Implode PHP array and display text strings in their own DIVs - php

I am using the following database query and PHP code to retrieve checkbox values and display them on the page as HTML.
$submissionId = JRequest::getInt('submissionId');
$db = JFactory::getDbo();
$db->setQuery("SELECT `FormId`, `FieldName`, `FieldValue` FROM `#__rsform_submission_values` WHERE `FormId` = '5' AND `SubmissionId` = '$submissionId' AND `FieldName` = 'documents'");
$rows = $db->loadObjectList();
foreach($rows as $row) {
$documentsArray[] = $row->FieldValue;
}
$document = implode(' ', $documentsArray);
$formLayout .= '<div class="formContainer">';
$formLayout .= '<div class="formView">';
for($i = 0; $i < count($document); $i++) {
$formLayout .= "<div>" . $document . "</div>";
}
$formLayout .= '</div>';
$formLayout .= '</div>';
The code is partially working. The problem lies in the "FieldValue" row containing one or more checkbox values. I am needing to have each checkbox value formatted and displayed in it's own DIV like I have detailed below.
<div>Checkbox value #1</div>
<div>Checkbox value #2</div>
<div>Checkbox value #3</div>
I only need to show the checkbox values and not the checkboxes themselves. Any tips on how I can select each individual string from the imploded array and display it in it's own DIV. Thank you.

Just remove a little part of your code:
$submissionId = JRequest::getInt('submissionId');
$db = JFactory::getDbo();
$db->setQuery("SELECT `FormId`, `FieldName`, `FieldValue` FROM `#__rsform_submission_values` WHERE `FormId` = '5' AND `SubmissionId` = '$submissionId' AND `FieldName` = 'documents'");
$rows = $db->loadObjectList();
$formLayout .= '<div class="formContainer">';
$formLayout .= '<div class="formView">';
foreach($rows as $row) {
$formLayout .= "<div>" . $row->FieldValue . "</div>";
}
$formLayout .= '</div>';
$formLayout .= '</div>';
Or implode in "divs":
...
foreach($rows as $row) {
$documentsArray[] = $row->FieldValue;
}
$document = implode('</div><div>', $documentsArray);
$formLayout .= '<div class="formContainer">';
$formLayout .= '<div class="formView">';
$formLayout .= '<div>' . $document . '</div>';
$formLayout .= '</div>';
$formLayout .= '</div>';

Related

How can I echo two items per one time by using PHP Foreach?

I'm using PHP to echo my products from the database. If we just use foreach, we will get the result one item per a loop, but actually I want it echo two items per one times as ub the below function.
This is my PHP function using foreach to fetch data from database.
I've used row item selector to wrap product selector, so I want to echo a block of product two times, and then it should echo the row item.
Example: row item = 1 then product = 2
public function last_upated_products() {
$data = $this->newest_products_from_db('products');
$out = '';
if ($data) {
foreach ($data as $k => $row) {
$out .= '<div class="row item">';
$out .= '<div class="product">';
$out .= '<div class="image">';
$out .= '<img src="' . base_url('asset/img/main/9.jpg') . '" alt="img" class="img-responsive">';
$out .= '<div class="promotion"><span class="discount">' . $row['prod_id'] . '% OFF</span> </div>';
$out .= '</div>';
$out .= '<div class="description"><div class="price"><span>$' . $row['prod_price'] . '</span></div><h4>' . $row['prod_name'] . '</h4>';
$out .= '<p>' . $row['prod_descrip'] . '</p>';
$out .= '</div>';
$out .= '</div>';
$out .= '</div>';
}
}
return $out;
}
This function will echo one item for a loop.
You can not print two times in one iteration of a loop. You can use conditional HTML output to do this job.
Consider this:
function last_upated_products() {
$data = $this->newest_products_from_db('products');
$out = '';
$counter = 1;
$length = count($data);
if ($data) {
foreach ($data as $k => $row) {
if ($counter % 2 != 0) {
$out .= '<div class="row item">';
}
$out .= '<div class="product">';
$out .= '<div class="image">';
$out .= '<img src="' . base_url('asset/img/main/9.jpg') . '" alt="img" class="img-responsive">';
$out .= '<div class="promotion"><span class="discount">' . $row['prod_id'] . '% OFF</span> </div>';
$out .= '</div>';
$out .= '<div class="description"><div class="price"><span>$' . $row['prod_price'] . '</span></div><h4>' . $row['prod_name'] . '</h4>';
$out .= '<p>' . $row['prod_descrip'] . '</p>';
$out .= '</div>';
$out .= '</div>';
if ($counter % 2 == 0 || $length == $counter) {
$out .= '</div>';
}
$counter++;
}
}
return $out;
}
You can use the modulus operator to make the check. If your iterator is a multiple of two it will output the appropriate elements (it does this by checking that the remainder is zero):
public function last_upated_products() {
$data = $this->newest_products_from_db('products');
$out = '';
if ($data) {
$i = 0;
foreach ($data as $k => $row) {
if( ($i % 2) === 0) {
$out .= '<div class="row item">';
}
$out .= '<div class="product">';
$out .= '<div class="image">';
$out .= '<img src="' . base_url('asset/img/main/9.jpg') . '" alt="img" class="img-responsive">';
$out .= '<div class="promotion"><span class="discount">' . $row['prod_id'] . '% OFF</span> </div>';
$out .= '</div>';
$out .= '<div class="description"><div class="price"><span>$' . $row['prod_price'] . '</span></div><h4>' . $row['prod_name'] . '</h4>';
$out .= '<p>' . $row['prod_descrip'] . '</p>';
$out .= '</div>';
$out .= '</div>';
if( ($i + 1) % 2 === 0 || ($i + 1) === count($data) ) {
$out .= '</div>';
}
$i++;
}
}
return $out;
}
Note that the last bit ($i + 1) === count($data) is important in the event that your set holds an uneven number.

TCPDF - Having trouble with getting MySQL content to show in PDF

I am trying to make a printable version of a catalogue of products. If I display the products in HTML it works fine. But when I try and use TCPDF I loose half of it or nothing at all.
$query = "SELECT ID, Category_Name, Image FROM Categories ORDER BY Position ASC";
$result = mysqli_query($connection, $query);
confirm_query($result);
while ($cat = mysqli_fetch_row($result)) {
// add a page
$pdf->AddPage();
$query1 = "SELECT * FROM Products WHERE Category = " . $cat[0] . " AND Visibility = 1 ORDER BY Product_Name ASC";
$result1 = mysqli_query($connection, $query1);
$html = $query1;
confirm_query($result1);
//$html .= '<style>'. file_get_contents('./images/print.css').'</style>';
$html .= '<table style="margin: 0 auto;"><tbody>';
$html .= '<tr><th colspan="6"><div id="title" style="color: white;">' . $cat[1] . '</div></th></tr>';
$html .= '<tr>';
$html .= '<th></th>';
$html .= '<th>Product</th>';
$html .= '<th>Pack Size</th>';
$html .= '<th>Price(Ex VAT)</th>';
$html .= '<th>Price(Inc)</th>';
$html .= '<th>RRP</th>';
$html .= '</tr>';
// Show product prodcuts from selected category
while ( $row123 = mysqli_fetch_row($result1)) {
$html .= '<tr><td>';
$html .= '<img width="100px" height="100px" src="/images/' . $row123[6] . '"/>';
$html .= '</td><td>';
$html .= '<b><u>' . $row123[1] . '</u></b><br /><i>' . $row123[5] . '</i>';
$html .= '</td><td>';
$html .= $row123[3];
$html .= '</td><td>';
$html .= '£' . $row123[4];
//echo '<br />';
$html .= '</td><td>';
$query2 = "SELECT VAT FROM VAT WHERE ID = " . $row123[7];
$result2 = mysqli_query($connection, $query2);
confirm_query($result2);
// Put results in an accessible form
$result_array2 = array();
while ($row234 = mysqli_fetch_row($result2)) {$result_array2[] = $row234;}
$html .= '£' . number_format($row123[4] + ($result_array2[0][0] * $row123[4] / 100), 2, '.', '');
$html .= '</td><td>';
if ($row123[9] == "") {
$html .= "N/A";
} else {
$html .= '£' . number_format($row123[9], 2, '.', '');
}
$html .= '</td>';
$html .='</tr>';
}
$html .= '</tbody></table>';
// output the HTML content
$pdf->writeHTML($html, true, false, true, false, '');
}
If I comment out the second while loop, I can get the first query ($query1) to echo out. One per page for each category. But when I uncomment it, it just creates 4 blank pages.

Split Joomla Database result in 3 columns

I am trying to split the mysql query result using joomla sql syntax and stuck as to how I can split the same in three columns.
my query for which I am getting the result in single column is like this:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query = "select m.member_name name from member m,club_name c where pst in (6,35,39,40) and c.id=m.club_name and c.id = '{club_name___id_raw}'";
if (!$query) {
echo 'Could not run query:' . mysql_error();
exit;
}
$i = 0;
$db->setQuery($query);
$results = $db->loadObjectList();
$text1 .= '<table style="border:1px solid silver;padding:2px;">';
$text1 .= "<tr><th>Past President</th><th>Past President</th></tr>";
foreach ($results as $result) {
$text .= "<tr><td>";
$text .= $result->name;
$text .= "</td></tr>";
$text .= "<br/>";
}
$text .= "</table>";
return $text1 . $text;
I am getting the result like
Past President
Jaydeven
Ashok
surendra
Narendra
Gopal
I want the result like
Past President Past President Past President
Jaydevan Ashok Surendra
Narendra Gopal
How can modify the above query to get the result as shown
Thanks.
Ok I somewhat achieved what I wanted. I have edited the query like below:
$db->setQuery($query);
$results = $db->loadObjectList();
//var_dump($results);exit;
$text1 .= '<table style="border:1px solid silver;padding:2px;width:800px;">';
$text1 .= "<tr>";
$i = 0;
foreach ($results as $result) {
if ($i % 3 === 0) {
$text .= "</tr><tr>";
}
$text .= "<td>";
$text .= $result->name;
$text .= "</td>";
$text .= $i++;
//$text .= "<br/>";
}
$text .= "</tr></table>";
return $text1 . $text;
Only problem I am now facing in my result set is I am getting a
string of number i.e. 0123456
if the result contains 7 items, which couldn't hide.
Thanks.

Insert array values into mysql database

The variables are being posted from a previous page through array values.
when I print_r($values) I get the whole value on this array including the numerical values of the array ex: array[0], array[1] ..etc.
Please can some tell me what I am doing wrong. the implode function was not used because the values are passed from a cart page though session variables.
First part of code below:
<?php
$current_url = base64_encode($url="http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']);
if(isset($_SESSION["products"]))
{
$total = 0;
echo '<form method="post" action="process.php">';
echo '<ul>';
$cart_items = 0;
foreach ($_SESSION["products"] as $cart_itm)
{
$product_code = $cart_itm["code"];
$results = $mysqli->query("SELECT Title,Description,Price FROM main_menu WHERE MenuID='$product_code' LIMIT 1");
$obj = $results->fetch_object();
echo '<li class="cart-itm">';
echo '<span class="remove-itm">×</span>';
echo '<div class="p-price">'.$currency.$obj->Price.'</div>';
echo '<div class="product-info">';
echo '<h3>'.$obj->Title.' (Code :'.$product_code.')</h3> ';
echo '<div class="p-qty">Qty : '.$cart_itm["qty"].'</div>';
echo '<div>'.$obj->Description.'</div>';
echo '</div>';
echo '</li>';
$subtotal = ($cart_itm["price"]*$cart_itm["qty"]);
$total = ($total + $subtotal);
echo '<input type="hidden" name="item_name['.$cart_items.']" value="'.$obj->Title.'" />';
echo '<input type="hidden" name="item_code['.$cart_items.']" value="'.$product_code.'" />';
echo '<input type="hidden" name="item_desc['.$cart_items.']" value="'.$obj->Description.'" />';
echo '<input type="hidden" name="item_qty['.$cart_items.']" value="'.$cart_itm["qty"].'" />';
$cart_items ++;
}
echo '</ul>';
echo '<span class="check-out-txt">';
echo '<strong>Total : '.$currency.$total.'</strong> ';
echo '<input name=\'submit\' type="submit" value="Complete Order" style=\"width:150px;background:#333;color:#ffcc33;height:30px;\" />';
echo '</span>';
echo '</form>';
}else{
echo 'No items added';
}
?>
Second part:
Try $post and the table name in the given function and use mysql_real_escape_string() to avoid any possibility of the SQL Injection
form.php
<?php
include ('func_curd.php') ;
if($_POST['hiddenfieldinfo']=='ok')
{
$r=insert_your_table_name($_POST);
if($r==true)
{
header('Location:'.get_full_url()); /* to redirect the form to the same page after successful submission*/
}
}
?>
func_curd.php
<?php
function insert_your_table_name($post)
{
unset($post['hiddenfieldinfo']);
/* Here I am unsetting this value as it is hidden field
in the form , which I am using as form submission check and
is not in database column, apart form auto-increment in database
that is id, you have to maek sure all the post value and column
name matches with case-sensitivities */
$u = insert('your_table_name', $post);
$r=is_numeric($u)? true : false ;
return $r;
}
function insert($table, $values){
$query="INSERT INTO `$table` ";
$column='(';
$val=' (';
$count=count($values);
$mk=1;
foreach ($values as $key=>$value)
{
$value=mysql_real_escape_string($value);
if ($mk==$count)
{
$column .= '`'.$key.'`';
$val .= "'".$value."'";
}
else
{
$column .= '`'.$key.'`, ';
$val .= "'".$value."', ";
}
$mk++;
}
$column .=') ';
$val .=')';
$query=$query.$column.'VALUES'.$val;
$Q=mysql_query($query);
if(mysql_error())
{
return print(mysql_error());
}
else
{
$insert_id=mysql_insert_id();
return $insert_id;
}
}
?>
try this one:
<?php
require_once('config/connect.php');
$item_name = strip_tags($_POST['item_name']);
$item_code = strip_tags($_POST['item_code']);
$item_desc = strip_tags($_POST['item_desc']);
$item_qty = strip_tags($_POST['qty']);
$price = strip_tags($_POST['price']);
$fields = "item_name, item_code, item_desc, price,qty";
$query = "INSERT INTO `x` SET ";
$i = 0;
foreach( $fields as $fieldname )
{
if ( $i > 0 )
$query .= ", ";
$val = strip_tags($_POST[$fieldname]);
$query .= "`" . $fieldname . "` = '" . $val . "'"
$i++
}
$query_result = mysql_query($query);
echo" Record saved";
print_r ( $query );
?>
There are certain syntax errors in your code like not closed foreach etc. whihc I did skip.
As a recommendation: code like this is disclosing the database structure to everyone on the internet - form field names = database col names. This is generally a bad idea.
Better is a kind of mapping table:
$fields = array (
'myFormName' => 'mySqlName',
....
foreach( $fields as $fieldname => $sqlame)
{
if ( $i > 0 )
$query .= ", ";
$val = strip_tags($_POST[$fieldname]);
$query .= "`" . $sqlname. "` = '" . $val . "'"
....
which also will make the form more independent from the underlying data structures.

Display a table in while loop

I am trying to display a table in while loop with 3 rows and 3 td for each row. But I am confusing how to archived thit.
This is my code so far:
while($row = mysqli_fetch_array($result)){
$testimonial = $row['testimonial'];
$cityName = $row['city_name'];
$name = $row['name'];
$imageName = $row['image_name'];
$member = $row['membership_type'];
$testimonial = nl2br($testimonial);
//Create new testimonial output
$output = "<table>\n";
$output .= " <tr>\n";
$output .= " <td>\n";
$output .= " <p>\n";
$output .= " <img src=\"".UPLOAD_DIR.$imageName."\" />";
$output .= " {$testimonial}";
$output .= " </p>\n";
$output .= " <p class=\"name\">{$name}<br />\n";
$output .= " <span>A Teacher - From {$cityName}</span></p>\n";
$output .= " </td>\n";
$output .= " </tr>\n";
$output .= "</table>\n";
echo $output;
}
The above code given me a table with multiple rows and 1 td for each row. But it is not my expecting result.
Can anybody tell me how can I display such a table in my While loop?
The current code creates a new table for every single entry. What you want is to move the <table> and </table> pieces outside of the loop, then you want a counter to keep track of how many cells you've handled. If it's even, start a new <tr>. Otherwise, end the current </tr>. Make sure you check at the end to see if you've finished a </tr>, and optionally add an empty <td></td> if needed.
this aught to do it
<?php
echo "<table>\n";
$cells = $total = 0;
$total_cells = mysqli_num_rows($result);
while($row = mysqli_fetch_array($result))
{
$testimonial = nl2br($row['testimonial']);
$cityName = $row['city_name'];
$name = $row['name'];
$imageName = $row['image_name'];
$member = $row['membership_type'];
if ($cells === 0)
echo "<tr>\n";
//Create new testimonial output
$output = " <td>\n";
$output .= " <p>\n";
$output .= " <img src=\"".UPLOAD_DIR.$imageName."\" />";
$output .= " {$testimonial}";
$output .= " </p>\n";
$output .= " <p class=\"name\">{$name}<br />\n";
$output .= " <span>A Teacher - From {$cityName}</span></p>\n";
$output .= " </td>\n";
echo $output;
$cells++;
$total++;
if ($cells === 3 || $total === $total_cells)
{
echo "</tr>\n";
$cells = 0;
}
}
echo "</table>\n";
?>
Try this
$i = 0;
echo "<table>\n<tr>";
while($row = mysqli_fetch_array($result)){
$testimonial = $row['testimonial'];
$cityName = $row['city_name'];
$name = $row['name'];
$imageName = $row['image_name'];
$member = $row['membership_type'];
$testimonial = nl2br($testimonial);
//Create new testimonial output
$output .= " <td>\n";
$output .= " <p>\n";
$output .= " <img src=\"".UPLOAD_DIR.$imageName."\" />";
$output .= " {$testimonial}";
$output .= " </p>\n";
$output .= " <p class=\"name\">{$name}<br />\n";
$output .= " <span>A Teacher - From {$cityName}</span></p>\n";
$output .= " </td>\n";
echo $output;
if( $i %2 == 1 )
echo "</tr><tr>\n";
$i++;
}
echo "</tr>\n</table>\n";
EDIT
In general, for displaying n cells per row, change the if statement to
if( $i % n == (n - 1) )

Categories