Here's the code I've started with:
$result = mysql_query("SELECT * FROM apis_hashes_a", $link);
$count = mysql_num_rows($result);
What I need to do is to get the total sum of all rows for all tables that start with apis_hashes_.
There are tons of tables and new ones are being added all the time, but all of these tables start with apis_hashes_ at the beginning. Is this something that would be possible to do or do I have to list every table individually in the PHP code?
JUST use SUM() IN SQL.Use the code below
<?php
$query = "SELECT SUM(TABLE_ROWS) as score
FROM INFORMATION_SCHEMA.TABLES
WHERE SCHEMA = '{your_db_name}'";
$result = mysql_query($query, $link);
while($row=mysql_fetch_array($result)){
$total_rows = $row['score'];
}
echo $total_rows;
?>
Hope this helps you
The sql:
show tables like 'apis_hashes_%'
will return the list of all your tables, then you need loop thru all the names of the tables with the mysql sum() function.
Related
I am using php and mysql to create a page that displays all of the jobs we have in the database. The data is shown is a table and when a row is clicked a modal window triggers with the information of the clicked job inside. At the top of the page I want a simple counter that shows amount of paid jobs, invoiced jobs etc etc. I am using the code below but having no luck...
<?php
$con = mysql_connect("localhost","databaseusername","password");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("databasename", $con);
$result = mysql_query("select count(1) FROM jobslist");
$row = mysql_fetch_array($result);
$total = $row[0];
mysql_close($con);
?>
This code as far as I am aware is counting the amount of INT columns set to 1 rather than 0. No matter what I try I can't seem to get it to count the amount of 'paid' items in the database or 'invoiced' etc etc.
Once the count function is complete currently I am echoing out the outcome as below:
<?php echo "" . $total;?>
I am sure I am overlooking something simple, but any help is appreciated.
EDIT: TABLE STRUCTURE INCLUDED
http://i.stack.imgur.com/hcMJV.png
Assuming a column called paid you could restructure the query similar to the following. If you needed to sum the amounts involved that requires additional tweaking.
$result = mysql_query("select
( select count(*) from `jobslist` where `paid`=1 ) as 'paid',
( select count(*) from `jobslist` where `paid`=0 ) as 'unpaid'
from jobslist");
$rows = mysql_num_rows( $result );
while( $rs=mysql_fetch_object( $result ) ){
$paid=$rs->paid;
$unpaid=$rs->unpaid;
echo 'Total: '.$rows.'Paid: '. $paid.' Unpaid: '.$unpaid;
}
When I do this I usually name the COUNT result. Try this out:
$result = mysql_query("SELECT COUNT(*) AS total_rows FROM jobslist;");
$row = mysql_fetch_array($result);
$total = $row['total_rows'];
If you do not want to name the COUNT result, then give the following a go:
$result = mysql_query("SELECT COUNT(*) FROM jobslist;");
$row = mysql_fetch_array($result);
$total = $row['COUNT(*)'];
select count(1) FROM jobslist
This code as far as I am aware is counting the amount of INT columns set to 1 rather than 0.
No, this is just counting rows in your table and not filtering. If you want to count something with a specific filter you have to add that filter condition:
SELECT COUNT(*) AS `MyCount`
FROM `joblist`
WHERE `MyColumn` = 1; -- assuming MyColumn contains the INT you're looking for
You should stop using mysql_* functions. These extensions have been removed in PHP 7. Learn about prepared statements for PDO and MySQLi and consider using PDO, it's really pretty easy.
First you should change deprecated mysql_... to mysqli_... (look here how to). But it's not the reason you fail.
Unlike you seem to suppose, COUNT(1) will not look for an INT column having value 1.
Instead you must use COUNT(*) or COUNT(a_column_name) (same result), with adding a WHERE clause stating which condition is involved.
Here you seem wanting to count records where a given column (say the_column) has value 1. So you should:
SELECT COUNT(*)
FROM jobslist
WHERE the_column = 1
Last point: you don't need echo "" . in <?php echo "" . $total;?>.
Merely write <?php echo $total;?>.
I am using a script that has a different way of doing a mySQL query to what I am used to. It starts with:
$query = $db->query("SELECT * etc ..... ");
then
while ($result = $db->fetchArray($query)) {
with variables shown as $result['a'], $result['b']. etc.
All I want to do is count the rows that are selected by the query, but mysql_num_rows doesn't work on $result.
What can I use instead?
You can use the count function to count the rows
$query = $db->query("SELECT count(*) as count from (SELECT * etc ..... ) as sq ");
$result = $db->fetchArray($query);
echo $result['count'];
You can change the query to:
SELECT count(*) as cnt etc .....
Then read the results back from the query.
I have a script and I want to return 5 values from the database that have the same category but it is only returning one. Any ideas?
Here's the script:
$result = mysql_query("SELECT Category FROM GameData
WHERE Title=\"$title\" ");
//returns category to search in next select
$row= mysql_fetch_array($result);
$results = mysql_query("SELECT Title FROM GameData
WHERE Category=\"$row[0]\" LIMIT 5 ");
$rows= mysql_fetch_array($results);
print_r($rows); //returns $title from first select query
I'm new to databases and MySQL so any help would be much appreciated.
mysql_fetch_array just fetch one row in one call use loop to fetch multiple records
while($row= mysql_fetch_array($results))
{
print_r($row); //returns $title from first select query
}
You must loop over all the results: mysql_fetch_array returns one result row, so you have to call it multiple times:
while($row = mysql_fetch_array($results)) {
// here process ONE row
}
mysql_fetch_array will only fetch one row : if you want to fetch several rows, you'll have to call mysql_fetch_array several times -- in a loop, typically.
For a couple of examples, you can take a look at its manual page ; but, in your case, you'll probably want to use something like this :
$results = mysql_query("SELECT Title FROM GameData
WHERE Category='...' LIMIT 5 ");
while ($row = mysql_fetch_array($results, MYSQL_ASSOC)) {
// work with $row['Title']
}
mysql_fetch_array only returns one row, you would have to loop through the rows
see example at: http://php.net/manual/en/function.mysql-fetch-array.php
You should use following query in order to make things right.
SELECT `Title` FROM GameData
LEFT JOIN
Category ON Category.Id = GameData.Category
WHERE Category.Title = "$title" LIMIT 5
I assumed that Category has column Id.
I advise you to learn about JOINS.
Additionally, you may want to rename Category to Category_Id, and drop letter-case so Category would become category_id.
I have this
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo $row['id'];
}
This echo's all id's found in the table.
How can I choose to echo only a selected id.
Say the second id found on the table?
EDIT
I think I have confused people and myself aswell.
Let me try to explain again.
Using the above query I can echo all results found in the table with echo $row['id'];
However I do not want echo all results, just selected ones.
You guys have suggested I use limit or a Where clause.
If I do this I will be limited to just one record. This is not what I want.
I want to echo a selection of records.
Something likes this
echo $row['id'][5], $row['id'][6], $row['id'][6]
But obviously this is incorrect syntax and will not work but hopefully you get what I am trying to do.
Thanks
If you only want the second row then you could change your query to use offset and limit e.g.
SELECT id FROM table LIMIT 1, 1
You could also use a for loop instead of the while loop and then put in a conditional.
UPDATE
Just noticed comments above - you also need to sort the PHP bug by changing mysql_fetch_array to mysql_fetch_assoc.
UPDATE 2
Ok based on your update above you are looking to get all of the rows into an array which you can then iterate over.
You can just use mysql_fetch_array and then use $array[0]. For example:
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
$ids = array();
while($row = mysql_fetch_array($result)) {
$ids[] = $row[0];
}
From what I can gather from your questions you should not be selecting all records in the table if you wish to just use the Nth value, use:
SELECT id FROM table LIMIT N, 1
That will select the Nth value that was returned. Note: The first result is 0 so if you wish to get the second value the Nth value should be 1.
mysql_data_seek() let's you jump to a specific data-set(e.g. the 2.nd)
Example:
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
//get the 2nd id(counting starts at 0)
if(mysql_data_seek($result,1))
{
$row=mysql_fetch_assoc($result);
echo $row['id'];
}
OR:
use mysqli_result::fetch_all
It returns an array instead of a resultset, so you can handle it like an array and select single items directly (requires PHP5.3)
If I need to know the total number of rows in a table of database I do something like this:
$query = "SELECT * FROM tablename WHERE link='1';";
$result = mysql_query($query);
$count = mysql_num_rows($result);
Updated: I made a mistake, above is my actual way. I apologize to all
So you see the total number of data is recovered scanning through the entire database.
Is there a better way?
$query = "SELECT COUNT(*) FROM tablename WHERE link = '1'";
$result = mysql_query($query);
$count = mysql_result($result, 0);
This means you aren't transferring all your data between the database and PHP, which is obviously a huge waste of time and resources.
For what it's worth, your code wouldn't actually count the number of rows - it'd give you 2x the number of columns, as you're counting the number of items in an array representing a single row (and mysql_fetch_array gives you two entries in the array per column - one numerical and one for the column name)
SELECT COUNT(*) FROM tablename WHERE link='1';
You could just do :
SELECT count(*) FROM tablename;
for your query. The result will be a single column containing the number of rows.
If I need to know the total number of rows in a table of database
Maybe I'm missing something here but if you just want to get the total number of rows in a table you don't need a WHERE condition. Just do this:
SELECT COUNT(*) FROM tablename
With the WHERE condition you will only be counting the number of rows that meet this condition.
use below code
$qry=SHOW TABLES FROM 'database_name';
$res=mysql_query($qry);
$output=array();
$i=0;
while($row=mysql_fetch_array($res,MYSQL_NUM)){
++$i;
$sql=SELECT COUNT(*) FROM $row[0];
$output[$i]=mysql_query($sql);
}
$totalRows=array_sum($ouptput);
echo $totalRows;
http://php.net/manual/en/function.mysql-num-rows.php You need this i think.
If you are going to use the following SQL statement:
SELECT COUNT(*) FROM tablename WHERE link='1';
Make sure you have an index on the 'link' column