Given the string:
100,000 this is some text 12,000 this is text I want to match.
I need a regular expression that matches 12,000 based on matching
text I want to match
So, we can get a position with:
strpos($haystack, 'text I want to match');
Then, I guess we could use a regular expression to look backwards:
But, this is where I need help.
If you know that the digits will always precede the based context you want to match ...
preg_match('/([\d,]+)\D*text I want to match/', $str, $match);
var_dump($match[1]);
It is simple:
/ ([0-9,]+) this is text I want to match\.$/
Demo:
http://sandbox.onlinephpfunctions.com/code/b288ca9a322c7a5b54c6490334540ab142b6a979
Another solution:
$re = "/([\\d,]+)(?=\\D*text I want to match)/";
$str = "100,000 this is some text 12,000 this is text I want to match.";
preg_match($re, $str, $matches);
Live demo
Related
I'm in trouble with preg_match, I want to extract a div using preg_match.
Div Example: <div class="post_message_(RANDOM NUMBER)">
I've tried to use <div\s+class="post_message_/\w+/"\s*> to detect the number sequence after the keyword and fill the preg_match_all command.
But <div\s+class="post_message_/\w+/"\s*> is not working, anyone know how to perform this?
Regards,
Assuming you want a random number (and not random text of numbers and letters) then this will catch the 123456:
$re = "/<div\\s+class=\"post_message_([\\d]+)\"\\s*>/";
$str = "<div class=\"post_message_123456\">";
preg_match($re, $str, $matches);
I am trying to extract the digits from between the words in this string.
110.0046102.005699.0008103.0104....
I want to extract 4 digits after dot (point/period).
110.0046
102.0056
99.0008
103.0104
I was wondering if this was possible to do with a regular expression or if I should just use other way.
// replace the variable $numbers with your numbers
$numbers = "110.0046102.005699.0008103.0104";
preg_match_all("#\d+\.\d{4}#", $numbers, $matches);
var_dump($matches); // outputting all matches
https://regex101.com/r/oG1dK1/1 -> you can see the regex in action here. The numbers are in the box MATCH INFORMATION on the right.
Try this regex:
(\d{1,}\.\d{4})
Demo here: https://regex101.com/r/uJ1wU6/1
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
Is it possible to create a regular expression of a pattern X that is not enclosed by a pattern Y using preg_match in PHP?
for example, consider this string:
hello, i said <a>hello</a>
I want a regex that matches the first hello but not the second... I couldn't think of anything
Use negative look behind lookup:
(?<!<a>)hello
Description
Assuming your use case is a bit more complex then hello, i said <a>hello</a>; then if you where looking for all the hello in hello, i said <a>after arriving say hello</a> you might want to just capture the good and bad, then use some programming logic to process only the matches you're interested in.
This expression will capture all the <a>...</a> sub strings and all the hello strings. Since the undesirable substring is matched first if the desirable substring appears inside then it won't ever be included in the capture group 1.
<a>.*?<\/a>|\b(hello)\b
Example
Live example: http://ideone.com/jpcqSR
Sample Text
Chello said Hello, i said <a>after arriving say hello</a>
Code
$string = 'Chello said Hello, i said <a>after arriving say hello</a>';
$regex = '/<a>.*?<\/a>|\b(hello)\b/ims';
preg_match_all($regex, $string, $matches);
foreach($matches as $key=>$value){
if ($value[1]) {
echo $key . "=" . $value[0];
}
}
Output
Note the upper case H in hello shows that it was the desired substring.
0=Hello
I want to test a string to see it contains certain words.
i.e:
$string = "The rain in spain is certain as the dry on the plain is over and it is not clear";
preg_match('`\brain\b`',$string);
But that method only matches one word. How do I check for multiple words?
Something like:
preg_match_all('#\b(rain|dry|clear)\b#', $string, $matches);
preg_match('~\b(rain|dry|certain|clear)\b~i',$string);
You can use the pipe character (|) as an "or" in a regex.
If you just need to know if any of the words is present, use preg_match as above. If you need to match all the occurences of any of the words, use preg_match_all:
preg_match_all('~\b(rain|dry|certain|clear)\b~i', $string, $matches);
Then check the $matches variable.
http://php.net/manual/en/function.preg-match.php
"Do not use preg_match() if you only want to check if one string is contained in another string. Use strpos() or strstr() instead as they will be faster."
preg_match('\brain\b',$string, $matches);
var_dump($matches);