update picture into database table using php - php

I have an address table and one of the fields is an image blob. When I update a record through $POST and include an image, everything works. However if no image is included in $POST, I want to reuse the image that is already stored in the record. This is were im having problems. when I run the code below it does not update the image file. here's my code.
function UpdateRecordfromPost()
{
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
$FirstName = test_input($_POST['fname']);
$LastName = test_input($_POST['lname']);
$Address = test_input($_POST['address']);
$Town = test_input($_POST['town']);
$Postcode = test_input($_POST['pcode']);
$Phone = test_input($_POST['phone']);
$Email = test_input($_POST['email']);
$ID = ($_POST['idname']);
}
$mysqli = new mysqli( $GLOBALS['servername'], $GLOBALS['username'], $GLOBALS['password'], $GLOBALS['dbname']);
if ($mysqli->connect_error)
{
die("Connection failed: " . $mysqli->connect_error);
}
$image = GetimagefromPost(); //this function returns a image and seems to work
if ($image == "")
{
$image = Saveimaqgefile($ID);
}
$query = "UPDATE addressbook SET firstname='$FirstName',lastname='$LastName',street='$Address',town='$Town',PostCode='$Postcode',phone='$Phone',email='$Email',Photo='$image' WHERE id='$ID'";
if ($result = $mysqli->query($query))
{
echo "Updated record successfully";
}
else
{
echo "Error: " . $query . "<br>" . $mysqli->error;
}
$mysqli->close();
}
function Saveimaqgefile($file_id) {
$mysqli = new mysqli( $GLOBALS['servername'], $GLOBALS['username'], $GLOBALS['password'], $GLOBALS['dbname']);
if ($mysqli->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql= "SELECT * from ".$GLOBALS['dbname']. " WHERE id=".$file_id;
$result = $mysqli->query($sql);
if ($result->num_rows > 0)
{
$row=mysqli_fetch_array($result);
}
else { $row = "";}
$mysqli->close();
return base64_encode($row['Photo']);
}
This is my first question, sorry if i've done something wrong

You'd need conditional logic.
if (image was uploaded) {
mysqli_query('... update record with new image ...;);
} else {
mysqli_query('... update record WITHOUT image data ...');
}
For most other types of (small) data, you could do it in a single query, e.g.
UPDATE ... SET field=IF($newdata = '', field, $newdata)
but your image blob is likely to be HUGE, and you don't want to repeat it twice in the same query string.

Related

How can i get all the values in the query?

<?php
$mysqli = new mysqli("localhost", "root", "", "titan3d");
if (mysqli_connect_error()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$sdate = "";
$stime = "";
if(isset($_POST['sdate']))
{
$sdate = $_POST["sdate"];
}
if(isset($_POST['stime']))
{
$stime = $_POST["stime"];
}
$statement = $mysqli->prepare("SELECT bookedseat FROM bookings WHERE sdate = ? AND stime = ?");{
$statement->bind_param("si", $sdate, $stime);
if (!$statement->execute()) {
trigger_error('Error executing MySQL query: ' . $statement->error);
}
$statement->bind_result($book);
$statement->fetch();
printf($book);
//header('Location: http://localhost/My%20Project/seats.html');
$statement->close();
}
$mysqli->close();
?>
This is my php file made to get the data from a form and make a query and then display the results.
When executed,the php works perfectly.
But it only displays the first value in the query.
Why is it?
How can I display all the values in my query?
You need to use $stmt->fetch() in a while loop, you can then iterate over each the returned row.
while ($stmt->fetch()) {
// $book will have the value of bookedseat for the current row
}

Codeigniter XML Datafeed to Multiple (MYSQL Tables)

goodness.. it's been a quite a headache for me.
I'm trying to get variable SQL1, SQL2 and SQL3 to update different mysql tables.. but how on earth will SQL2 and SQL3's "product_id" fields, correlate with SQL1?
See 'id' in the insert sections in SQL2 and SQL3.. i'm not sure how to replace and grab this generated data into this sections without making more ugly code.
Also, if any of you have any idea how to make this easier, please help a fellow out here.. this looks pretty dirty to me.. surely there are better ways :(
// DB Settings
$servername = "localhost";
$username = "user";
$password = "pass";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Load data from XML file
$xml = simplexml_load_file("Datafeed.xml");
// Capture XML Data
foreach($xml->children() as $product) {
// Change stock wording
$stock = $product->stock;
if ($stock == 'yes') {
$stock = 'on';
} else {
$stock = 'off'; }
// Convert XML data and insert into MYSQL
$sql = "INSERT INTO testshop_products (product_id, product_name, product_type, product_price, product_status) VALUES ("echo $product->code;", "echo $product->cat;", "echo $product->price;","echo $stock;")";
$sql2 = "INSERT INTO testshop_product_details (product_id, product_color, product_image, details_status) VALUES ('id', "Generating...", "echo $product->img;","echo $stock;")";
$sql3 = "INSERT INTO testshop_spesifications (product_id, specs_meta, specs_details, specs_slug, specs_status) VALUES ('id', General, "echo $product->img;", general, "echo $stock;")";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
if ($conn->query($sql2) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
if ($conn->query($sql3) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
}
write store procedure and inset all records and all table it will find.
store procedure like this
CREATE PROCEDURE `addJobApplicant`(IN XMLINPUT
text, OUT vresult VARCHAR(100))
BEGIN
DECLARE iCounter INT DEFAULT 1;
DECLARE maxCount INT;
SET vcompID=ExtractValue(XMLINPUT, '/ROOT/HEADER/COMPANYID[$iCounter]');
SET vjpID=ExtractValue(XMLINPUT, '/ROOT/HEADER/JOBID[$iCounter]');
insert command here
SET vresult = 'Successfully Inserted';
end

How can I use a for loop to insert data from a csv table to a sql database?

This is the sample csv file I'm using:
Column1,Column2,Column3
data1,data2,data3
data1,data2,data3
data1,data2,data3
data1,data2,data3
The purpose of my program is to insert this table into a php file via command line and insert the data into an SQL database. I'm using this project as a way of learning how to use MySql.
A csv file is taken and the data is then converted into an array or arrays. A database is then created and the data is supposed to be inserted into the table.
Instead of my data being inserted, I get only one row with null values.
<?php
/**
* Created by PhpStorm.
* User:
* Date: 6/16/2017
* Time: 11:32 AM
*/
$servername = "localhost";
$username = "pop-user";
$password = "pop-pw";
$database = 'popdb';
parse_str(implode('&', array_slice($argv, 1)), $_GET);
$file = array_map('str_getcsv', file($argv[1]));
// connecting to MySQL
$link = mysqli_connect($servername,$username,$password);
// check if connection completed
if ($link->connect_error) {
die("Connection failed: ". $link->connect_error);
}
//creating database
printf("Creating database...\n");
$dbcheck = mysqli_select_db($link, $database);
// if database doesn't exist, then one will be created
if (!$dbcheck) {
$sql = 'CREATE DATABASE '. $database;
if (mysqli_query($link, $sql)) {
echo "Database ". $database ." created\n";
}
else {
echo "Failed to create database:\n";
echo $link->error."\n";
}
}
printf("Creating table...");
//creating table to hold information
$sql = 'USE '. $database. ';';
printf("\r\n");
mysqli_query($link,$sql);
$sql2 = "CREATE TABLE popCensus (";
foreach ($file[0] as $rows) {
if ($rows != end($file[0]))
$sql2 .= "{$rows} varchar(33), ";
else
$sql2 .= "{$rows} varchar(33)";
}
$sql2 .= ");";
echo $sql2;
printf("\r\n");
mysqli_query($link,$sql2);
printf("Inserting data into table...\n");
$cnt = 1;
$sql3 = "";
//Not inserting data
foreach ( $file as $file[$cnt]) {
$sql3 = "INSERT INTO popcensus VALUES ( ";
foreach ($file[$cnt] as $rows) {
if ($rows != end($file[$cnt]))
$sql3 .= "{$rows} , ";
else
$sql3 .= "{$rows});";
}
printf($sql3);
printf("\n");
mysqli_query($link, $sql3);
$cnt++;
printf("cnt: ". $cnt."\n");
$sql3 = "";
}
printf("\nDone\n");
mysqli_close($link);
?>
edit: I'm able to parse the information into an arrays of arrays. the problem I'm having is trying to insert them into a table afterwards.
you need to use prepared statement inside the loop
Try checking the query for an error result inside the foreach loop.
if (false === mysqli_query($link, $sql3)) {
throw new Exception(mysqli_error($link));
}
Beyond that, you should really be using a prepare statement.

Warning: mysqli_query(): Couldn't fetch mysqli in my code

I know this question has been asked many times , I tried lot of other answers but it didn't work for me
Here is my class
<?php
class saveexceltodb
{
var $inputFileName;
var $tableName;
var $conn;
var $allDataInSheet;
var $arrayCount;
/**
* Create a new PHPExcel with one Worksheet
*/
public function __construct($table=0)
{
$this->initiatedb();
}
private function initiatedb(){
//var_dump($allDataInSheet);
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "xyx";
// Create connection
$this->conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$this->conn) {
die("Connection failed: " . mysqli_connect_error());
}
}
public function updateIntermidiate(){
$allocationeventwise=array();
mysqli_query($this->conn,"DELETE FROM `allocationeventwise` WHERE 1");
$sql = "INSERT INTO `allocationeventwise` (`empid`, `event1`, `event2`, `event3`, `event4`, `event5` `event6`, `event7`) VALUES ";
$result = mysqli_query($this->conn, "SELECT usdeal.empid , usdeal.event1 , usdeal.event2, usdeal.event3, usdeal.event4, usdeal.event5, usdeal.event6, usdeal.event7 , salary.salary from usdeal INNER JOIN salary ON usdeal.empid = salary.empid where usdeal.allocated=0");
$i=0;
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$i++;
$totaleventDays = $row["event1"]+$row["event2"]+$row["event3"]+$row["event4"]+$row["event5"]+$row["event6"]+$row["event7"];
$allocationeventwise[$row["empid"]]['event1']=($row['salary']/$totaleventDays)*$row["event1"];
$allocationeventwise[$row["empid"]]['event2']=($row['salary']/$totaleventDays)*$row["event2"];
$allocationeventwise[$row["empid"]]['event3']=($row['salary']/$totaleventDays)*$row["event3"];
$allocationeventwise[$row["empid"]]['event4']=($row['salary']/$totaleventDays)*$row["event4"];
$allocationeventwise[$row["empid"]]['event5']=($row['salary']/$totaleventDays)*$row["event5"];
$allocationeventwise[$row["empid"]]['event6']=($row['salary']/$totaleventDays)*$row["event6"];
$allocationeventwise[$row["empid"]]['event7']=($row['salary']/$totaleventDays)*$row["event7"];
$sql .='("'.$row["empid"].'",
'.$allocationeventwise[$row["empid"]]["event1"].',
'.$allocationeventwise[$row["empid"]]["event2"].',
'.$allocationeventwise[$row["empid"]]["event3"].',
'.$allocationeventwise[$row["empid"]]["event4"].',
'.$allocationeventwise[$row["empid"]]["event5"].',
'.$allocationeventwise[$row["empid"]]["event6"].',
'.$allocationeventwise[$row["empid"]]["event7"].',)';
if($i<mysqli_num_rows($result))
$sql .=",";
else
$sql .=";";
}
echo $sql;
if (mysqli_query($this->conn, $sql)) {
echo "New record created successfully<br/>";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($this->conn);
}
} else {
echo "0 results";
}
}
}
When I use it like this
include('saveexceltodb.php');
$obj = new saveexceltodb(0);
$obj->updateIntermidiate();
I get following error .
Warning: mysqli_query(): Couldn't fetch mysqli in C:\xampp\htdocs\import-excel\saveexceltodb.php
You should follow below steps
Check database connection
Check query syntax
You have to pass connection object in mysqli_query function in you case it is ' $this->conn '
Hope, It may help you.

Change code to link mySQL into a function

I'm new to php. I have this piece of code:
<?php
if (!isset($_GET['id'])) {
die("missing query parameter");
}
$id = intval($_GET['id']);
if ($id === '') {
die("Invalid query parameter");
}
$db = mysql_connect("localhost", "root", "usbw");
$sdb = mysql_select_db("test", $db);
$sql = "SELECT * FROM config WHERE id=$id";
$mq = mysql_query($sql) or die("not working query");
$row = mysql_fetch_array($mq);
?>
And from this code, I want to make a function, but how?
What I'm trying to do is linking my MySQL database to my PHP code, and I also try to use the GET[id] to auto change my page if a change my id.
This piece of code does work, but I want to change it into a function. But I don't know how to start.
Here's an example of a function around your query, mind you it's just an example, as there are many improvements to make.
Such as not using the mysql_* api and moving towards PDO or mysqli_*
But it should be enough to get you started
<?php
// your if logic stays unchanged
$db=mysql_connect("localhost","root","usbw");
$sdb=mysql_select_db("test",$db);
function getConfig($id,$db){
$sql="SELECT * FROM config WHERE id=$id";
$mq=mysql_query($sql);
if ($mq) {
return mysql_fetch_array($mq);
}
else {
return false;
}
}
$results = getConfig($id,$db);
if ($results==false) {
print "the query failed";
}
else var_dump($results);
You can make a file named db.php including some common db functions so you will be able to use them easier:
<?php
function db_connection() {
//SERVER, USER, MY_PASSWORD, MY_DATABASE are constants
$connection = mysqli_connect(SERVER, USER, MY_PASSWORD, MY_DATABASE);
mysqli_set_charset($connection, 'utf8');
if (!$connection) {
die("Database connection failed: " . mysqli_error());
}
return $connection;
}
function db_selection() {
$db_select = mysqli_select_db(MY_DATABASE, db_connection());
if (!$db_select) {
die("Database selection failed: " . mysqli_error());
}
return $db_select;
}
function confirm_query($connection, $result_set) {
if (!$result_set) {
die("Database error: " . mysqli_error($connection));
}
}
function q($connection, $query) {
$result = mysqli_query($connection, $query);
confirm_query($connection, $result);
return $result;
}
?>
Then, you can have your code in some other files:
<?php
require_once('db.php'); //This file is required
$id = $_GET['id']; //Shorthand the $_GET['id'] variable
if (!isset($id)) {
die("missing query parameter");
}
if ( filter_var($id, FILTER_VALIDATE_INT) === false) ) {
die("Invalid query parameter");
}
$sql = "SELECT * FROM config WHERE id = '$id'";
$result = q($connection, $sql);
while ($row = mysqli_fetch_array($result)) {
//Do something
}
?>
Try not to use mysql_* functions because they are deprecated. Use mysqli_* or even better try to learn about prepared statements or PDO.

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