

#Barmar, your solution partially works. i've written this:
$sql6 = "SELECT * FROM Answer WHERE userId = :userId and qId = 'q6'";
$stmt6 = $conn->prepare($sql6);
$stmt6->execute(array(':userId' => $_SESSION['SESS_MEMBER_ID']));
$count6 = $stmt6->rowCount(array(':userId' => $_SESSION['SESS_MEMBER_ID']));
$answer6 = array();
while ($result6 = $stmt6->fetch(PDO::FETCH_OBJ)) {
$answer6[] = $result6->answer;
}
then i want to pass this array to a script, so:
<script>
var num = var ans6 = '<?php echo $count6; ?>';
var ans6 = '<?php echo json_encode($answer6); ?>';
for(var i=0; i<num;i++){
alert(ans6);
}
the result is a popup in which is written "["abba","bbaa"]".
but if i write
for(var i=0; i<num;i++){
alert(ans6[i]);
}
the popup shows first"[" and then " " "