Related
Here's what I'm trying to do. Let's say I have this table t:
key_id | id | record_date | other_cols
1 | 18 | 2011-04-03 | x
2 | 18 | 2012-05-19 | y
3 | 18 | 2012-08-09 | z
4 | 19 | 2009-06-01 | a
5 | 19 | 2011-04-03 | b
6 | 19 | 2011-10-25 | c
7 | 19 | 2012-08-09 | d
For each id, I want to select the row containing the minimum record_date. So I'd get:
key_id | id | record_date | other_cols
1 | 18 | 2011-04-03 | x
4 | 19 | 2009-06-01 | a
The only solutions I've seen to this problem assume that all record_date entries are distinct, but that is not this case in my data. Using a subquery and an inner join with two conditions would give me duplicate rows for some ids, which I don't want:
key_id | id | record_date | other_cols
1 | 18 | 2011-04-03 | x
5 | 19 | 2011-04-03 | b
4 | 19 | 2009-06-01 | a
How about something like:
SELECT mt.*
FROM MyTable mt INNER JOIN
(
SELECT id, MIN(record_date) AS MinDate
FROM MyTable
GROUP BY id
) t ON mt.id = t.id AND mt.record_date = t.MinDate
This gets the minimum date per ID, and then gets the values based on those values. The only time you would have duplicates is if there are duplicate minimum record_dates for the same ID.
I could get to your expected result just by doing this in mysql:
SELECT id, min(record_date), other_cols
FROM mytable
GROUP BY id
Does this work for you?
To get the cheapest product in each category, you use the MIN() function in a correlated subquery as follows:
SELECT categoryid,
productid,
productName,
unitprice
FROM products a WHERE unitprice = (
SELECT MIN(unitprice)
FROM products b
WHERE b.categoryid = a.categoryid)
The outer query scans all rows in the products table and returns the products that have unit prices match with the lowest price in each category returned by the correlated subquery.
I would like to add to some of the other answers here, if you don't need the first item but say the second number for example you can use rownumber in a subquery and base your result set off of that.
SELECT * FROM
(
SELECT
ROW_NUM() OVER (PARTITION BY Id ORDER BY record_date, other_cols) as rownum,
*
FROM products P
) INNER
WHERE rownum = 2
This also allows you to order off multiple columns in the subquery which may help if two record_dates have identical values. You can also partition off of multiple columns if needed by delimiting them with a comma
This does it simply:
select t2.id,t2.record_date,t2.other_cols
from (select ROW_NUMBER() over(partition by id order by record_date)as rownum,id,record_date,other_cols from MyTable)t2
where t2.rownum = 1
If record_date has no duplicates within a group:
think of it as of filtering. Simpliy get (WHERE) one (MIN(record_date)) row from the current group:
SELECT * FROM t t1 WHERE record_date = (
select MIN(record_date)
from t t2 where t2.group_id = t1.group_id)
If there could be 2+ min record_date within a group:
filter out non-min rows (see above)
then (AND) pick only one from the 2+ min record_date rows, within the given group_id. E.g. pick the one with the min unique key:
AND key_id = (select MIN(key_id)
from t t3 where t3.record_date = t1.record_date
and t3.group_id = t1.group_id)
so
key_id | group_id | record_date | other_cols
1 | 18 | 2011-04-03 | x
4 | 19 | 2009-06-01 | a
8 | 19 | 2009-06-01 | e
will select key_ids: #1 and #4
SELECT p.* FROM tbl p
INNER JOIN(
SELECT t.id, MIN(record_date) AS MinDate
FROM tbl t
GROUP BY t.id
) t ON p.id = t.id AND p.record_date = t.MinDate
GROUP BY p.id
This code eliminates duplicate record_date in case there are same ids with same record_date.
If you want duplicates, remove the last line GROUP BY p.id.
This a old question, but this can useful for someone
In my case i can't using a sub query because i have a big query and i need using min() on my result, if i use sub query the db need reexecute my big query. i'm using Mysql
select t.*
from (select m.*, #g := 0
from MyTable m --here i have a big query
order by id, record_date) t
where (1 = case when #g = 0 or #g <> id then 1 else 0 end )
and (#g := id) IS NOT NULL
Basically I ordered the result and then put a variable in order to get only the first record in each group.
The below query takes the first date for each work order (in a table of showing all status changes):
SELECT
WORKORDERNUM,
MIN(DATE)
FROM
WORKORDERS
WHERE
DATE >= to_date('2015-01-01','YYYY-MM-DD')
GROUP BY
WORKORDERNUM
select
department,
min_salary,
(select s1.last_name from staff s1 where s1.salary=s3.min_salary ) lastname
from
(select department, min (salary) min_salary from staff s2 group by s2.department) s3
I have a MySQL table which is as follows:
id
name
parent_id
19
category1
0
20
category2
19
21
category3
20
22
category4
21
...
...
...
Now, I want to have a single MySQL query to which I simply supply the id [for instance say id=19] then I should get all its child ids [i.e. result should have ids '20,21,22']....
The hierarchy of the children is not known; it can vary....
I know how to do it using a for loop... but how to achieve the same using a single MySQL query?
For MySQL 8+: use the recursive with syntax.
For MySQL 5.x: use inline variables, path IDs, or self-joins.
MySQL 8+
with recursive cte (id, name, parent_id) as (
select id,
name,
parent_id
from products
where parent_id = 19
union all
select p.id,
p.name,
p.parent_id
from products p
inner join cte
on p.parent_id = cte.id
)
select * from cte;
The value specified in parent_id = 19 should be set to the id of the parent you want to select all the descendants of.
MySQL 5.x
For MySQL versions that do not support Common Table Expressions (up to version 5.7), you would achieve this with the following query:
select id,
name,
parent_id
from (select * from products
order by parent_id, id) products_sorted,
(select #pv := '19') initialisation
where find_in_set(parent_id, #pv)
and length(#pv := concat(#pv, ',', id))
Here is a fiddle.
Here, the value specified in #pv := '19' should be set to the id of the parent you want to select all the descendants of.
This will work also if a parent has multiple children. However, it is required that each record fulfills the condition parent_id < id, otherwise the results will not be complete.
Variable assignments inside a query
This query uses specific MySQL syntax: variables are assigned and modified during its execution. Some assumptions are made about the order of execution:
The from clause is evaluated first. So that is where #pv gets initialised.
The where clause is evaluated for each record in the order of retrieval from the from aliases. So this is where a condition is put to only include records for which the parent was already identified as being in the descendant tree (all descendants of the primary parent are progressively added to #pv).
The conditions in this where clause are evaluated in order, and the evaluation is interrupted once the total outcome is certain. Therefore the second condition must be in second place, as it adds the id to the parent list, and this should only happen if the id passes the first condition. The length function is only called to make sure this condition is always true, even if the pv string would for some reason yield a falsy value.
All in all, one may find these assumptions too risky to rely on. The documentation warns:
you might get the results you expect, but this is not guaranteed [...] the order of evaluation for expressions involving user variables is undefined.
So even though it works consistently with the above query, the evaluation order may still change, for instance when you add conditions or use this query as a view or sub-query in a larger query. It is a "feature" that will be removed in a future MySQL release:
Previous releases of MySQL made it possible to assign a value to a user variable in statements other than SET. This functionality is supported in MySQL 8.0 for backward compatibility but is subject to removal in a future release of MySQL.
As stated above, from MySQL 8.0 onward you should use the recursive with syntax.
Efficiency
For very large data sets this solution might get slow, as the find_in_set operation is not the most ideal way to find a number in a list, certainly not in a list that reaches a size in the same order of magnitude as the number of records returned.
Alternative 1: with recursive, connect by
More and more databases implement the SQL:1999 ISO standard WITH [RECURSIVE] syntax for recursive queries (e.g. Postgres 8.4+, SQL Server 2005+, DB2, Oracle 11gR2+, SQLite 3.8.4+, Firebird 2.1+, H2, HyperSQL 2.1.0+, Teradata, MariaDB 10.2.2+). And as of version 8.0, also MySQL supports it. See the top of this answer for the syntax to use.
Some databases have an alternative, non-standard syntax for hierarchical look-ups, such as the CONNECT BY clause available on Oracle, DB2, Informix, CUBRID and other databases.
MySQL version 5.7 does not offer such a feature. When your database engine provides this syntax or you can migrate to one that does, then that is certainly the best option to go for. If not, then also consider the following alternatives.
Alternative 2: Path-style Identifiers
Things become a lot easier if you would assign id values that contain the hierarchical information: a path. For example, in your case this could look like this:
ID
NAME
19
category1
19/1
category2
19/1/1
category3
19/1/1/1
category4
Then your select would look like this:
select id,
name
from products
where id like '19/%'
Alternative 3: Repeated Self-joins
If you know an upper limit for how deep your hierarchy tree can become, you can use a standard sql query like this:
select p6.parent_id as parent6_id,
p5.parent_id as parent5_id,
p4.parent_id as parent4_id,
p3.parent_id as parent3_id,
p2.parent_id as parent2_id,
p1.parent_id as parent_id,
p1.id as product_id,
p1.name
from products p1
left join products p2 on p2.id = p1.parent_id
left join products p3 on p3.id = p2.parent_id
left join products p4 on p4.id = p3.parent_id
left join products p5 on p5.id = p4.parent_id
left join products p6 on p6.id = p5.parent_id
where 19 in (p1.parent_id,
p2.parent_id,
p3.parent_id,
p4.parent_id,
p5.parent_id,
p6.parent_id)
order by 1, 2, 3, 4, 5, 6, 7;
See this fiddle
The where condition specifies which parent you want to retrieve the descendants of. You can extend this query with more levels as needed.
From the blog Managing Hierarchical Data in MySQL
Table structure
+-------------+----------------------+--------+
| category_id | name | parent |
+-------------+----------------------+--------+
| 1 | ELECTRONICS | NULL |
| 2 | TELEVISIONS | 1 |
| 3 | TUBE | 2 |
| 4 | LCD | 2 |
| 5 | PLASMA | 2 |
| 6 | PORTABLE ELECTRONICS | 1 |
| 7 | MP3 PLAYERS | 6 |
| 8 | FLASH | 7 |
| 9 | CD PLAYERS | 6 |
| 10 | 2 WAY RADIOS | 6 |
+-------------+----------------------+--------+
Query:
SELECT t1.name AS lev1, t2.name as lev2, t3.name as lev3, t4.name as lev4
FROM category AS t1
LEFT JOIN category AS t2 ON t2.parent = t1.category_id
LEFT JOIN category AS t3 ON t3.parent = t2.category_id
LEFT JOIN category AS t4 ON t4.parent = t3.category_id
WHERE t1.name = 'ELECTRONICS';
Output
+-------------+----------------------+--------------+-------+
| lev1 | lev2 | lev3 | lev4 |
+-------------+----------------------+--------------+-------+
| ELECTRONICS | TELEVISIONS | TUBE | NULL |
| ELECTRONICS | TELEVISIONS | LCD | NULL |
| ELECTRONICS | TELEVISIONS | PLASMA | NULL |
| ELECTRONICS | PORTABLE ELECTRONICS | MP3 PLAYERS | FLASH |
| ELECTRONICS | PORTABLE ELECTRONICS | CD PLAYERS | NULL |
| ELECTRONICS | PORTABLE ELECTRONICS | 2 WAY RADIOS | NULL |
+-------------+----------------------+--------------+-------+
Most users at one time or another have dealt with hierarchical data in a SQL database and no doubt learned that the management of hierarchical data is not what a relational database is intended for. The tables of a relational database are not hierarchical (like XML), but are simply a flat list. Hierarchical data has a parent-child relationship that is not naturally represented in a relational database table.
Read more
Refer the blog for more details.
EDIT:
select #pv:=category_id as category_id, name, parent from category
join
(select #pv:=19)tmp
where parent=#pv
Output:
category_id name parent
19 category1 0
20 category2 19
21 category3 20
22 category4 21
Reference: How to do the Recursive SELECT query in Mysql?
Try these:
Table definition:
DROP TABLE IF EXISTS category;
CREATE TABLE category (
id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(20),
parent_id INT,
CONSTRAINT fk_category_parent FOREIGN KEY (parent_id)
REFERENCES category (id)
) engine=innodb;
Experimental rows:
INSERT INTO category VALUES
(19, 'category1', NULL),
(20, 'category2', 19),
(21, 'category3', 20),
(22, 'category4', 21),
(23, 'categoryA', 19),
(24, 'categoryB', 23),
(25, 'categoryC', 23),
(26, 'categoryD', 24);
Recursive Stored procedure:
DROP PROCEDURE IF EXISTS getpath;
DELIMITER $$
CREATE PROCEDURE getpath(IN cat_id INT, OUT path TEXT)
BEGIN
DECLARE catname VARCHAR(20);
DECLARE temppath TEXT;
DECLARE tempparent INT;
SET max_sp_recursion_depth = 255;
SELECT name, parent_id FROM category WHERE id=cat_id INTO catname, tempparent;
IF tempparent IS NULL
THEN
SET path = catname;
ELSE
CALL getpath(tempparent, temppath);
SET path = CONCAT(temppath, '/', catname);
END IF;
END$$
DELIMITER ;
Wrapper function for the stored procedure:
DROP FUNCTION IF EXISTS getpath;
DELIMITER $$
CREATE FUNCTION getpath(cat_id INT) RETURNS TEXT DETERMINISTIC
BEGIN
DECLARE res TEXT;
CALL getpath(cat_id, res);
RETURN res;
END$$
DELIMITER ;
Select example:
SELECT id, name, getpath(id) AS path FROM category;
Output:
+----+-----------+-----------------------------------------+
| id | name | path |
+----+-----------+-----------------------------------------+
| 19 | category1 | category1 |
| 20 | category2 | category1/category2 |
| 21 | category3 | category1/category2/category3 |
| 22 | category4 | category1/category2/category3/category4 |
| 23 | categoryA | category1/categoryA |
| 24 | categoryB | category1/categoryA/categoryB |
| 25 | categoryC | category1/categoryA/categoryC |
| 26 | categoryD | category1/categoryA/categoryB/categoryD |
+----+-----------+-----------------------------------------+
Filtering rows with certain path:
SELECT id, name, getpath(id) AS path FROM category HAVING path LIKE 'category1/category2%';
Output:
+----+-----------+-----------------------------------------+
| id | name | path |
+----+-----------+-----------------------------------------+
| 20 | category2 | category1/category2 |
| 21 | category3 | category1/category2/category3 |
| 22 | category4 | category1/category2/category3/category4 |
+----+-----------+-----------------------------------------+
Did the same thing for another quetion here
Mysql select recursive get all child with multiple level
The query will be :
SELECT GROUP_CONCAT(lv SEPARATOR ',') FROM (
SELECT #pv:=(
SELECT GROUP_CONCAT(id SEPARATOR ',')
FROM table WHERE parent_id IN (#pv)
) AS lv FROM table
JOIN
(SELECT #pv:=1)tmp
WHERE parent_id IN (#pv)
) a;
If you need quick read speed, the best option is to use a closure table. A closure table contains a row for each ancestor/descendant pair. So in your example, the closure table would look like
ancestor | descendant | depth
0 | 0 | 0
0 | 19 | 1
0 | 20 | 2
0 | 21 | 3
0 | 22 | 4
19 | 19 | 0
19 | 20 | 1
19 | 21 | 3
19 | 22 | 4
20 | 20 | 0
20 | 21 | 1
20 | 22 | 2
21 | 21 | 0
21 | 22 | 1
22 | 22 | 0
Once you have this table, hierarchical queries become very easy and fast. To get all the descendants of category 20:
SELECT cat.* FROM categories_closure AS cl
INNER JOIN categories AS cat ON cat.id = cl.descendant
WHERE cl.ancestor = 20 AND cl.depth > 0
Of course, there is a big downside whenever you use denormalized data like this. You need to maintain the closure table alongside your categories table. The best way is probably to use triggers, but it is somewhat complex to correctly track inserts/updates/deletes for closure tables. As with anything, you need to look at your requirements and decide what approach is best for you.
Edit: See the question What are the options for storing hierarchical data in a relational database? for more options. There are different optimal solutions for different situations.
The best approach I've come up with is
Use lineage to store\sort\trace trees. That's more than enough, and works thousands times faster for reading than any other approach.
It also allows to stay on that pattern even if DB will change(as ANY db will allow that pattern to be used)
Use function that determines lineage for specific ID.
Use it as you wish (in selects, or on CUD operations, or even by jobs).
Lineage approach descr. can be found wherever, for example
Here or here.
As of function - that is what enspired me.
In the end - got more-or-less simple, relatively fast, and SIMPLE solution.
Function's body
-- --------------------------------------------------------------------------------
-- Routine DDL
-- Note: comments before and after the routine body will not be stored by the server
-- --------------------------------------------------------------------------------
DELIMITER $$
CREATE DEFINER=`root`#`localhost` FUNCTION `get_lineage`(the_id INT) RETURNS text CHARSET utf8
READS SQL DATA
BEGIN
DECLARE v_rec INT DEFAULT 0;
DECLARE done INT DEFAULT FALSE;
DECLARE v_res text DEFAULT '';
DECLARE v_papa int;
DECLARE v_papa_papa int DEFAULT -1;
DECLARE csr CURSOR FOR
select _id,parent_id -- #n:=#n+1 as rownum,T1.*
from
(SELECT #r AS _id,
(SELECT #r := table_parent_id FROM table WHERE table_id = _id) AS parent_id,
#l := #l + 1 AS lvl
FROM
(SELECT #r := the_id, #l := 0,#n:=0) vars,
table m
WHERE #r <> 0
) T1
where T1.parent_id is not null
ORDER BY T1.lvl DESC;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
open csr;
read_loop: LOOP
fetch csr into v_papa,v_papa_papa;
SET v_rec = v_rec+1;
IF done THEN
LEAVE read_loop;
END IF;
-- add first
IF v_rec = 1 THEN
SET v_res = v_papa_papa;
END IF;
SET v_res = CONCAT(v_res,'-',v_papa);
END LOOP;
close csr;
return v_res;
END
And then you just
select get_lineage(the_id)
Hope it helps somebody :)
Based on the #trincot answer, very good explained, I use WITH RECURSIVE () statement to create a breadcrumb using id of the current page and go backwards in the hierarchy to find the every parent in my route table.
So, the #trincot solution is adapted here in the opposite direction to find parents instead of descendants.
I also added depth value which is usefull to invert result order (otherwise the breadcrumb would be upside down).
WITH RECURSIVE cte (
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent_id`,
`depth`
) AS (
SELECT
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent_id`,
1 AS `depth`
FROM `route`
WHERE `id` = :id
UNION ALL
SELECT
P.`id`,
P.`title`,
P.`url`,
P.`icon`,
P.`class`,
P.`parent_id`,
`depth` + 1
FROM `route` P
INNER JOIN cte
ON P.`id` = cte.`parent_id`
)
SELECT * FROM cte ORDER BY `depth` DESC;
Before upgrade to mySQL 8+, I was using vars but it's deprecated and no more working on my 8.0.22 version !
EDIT 2021-02-19 :
Example for hierarchical menu
After #david comment I decided to try to make a full hierarchical menu with all nodes and sorted as I want (with sorting column which sort items in each depth). Very usefull for my user/authorization matrix page.
This really simplifies my old version with one query on each depth (PHP loops).
This example intergrates an INNER JOIN with url table to filter route by website (multi-websites CMS system).
You can see the essential path column that contains CONCAT() function to sort the menu in the right way.
SELECT R.* FROM (
WITH RECURSIVE cte (
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent`,
`depth`,
`sorting`,
`path`
) AS (
SELECT
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent`,
1 AS `depth`,
`sorting`,
CONCAT(`sorting`, ' ' , `title`) AS `path`
FROM `route`
WHERE `parent` = 0
UNION ALL SELECT
D.`id`,
D.`title`,
D.`url`,
D.`icon`,
D.`class`,
D.`parent`,
`depth` + 1,
D.`sorting`,
CONCAT(cte.`path`, ' > ', D.`sorting`, ' ' , D.`title`)
FROM `route` D
INNER JOIN cte
ON cte.`id` = D.`parent`
)
SELECT * FROM cte
) R
INNER JOIN `url` U
ON R.`id` = U.`route_id`
AND U.`site_id` = 1
ORDER BY `path` ASC
Something not mentioned here, although a bit similar to the second alternative of the accepted answer but different and low cost for big hierarchy query and easy (insert update delete) items, would be adding a persistent path column for each item.
some like:
id | name | path
19 | category1 | /19
20 | category2 | /19/20
21 | category3 | /19/20/21
22 | category4 | /19/20/21/22
Example:
-- get children of category3:
SELECT * FROM my_table WHERE path LIKE '/19/20/21%'
-- Reparent an item:
UPDATE my_table SET path = REPLACE(path, '/19/20', '/15/16') WHERE path LIKE '/19/20/%'
Optimise the path length and ORDER BY path using base36 encoding instead real numeric path id
// base10 => base36
'1' => '1',
'10' => 'A',
'100' => '2S',
'1000' => 'RS',
'10000' => '7PS',
'100000' => '255S',
'1000000' => 'LFLS',
'1000000000' => 'GJDGXS',
'1000000000000' => 'CRE66I9S'
https://en.wikipedia.org/wiki/Base36
Suppressing also the slash '/' separator by using fixed length and padding to the encoded id
Detailed optimization explanation here:
https://bojanz.wordpress.com/2014/04/25/storing-hierarchical-data-materialized-path/
TODO
building a function or procedure to split path for retreive ancestors of one item
Simple query to list child's of first recursion:
select #pv:=id as id, name, parent_id
from products
join (select #pv:=19)tmp
where parent_id=#pv
Result:
id name parent_id
20 category2 19
21 category3 20
22 category4 21
26 category24 22
... with left join:
select
#pv:=p1.id as id
, p2.name as parent_name
, p1.name name
, p1.parent_id
from products p1
join (select #pv:=19)tmp
left join products p2 on p2.id=p1.parent_id -- optional join to get parent name
where p1.parent_id=#pv
The solution of #tincot to list all child's:
select id,
name,
parent_id
from (select * from products
order by parent_id, id) products_sorted,
(select #pv := '19') initialisation
where find_in_set(parent_id, #pv) > 0
and #pv := concat(#pv, ',', id)
Test it online with Sql Fiddle and see all results.
http://sqlfiddle.com/#!9/a318e3/4/0
You can do it like this in other databases quite easily with a recursive query (YMMV on performance).
The other way to do it is to store two extra bits of data, a left and right value. The left and right value are derived from a pre-order traversal of the tree structure you're representing.
This is know as Modified Preorder Tree Traversal and lets you run a simple query to get all parent values at once. It also goes by the name "nested set".
Just use BlueM/tree php class for make tree of a self-relation table in mysql.
Tree and Tree\Node are PHP classes for handling data that is structured hierarchically using parent ID references. A typical example is a table in a relational database where each record’s “parent” field references the primary key of another record. Of course, Tree cannot only use data originating from a database, but anything: you supply the data, and Tree uses it, regardless of where the data came from and how it was processed. read more
Here is an example of using BlueM/tree:
<?php
require '/path/to/vendor/autoload.php'; $db = new PDO(...); // Set up your database connection
$stm = $db->query('SELECT id, parent, title FROM tablename ORDER BY title');
$records = $stm->fetchAll(PDO::FETCH_ASSOC);
$tree = new BlueM\Tree($records);
...
It's a category table.
SELECT id,
NAME,
parent_category
FROM (SELECT * FROM category
ORDER BY parent_category, id) products_sorted,
(SELECT #pv := '2') initialisation
WHERE FIND_IN_SET(parent_category, #pv) > 0
AND #pv := CONCAT(#pv, ',', id)
Output::
Its a little tricky one, check this whether it is working for you
select a.id,if(a.parent = 0,#varw:=concat(a.id,','),#varw:=concat(a.id,',',#varw)) as list from (select * from recursivejoin order by if(parent=0,id,parent) asc) a left join recursivejoin b on (a.id = b.parent),(select #varw:='') as c having list like '%19,%';
SQL fiddle link http://www.sqlfiddle.com/#!2/e3cdf/2
Replace with your field and table name appropriately.
This works for me, hope this will work for you too. It will give you a Record set Root to Child for any Specific Menu. Change the Field name as per your requirements.
SET #id:= '22';
SELECT Menu_Name, (#id:=Sub_Menu_ID ) as Sub_Menu_ID, Menu_ID
FROM
( SELECT Menu_ID, Menu_Name, Sub_Menu_ID
FROM menu
ORDER BY Sub_Menu_ID DESC
) AS aux_table
WHERE Menu_ID = #id
ORDER BY Sub_Menu_ID;
I found it more easily to :
1) create a function that will check if a item is anywhere in the parent hierarchy of another one. Something like this (I will not write the function, make it with WHILE DO) :
is_related(id, parent_id);
in your example
is_related(21, 19) == 1;
is_related(20, 19) == 1;
is_related(21, 18) == 0;
2) use a sub-select , something like this:
select ...
from table t
join table pt on pt.id in (select i.id from table i where is_related(t.id,i.id));
I have made a query for you. This will give you Recursive Category with a Single Query:
SELECT id,NAME,'' AS subName,'' AS subsubName,'' AS subsubsubName FROM Table1 WHERE prent is NULL
UNION
SELECT b.id,a.name,b.name AS subName,'' AS subsubName,'' AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id WHERE a.prent is NULL AND b.name IS NOT NULL
UNION
SELECT c.id,a.name,b.name AS subName,c.name AS subsubName,'' AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id LEFT JOIN Table1 AS c ON c.prent=b.id WHERE a.prent is NULL AND c.name IS NOT NULL
UNION
SELECT d.id,a.name,b.name AS subName,c.name AS subsubName,d.name AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id LEFT JOIN Table1 AS c ON c.prent=b.id LEFT JOIN Table1 AS d ON d.prent=c.id WHERE a.prent is NULL AND d.name IS NOT NULL
ORDER BY NAME,subName,subsubName,subsubsubName
Here is a fiddle.
The following is the simplest possible example, though any solution should be able to scale to however many n top results are needed:
Given a table like that below, with person, group, and age columns, how would you get the 2 oldest people in each group? (Ties within groups should not yield more results, but give the first 2 in alphabetical order)
+--------+-------+-----+
| Person | Group | Age |
+--------+-------+-----+
| Bob | 1 | 32 |
| Jill | 1 | 34 |
| Shawn | 1 | 42 |
| Jake | 2 | 29 |
| Paul | 2 | 36 |
| Laura | 2 | 39 |
+--------+-------+-----+
Desired result set:
+--------+-------+-----+
| Shawn | 1 | 42 |
| Jill | 1 | 34 |
| Laura | 2 | 39 |
| Paul | 2 | 36 |
+--------+-------+-----+
NOTE: This question builds on a previous one- Get records with max value for each group of grouped SQL results - for getting a single top row from each group, and which received a great MySQL-specific answer from #Bohemian:
select *
from (select * from mytable order by `Group`, Age desc, Person) x
group by `Group`
Would love to be able to build off this, though I don't see how.
Here is one way to do this, using UNION ALL (See SQL Fiddle with Demo). This works with two groups, if you have more than two groups, then you would need to specify the group number and add queries for each group:
(
select *
from mytable
where `group` = 1
order by age desc
LIMIT 2
)
UNION ALL
(
select *
from mytable
where `group` = 2
order by age desc
LIMIT 2
)
There are a variety of ways to do this, see this article to determine the best route for your situation:
http://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/
Edit:
This might work for you too, it generates a row number for each record. Using an example from the link above this will return only those records with a row number of less than or equal to 2:
select person, `group`, age
from
(
select person, `group`, age,
(#num:=if(#group = `group`, #num +1, if(#group := `group`, 1, 1))) row_number
from test t
CROSS JOIN (select #num:=0, #group:=null) c
order by `Group`, Age desc, person
) as x
where x.row_number <= 2;
See Demo
In other databases you can do this using ROW_NUMBER. MySQL doesn't support ROW_NUMBER but you can use variables to emulate it:
SELECT
person,
groupname,
age
FROM
(
SELECT
person,
groupname,
age,
#rn := IF(#prev = groupname, #rn + 1, 1) AS rn,
#prev := groupname
FROM mytable
JOIN (SELECT #prev := NULL, #rn := 0) AS vars
ORDER BY groupname, age DESC, person
) AS T1
WHERE rn <= 2
See it working online: sqlfiddle
Edit I just noticed that bluefeet posted a very similar answer: +1 to him. However this answer has two small advantages:
It it is a single query. The variables are initialized inside the SELECT statement.
It handles ties as described in the question (alphabetical order by name).
So I'll leave it here in case it can help someone.
Try this:
SELECT a.person, a.group, a.age FROM person AS a WHERE
(SELECT COUNT(*) FROM person AS b
WHERE b.group = a.group AND b.age >= a.age) <= 2
ORDER BY a.group ASC, a.age DESC
DEMO
How about using self-joining:
CREATE TABLE mytable (person, groupname, age);
INSERT INTO mytable VALUES('Bob',1,32);
INSERT INTO mytable VALUES('Jill',1,34);
INSERT INTO mytable VALUES('Shawn',1,42);
INSERT INTO mytable VALUES('Jake',2,29);
INSERT INTO mytable VALUES('Paul',2,36);
INSERT INTO mytable VALUES('Laura',2,39);
SELECT a.* FROM mytable AS a
LEFT JOIN mytable AS a2
ON a.groupname = a2.groupname AND a.age <= a2.age
GROUP BY a.person
HAVING COUNT(*) <= 2
ORDER BY a.groupname, a.age DESC;
gives me:
a.person a.groupname a.age
---------- ----------- ----------
Shawn 1 42
Jill 1 34
Laura 2 39
Paul 2 36
I was strongly inspired by the answer from Bill Karwin to Select top 10 records for each category
Also, I'm using SQLite, but this should work on MySQL.
Another thing: in the above, I replaced the group column with a groupname column for convenience.
Edit:
Following-up on the OP's comment regarding missing tie results, I incremented on snuffin's answer to show all the ties. This means that if the last ones are ties, more than 2 rows can be returned, as shown below:
.headers on
.mode column
CREATE TABLE foo (person, groupname, age);
INSERT INTO foo VALUES('Paul',2,36);
INSERT INTO foo VALUES('Laura',2,39);
INSERT INTO foo VALUES('Joe',2,36);
INSERT INTO foo VALUES('Bob',1,32);
INSERT INTO foo VALUES('Jill',1,34);
INSERT INTO foo VALUES('Shawn',1,42);
INSERT INTO foo VALUES('Jake',2,29);
INSERT INTO foo VALUES('James',2,15);
INSERT INTO foo VALUES('Fred',1,12);
INSERT INTO foo VALUES('Chuck',3,112);
SELECT a.person, a.groupname, a.age
FROM foo AS a
WHERE a.age >= (SELECT MIN(b.age)
FROM foo AS b
WHERE (SELECT COUNT(*)
FROM foo AS c
WHERE c.groupname = b.groupname AND c.age >= b.age) <= 2
GROUP BY b.groupname)
ORDER BY a.groupname ASC, a.age DESC;
gives me:
person groupname age
---------- ---------- ----------
Shawn 1 42
Jill 1 34
Laura 2 39
Paul 2 36
Joe 2 36
Chuck 3 112
Snuffin solution seems quite slow to execute when you've got plenty of rows and Mark Byers/Rick James and Bluefeet solutions doesn't work on my environnement (MySQL 5.6) because order by is applied after execution of select, so here is a variant of Marc Byers/Rick James solutions to fix this issue (with an extra imbricated select):
select person, groupname, age
from
(
select person, groupname, age,
(#rn:=if(#prev = groupname, #rn +1, 1)) as rownumb,
#prev:= groupname
from
(
select person, groupname, age
from persons
order by groupname , age desc, person
) as sortedlist
JOIN (select #prev:=NULL, #rn :=0) as vars
) as groupedlist
where rownumb<=2
order by groupname , age desc, person;
I tried similar query on a table having 5 millions rows and it returns result in less than 3 seconds
If the other answers are not fast enough Give this code a try:
SELECT
province, n, city, population
FROM
( SELECT #prev := '', #n := 0 ) init
JOIN
( SELECT #n := if(province != #prev, 1, #n + 1) AS n,
#prev := province,
province, city, population
FROM Canada
ORDER BY
province ASC,
population DESC
) x
WHERE n <= 3
ORDER BY province, n;
Output:
+---------------------------+------+------------------+------------+
| province | n | city | population |
+---------------------------+------+------------------+------------+
| Alberta | 1 | Calgary | 968475 |
| Alberta | 2 | Edmonton | 822319 |
| Alberta | 3 | Red Deer | 73595 |
| British Columbia | 1 | Vancouver | 1837970 |
| British Columbia | 2 | Victoria | 289625 |
| British Columbia | 3 | Abbotsford | 151685 |
| Manitoba | 1 | ...
Check this out:
SELECT
p.Person,
p.`Group`,
p.Age
FROM
people p
INNER JOIN
(
SELECT MAX(Age) AS Age, `Group` FROM people GROUP BY `Group`
UNION
SELECT MAX(p3.Age) AS Age, p3.`Group` FROM people p3 INNER JOIN (SELECT MAX(Age) AS Age, `Group` FROM people GROUP BY `Group`) p4 ON p3.Age < p4.Age AND p3.`Group` = p4.`Group` GROUP BY `Group`
) p2 ON p.Age = p2.Age AND p.`Group` = p2.`Group`
ORDER BY
`Group`,
Age DESC,
Person;
SQL Fiddle: http://sqlfiddle.com/#!2/cdbb6/15
WITH cte_window AS (
SELECT movie_name,director_id,release_date,
ROW_NUMBER() OVER( PARTITION BY director_id ORDER BY release_date DESC) r
FROM movies
)
SELECT * FROM cte_window WHERE r <= <n>;
Above query will returns latest n movies for each directors.
I wanted to share this because I spent a long time searching for an easy way to implement this in a java program I'm working on. This doesn't quite give the output you're looking for but its close. The function in mysql called GROUP_CONCAT() worked really well for specifying how many results to return in each group. Using LIMIT or any of the other fancy ways of trying to do this with COUNT didn't work for me. So if you're willing to accept a modified output, its a great solution. Lets say I have a table called 'student' with student ids, their gender, and gpa. Lets say I want to top 5 gpas for each gender. Then I can write the query like this
SELECT sex, SUBSTRING_INDEX(GROUP_CONCAT(cast(gpa AS char ) ORDER BY gpa desc), ',',5)
AS subcategories FROM student GROUP BY sex;
Note that the parameter '5' tells it how many entries to concatenate into each row
And the output would look something like
+--------+----------------+
| Male | 4,4,4,4,3.9 |
| Female | 4,4,3.9,3.9,3.8|
+--------+----------------+
You can also change the ORDER BY variable and order them a different way. So if I had the student's age I could replace the 'gpa desc' with 'age desc' and it will work! You can also add variables to the group by statement to get more columns in the output. So this is just a way I found that is pretty flexible and works good if you are ok with just listing results.
In SQL Server row_numer() is a powerful function that can get result easily as below
select Person,[group],age
from
(
select * ,row_number() over(partition by [group] order by age desc) rn
from mytable
) t
where rn <= 2
There is a really nice answer to this problem at MySQL - How To Get Top N Rows per Each Group
Based on the solution in the referenced link, your query would be like:
SELECT Person, Group, Age
FROM
(SELECT Person, Group, Age,
#group_rank := IF(#group = Group, #group_rank + 1, 1) AS group_rank,
#current_group := Group
FROM `your_table`
ORDER BY Group, Age DESC
) ranked
WHERE group_rank <= `n`
ORDER BY Group, Age DESC;
where n is the top n and your_table is the name of your table.
I think the explanation in the reference is really clear. For quick reference I will copy and paste it here:
Currently MySQL does not support ROW_NUMBER() function that can assign
a sequence number within a group, but as a workaround we can use MySQL
session variables.
These variables do not require declaration, and can be used in a query
to do calculations and to store intermediate results.
#current_country := country This code is executed for each row and
stores the value of country column to #current_country variable.
#country_rank := IF(#current_country = country, #country_rank + 1, 1)
In this code, if #current_country is the same we increment rank,
otherwise set it to 1. For the first row #current_country is NULL, so
rank is also set to 1.
For correct ranking, we need to have ORDER BY country, population DESC
SELECT
p1.Person,
p1.`GROUP`,
p1.Age
FROM
person AS p1
WHERE
(
SELECT
COUNT( DISTINCT ( p2.age ) )
FROM
person AS p2
WHERE
p2.`GROUP` = p1.`GROUP`
AND p2.Age >= p1.Age
) < 2
ORDER BY
p1.`GROUP` ASC,
p1.age DESC
reference leetcode
The following is the simplest possible example, though any solution should be able to scale to however many n top results are needed:
Given a table like that below, with person, group, and age columns, how would you get the 2 oldest people in each group? (Ties within groups should not yield more results, but give the first 2 in alphabetical order)
+--------+-------+-----+
| Person | Group | Age |
+--------+-------+-----+
| Bob | 1 | 32 |
| Jill | 1 | 34 |
| Shawn | 1 | 42 |
| Jake | 2 | 29 |
| Paul | 2 | 36 |
| Laura | 2 | 39 |
+--------+-------+-----+
Desired result set:
+--------+-------+-----+
| Shawn | 1 | 42 |
| Jill | 1 | 34 |
| Laura | 2 | 39 |
| Paul | 2 | 36 |
+--------+-------+-----+
NOTE: This question builds on a previous one- Get records with max value for each group of grouped SQL results - for getting a single top row from each group, and which received a great MySQL-specific answer from #Bohemian:
select *
from (select * from mytable order by `Group`, Age desc, Person) x
group by `Group`
Would love to be able to build off this, though I don't see how.
Here is one way to do this, using UNION ALL (See SQL Fiddle with Demo). This works with two groups, if you have more than two groups, then you would need to specify the group number and add queries for each group:
(
select *
from mytable
where `group` = 1
order by age desc
LIMIT 2
)
UNION ALL
(
select *
from mytable
where `group` = 2
order by age desc
LIMIT 2
)
There are a variety of ways to do this, see this article to determine the best route for your situation:
http://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/
Edit:
This might work for you too, it generates a row number for each record. Using an example from the link above this will return only those records with a row number of less than or equal to 2:
select person, `group`, age
from
(
select person, `group`, age,
(#num:=if(#group = `group`, #num +1, if(#group := `group`, 1, 1))) row_number
from test t
CROSS JOIN (select #num:=0, #group:=null) c
order by `Group`, Age desc, person
) as x
where x.row_number <= 2;
See Demo
In other databases you can do this using ROW_NUMBER. MySQL doesn't support ROW_NUMBER but you can use variables to emulate it:
SELECT
person,
groupname,
age
FROM
(
SELECT
person,
groupname,
age,
#rn := IF(#prev = groupname, #rn + 1, 1) AS rn,
#prev := groupname
FROM mytable
JOIN (SELECT #prev := NULL, #rn := 0) AS vars
ORDER BY groupname, age DESC, person
) AS T1
WHERE rn <= 2
See it working online: sqlfiddle
Edit I just noticed that bluefeet posted a very similar answer: +1 to him. However this answer has two small advantages:
It it is a single query. The variables are initialized inside the SELECT statement.
It handles ties as described in the question (alphabetical order by name).
So I'll leave it here in case it can help someone.
Try this:
SELECT a.person, a.group, a.age FROM person AS a WHERE
(SELECT COUNT(*) FROM person AS b
WHERE b.group = a.group AND b.age >= a.age) <= 2
ORDER BY a.group ASC, a.age DESC
DEMO
How about using self-joining:
CREATE TABLE mytable (person, groupname, age);
INSERT INTO mytable VALUES('Bob',1,32);
INSERT INTO mytable VALUES('Jill',1,34);
INSERT INTO mytable VALUES('Shawn',1,42);
INSERT INTO mytable VALUES('Jake',2,29);
INSERT INTO mytable VALUES('Paul',2,36);
INSERT INTO mytable VALUES('Laura',2,39);
SELECT a.* FROM mytable AS a
LEFT JOIN mytable AS a2
ON a.groupname = a2.groupname AND a.age <= a2.age
GROUP BY a.person
HAVING COUNT(*) <= 2
ORDER BY a.groupname, a.age DESC;
gives me:
a.person a.groupname a.age
---------- ----------- ----------
Shawn 1 42
Jill 1 34
Laura 2 39
Paul 2 36
I was strongly inspired by the answer from Bill Karwin to Select top 10 records for each category
Also, I'm using SQLite, but this should work on MySQL.
Another thing: in the above, I replaced the group column with a groupname column for convenience.
Edit:
Following-up on the OP's comment regarding missing tie results, I incremented on snuffin's answer to show all the ties. This means that if the last ones are ties, more than 2 rows can be returned, as shown below:
.headers on
.mode column
CREATE TABLE foo (person, groupname, age);
INSERT INTO foo VALUES('Paul',2,36);
INSERT INTO foo VALUES('Laura',2,39);
INSERT INTO foo VALUES('Joe',2,36);
INSERT INTO foo VALUES('Bob',1,32);
INSERT INTO foo VALUES('Jill',1,34);
INSERT INTO foo VALUES('Shawn',1,42);
INSERT INTO foo VALUES('Jake',2,29);
INSERT INTO foo VALUES('James',2,15);
INSERT INTO foo VALUES('Fred',1,12);
INSERT INTO foo VALUES('Chuck',3,112);
SELECT a.person, a.groupname, a.age
FROM foo AS a
WHERE a.age >= (SELECT MIN(b.age)
FROM foo AS b
WHERE (SELECT COUNT(*)
FROM foo AS c
WHERE c.groupname = b.groupname AND c.age >= b.age) <= 2
GROUP BY b.groupname)
ORDER BY a.groupname ASC, a.age DESC;
gives me:
person groupname age
---------- ---------- ----------
Shawn 1 42
Jill 1 34
Laura 2 39
Paul 2 36
Joe 2 36
Chuck 3 112
Snuffin solution seems quite slow to execute when you've got plenty of rows and Mark Byers/Rick James and Bluefeet solutions doesn't work on my environnement (MySQL 5.6) because order by is applied after execution of select, so here is a variant of Marc Byers/Rick James solutions to fix this issue (with an extra imbricated select):
select person, groupname, age
from
(
select person, groupname, age,
(#rn:=if(#prev = groupname, #rn +1, 1)) as rownumb,
#prev:= groupname
from
(
select person, groupname, age
from persons
order by groupname , age desc, person
) as sortedlist
JOIN (select #prev:=NULL, #rn :=0) as vars
) as groupedlist
where rownumb<=2
order by groupname , age desc, person;
I tried similar query on a table having 5 millions rows and it returns result in less than 3 seconds
If the other answers are not fast enough Give this code a try:
SELECT
province, n, city, population
FROM
( SELECT #prev := '', #n := 0 ) init
JOIN
( SELECT #n := if(province != #prev, 1, #n + 1) AS n,
#prev := province,
province, city, population
FROM Canada
ORDER BY
province ASC,
population DESC
) x
WHERE n <= 3
ORDER BY province, n;
Output:
+---------------------------+------+------------------+------------+
| province | n | city | population |
+---------------------------+------+------------------+------------+
| Alberta | 1 | Calgary | 968475 |
| Alberta | 2 | Edmonton | 822319 |
| Alberta | 3 | Red Deer | 73595 |
| British Columbia | 1 | Vancouver | 1837970 |
| British Columbia | 2 | Victoria | 289625 |
| British Columbia | 3 | Abbotsford | 151685 |
| Manitoba | 1 | ...
Check this out:
SELECT
p.Person,
p.`Group`,
p.Age
FROM
people p
INNER JOIN
(
SELECT MAX(Age) AS Age, `Group` FROM people GROUP BY `Group`
UNION
SELECT MAX(p3.Age) AS Age, p3.`Group` FROM people p3 INNER JOIN (SELECT MAX(Age) AS Age, `Group` FROM people GROUP BY `Group`) p4 ON p3.Age < p4.Age AND p3.`Group` = p4.`Group` GROUP BY `Group`
) p2 ON p.Age = p2.Age AND p.`Group` = p2.`Group`
ORDER BY
`Group`,
Age DESC,
Person;
SQL Fiddle: http://sqlfiddle.com/#!2/cdbb6/15
WITH cte_window AS (
SELECT movie_name,director_id,release_date,
ROW_NUMBER() OVER( PARTITION BY director_id ORDER BY release_date DESC) r
FROM movies
)
SELECT * FROM cte_window WHERE r <= <n>;
Above query will returns latest n movies for each directors.
I wanted to share this because I spent a long time searching for an easy way to implement this in a java program I'm working on. This doesn't quite give the output you're looking for but its close. The function in mysql called GROUP_CONCAT() worked really well for specifying how many results to return in each group. Using LIMIT or any of the other fancy ways of trying to do this with COUNT didn't work for me. So if you're willing to accept a modified output, its a great solution. Lets say I have a table called 'student' with student ids, their gender, and gpa. Lets say I want to top 5 gpas for each gender. Then I can write the query like this
SELECT sex, SUBSTRING_INDEX(GROUP_CONCAT(cast(gpa AS char ) ORDER BY gpa desc), ',',5)
AS subcategories FROM student GROUP BY sex;
Note that the parameter '5' tells it how many entries to concatenate into each row
And the output would look something like
+--------+----------------+
| Male | 4,4,4,4,3.9 |
| Female | 4,4,3.9,3.9,3.8|
+--------+----------------+
You can also change the ORDER BY variable and order them a different way. So if I had the student's age I could replace the 'gpa desc' with 'age desc' and it will work! You can also add variables to the group by statement to get more columns in the output. So this is just a way I found that is pretty flexible and works good if you are ok with just listing results.
In SQL Server row_numer() is a powerful function that can get result easily as below
select Person,[group],age
from
(
select * ,row_number() over(partition by [group] order by age desc) rn
from mytable
) t
where rn <= 2
There is a really nice answer to this problem at MySQL - How To Get Top N Rows per Each Group
Based on the solution in the referenced link, your query would be like:
SELECT Person, Group, Age
FROM
(SELECT Person, Group, Age,
#group_rank := IF(#group = Group, #group_rank + 1, 1) AS group_rank,
#current_group := Group
FROM `your_table`
ORDER BY Group, Age DESC
) ranked
WHERE group_rank <= `n`
ORDER BY Group, Age DESC;
where n is the top n and your_table is the name of your table.
I think the explanation in the reference is really clear. For quick reference I will copy and paste it here:
Currently MySQL does not support ROW_NUMBER() function that can assign
a sequence number within a group, but as a workaround we can use MySQL
session variables.
These variables do not require declaration, and can be used in a query
to do calculations and to store intermediate results.
#current_country := country This code is executed for each row and
stores the value of country column to #current_country variable.
#country_rank := IF(#current_country = country, #country_rank + 1, 1)
In this code, if #current_country is the same we increment rank,
otherwise set it to 1. For the first row #current_country is NULL, so
rank is also set to 1.
For correct ranking, we need to have ORDER BY country, population DESC
SELECT
p1.Person,
p1.`GROUP`,
p1.Age
FROM
person AS p1
WHERE
(
SELECT
COUNT( DISTINCT ( p2.age ) )
FROM
person AS p2
WHERE
p2.`GROUP` = p1.`GROUP`
AND p2.Age >= p1.Age
) < 2
ORDER BY
p1.`GROUP` ASC,
p1.age DESC
reference leetcode
I have a set of approx 9000 tutor ids in an array and i have put them in a string like:
(1,2, 3, 4,5,6,7,....9000,9001,9002)
so that i can use them in the following query:
select count(student_assignment.assignment_id) as total_assignment from
student_assignment, assigned_tutor_fk where assignment_status = 'closed'
and assigned_tutor_fk in (1,2, 3, 4,5,6,7,..100,101,103...9000,9001,9002)
group by assigned tutor_fk.
I want to calculate total number of rows associated with each tutor(assigned_tutor_fk), and those tutors which do not have an assignment ie those which do not have assignment
record in the table i want to show their assignment count as 0, and i just want my query to return count and assigned_tutor_fk
my table structure is:
assignment_id | assigned_tutor_fk | assignment_date | student_id |
| 1 | 2 | 22-01-2011 | 4 |
| 2 | 3 | 14-03-2011 | 5 |
Im trying to get my output to be like this:
|total_assignment | assigned_tutor_fk |
| 5 | 4 |
| 2 | 7 |
| 0 | 8 |
Update: I tthink i have not been able to express myself properly,i already have a list of tutors filtered on another criteria, it was very complex to combine these two queries so now i have a set of the tutor id's and i want the sum to be displayed as zero in case the tutors does not have assignment record. please help me on this as i don know wht to do now
SELECT t.id, COUNT(sa.assignment_id)
FROM tutor t
LEFT JOIN
student_assignement sa
ON sa.assignment_tutor_fk = t.id
WHERE t.id IN (1, 2, ..., 9002)
GROUP BY
t.id
dont put the tutors in a string. Select them from a table and do a LEFT JOIN with the assignment and FK table. Without knowing all of your tables, i'm guessing it would look like this:
select
t.tutorId,
count(sa.assignment_id) as total_assignment
from
tutor t
LEFT JOIN
assigned_tutor_fk fk
ON
fk.assigned_tutor_fk = tutor.tutorId
LEFT JOIN
student_assignment sa
ON
fk.assignment_id = sa.id
where
sa.assignment_status = 'closed' OR
ISNULL(sa.assignment_status) -- if join fails.
group by
t.tutorId
Left Join retrieves all your values from the tutor table and merges it with the joined table IF there is a match. If not, NULL is inserted.
SELECT
count(*) as total_assignment,
assigned_tutor_fk
FROM assignmentTable
GROUP BY assigned_tutor_fk