query Fetch data from multiple tables MySQL - php

i have a page on which there is a form, in which there are two radio buttons, on selected the on of the related buttons, it's related content will be shown on the form.
<tr class="text">
<td colspan="4" valign="top" bgcolor="f2f2f2">
<?php
$srl=mysql_query("select * from module ORDER BY module_id ASC");
while($rows=mysql_fetch_array($srl))
{ ?>
<input type="radio" name="module" value=<?php echo $rows[module_id] ?>><?php echo $rows[module_name] ?>
<?php
}
?>
</td>
</tr>
</tbody>
</table>
<tr class="text">
<td colspan="6">
<div id="items_list"></div>
</tr>
and i have write this jquery for api calls.
<script type="text/javascript">
$(function() {
$("module").change(function() {
var module_id = $(this);
var dataString = 'module_id='+ module_id.val();
alert(dataString);
$("#items_list").html("");
if(module_id.val()=='')
{
alert("select stock type");
}
else {
$.ajax({
type: "POST",
url: "ajax/request_fetch_items.php",
data: dataString,
cache: false,
success: function(){
$("#items_list").html( html );
},
error:function (xhr, ajaxOptions, thrownError){
//On error, we alert user
alert(thrownError);
}
});
}
return false;
});
});
</script>
but nothing happens when i select any radio button, neither it shows the alert in jquery.
what i want is whenever a radio button is selected, its value is passed via ajax call, the the remaining html content will be load into the next row.
On inepcting the radio buttons it shows following code,
<input type="radio" name="module" value="1">Stationary
<input type="radio" name="module" value="2">Inventory

Your jQuery selector $("module") is targeting <module> html tags, just change it to $("input[name=module]:radio") so it targets <input> elements of type radio named module.
https://jsfiddle.net/eh6c5wjb/

Related

How to update data directly in row?

I have a problem with my code. I have a php script where i, in a while, i write a table in html with html name and html value attr with the data of database, like the printscreen above
My table was assembled with input inside the TDs, to be able to "edit" directly in the table, without MODAL or redirection
</thead>
<tbody id="corpoTabela">
<?php
$i = 1;
while ($row = mysqli_fetch_array($result)) :;
?>
<tr>
<form name="presencaForm" id="presencaForm" method="POST">
<input type="hidden" id="idcrmmedico" name="idcrmmedico" value="<?php echo $row['id']; ?>"></input>
See that the opening of the form tag is inside the while, that is, for each row of the table, for each TR, I have a form (all with the same name)
The end of the form tag still inside php while. The Button, who receives the ID referring to the record in the DB, has the same name of the form
<td><button id="d" name="presencaForm" value="<?php echo $row['id'] ?>" class="btn btn-sm btn-info">Atualizar</a></td>
<td>
<button type="submit" id="" name="deletamedico" class="btn btn-sm btn-danger">Excluir</button>
</td>
</form>
</tr>
<?php
endwhile;
}
?>
</tbody>
This is my ajax script, which updates the data in the database without refreshing the page and returning me a success message.
<script>
$(document).ready(function() {
$('#presencaForm').on('submit', function(event) {
event.preventDefault();
$("#alert").css('display', 'none');
console.log("Botão Clicado!");
$.ajax({
url: "DAO/medico/update.php",
method: "POST",
data: $(this).serialize(),
dataType: "json",
success: function(data) {
if (data[0] == true) {
$("#success").html('Médico ' + data[1] + ' atualizado com sucesso');
$("#success").show();
setTimeout(function() {
$("#success").hide();
}, 5000);
}
}
})
});
});
</script>
The problem is that if i try to refresh the second line, the page just refreshes.
I used the code below to check, and I saw that all buttons return only the first record in the LOG.
Is there any way to update the data as I want, right in the table?
$(document).ready(function() {
$("button[name='presencaForm']").on("click", function(event) {
event.preventDefault();
for (var i = 1; i < document.getElementById("dataTable").rows.length; i++) {
console.log($('#idcrmmedico').val());
}
var val = document.getElementById('d').value;
var x = document.getElementById("dataTable").rows.length;
});
id is unique,if you want to control a group of form,you can use class.
For example:
<form class="presencaForm" method="POST">
Then in your javascript:
$('.presencaForm').on('submit', function(event) {

How to use a value imported from a database

Hey Everyone here is my question .
The code below gets data from my database and displays it both in an input field and a button. I want it to be in such a way that if i click the button it should get the value(which is imported from the db).But the problem i am facing is that all the inputs and buttons have the same ids so it only captures the value of the first button(or so i think). How can i make it in such a way that for every button i click it should have its own separate value.
<?php
$dbcon=mysqli_connect("localhost","root","");
mysqli_select_db($dbcon,"codex");
require('config/server.php');
?>
<table class="table table-striped">
<th>ID</th>
<?php
$view_users_query="select * from users";//select query for viewing
users.
$run=mysqli_query($dbcon,$view_users_query);//here run the sql
query.
while($row=mysqli_fetch_array($run))//while look to fetch the result
and store in a array $row.
{
?>
<!--here showing results in the table -->
<form id="loginForm" method="" action="" novalidate>
<tr>
<div class="panel2">
<main class="content">
<td><input name="hanis" id="hanis" type="text" value="<?php echo
$row['email']?>" autofocus /></td>
<td><button type="button" class="btn btn-success btn-block"
name="hanis" id="hanis" onclick="hanisdata()" value="<?php echo
$row['email']?>" ><?php echo $row['email']?></button><</td>
</main></div>
</div>
</div>
</form>
<?php } ?>
</tr>
<script type="text/javascript">
function hanisdata() {
var hanis=$("hanis").val();
alert(hanis);
// AJAX code to send data to php file.
$.ajax({
type: "POST",
url: "hanis.php",
data: {hanis:hanis},
dataType: "JSON",
success: function(data) {
$("#message").html(data);
$("p").addClass("alert alert-success");
},
error: function(err) {
alert(err);
}
});
}
</script>
NOTE :- Don't use same id for elements
You can get values by passing this with onclick function like onclick="hanisdata(this)"
Example
<button type="button" class="btn btn-success btn-block"
name="hanis" id="hanis" onclick="hanisdata(this)" value="<?php echo
$row['email']?>" ><?php echo $row['email']?></button>
Then you can get specific element in js and then can find parent and search for input field in that like below example.
JS CODE
<script type="text/javascript">
function hanisdata(el) {
var hanis=$(el).parent().find("input").val();
alert(hanis);
// AJAX code to send data to php file.
$.ajax({
type: "POST",
url: "hanis.php",
data: {hanis:hanis},
dataType: "JSON",
success: function(data) {
$("#message").html(data);
$("p").addClass("alert alert-success");
},
error: function(err) {
alert(err);
}
});
}
</script>

Toggle Switch in ajax

I have written below code in PHP + Ajax
<table>
<tr><td data-id="1" onclick="showData(event);">ABC</td>
<tr style='display:none' data-fold='1'><td>ABC - 01</td>
<tr><td data-id="2" onclick="showData(event);">PQR</td>
<tr style='display:none' data-fold='2'><td>PQR- 01</td>
</table>
I need to show data-fold "tr" when someone click on data-id with respective id, that is when I click on data-id 1, then data-fold 1 should be visible.
Also, the content in data-fold is coming from AJAX..
Below is my AJAX code:
function showData(event){
var rowId = $(event.currentTarget).attr('data-id');
$.ajax({
type: "POST",
url: "ajax.php", //
data: 'type=viewOrder&rowId='+rowId,
success: function(msg){
$("tr").each(function(){
childId = $(this).attr('data-fold');
if(childId == rowId) {
$(this).toggle("slow");
$(this).html(msg);
}
});
},
error: function(){
alert("failure");
}
});
}
My code is working fine, but I need to close all other tr expect the one I clicked.

multiple select with checkbox in php

i am making a website in which i am to embbed the functionality of delete using multiple checkbox. here is my code. my problem is
1. Ajax call is not working.
2. how can i make search from database for array .
<?php
if(isset($_POST['Delete']))
{
$array=$_POST['check_box'];
}
?>
<form method="post" id="form">
<table width="200" border="1">
<tr>
<td>select</td>
<td>NAme</td>
<td>Action</td>
</tr>
<?php
while($selectnumberarr=mysql_fetch_array($selectnumber))
{
?>
<tr>
<td><input type="checkbox" name="check_box[]" class="check_box" id="<?php $selectnumberarr[0]; ?>" /> </td>
<td><?php echo $selectnumberarr[1]; ?></td>
</tr>
<?php
}?>
<input type="submit" name="Delete" id="delete">
</table>
</form>
and below is my ajax and javascript code.
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#delete').click(function() {
$.ajax({
type: "POST",
url: "checkbox.php",
data: $('#form').serialize(),
cache: false,
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
any help would be appriciated
your code is almost correct. You need to remove `onChange="show()" for input checkbox, because if you have jquery then you don't need to put events on HTML elements.
Use jquery 'on' method for compatibility for latest php library.
Replace your jquery code with following jquery code :-
<script>
$(document).ready(function(){
$('#delete').on('click',function()
{
var cat_id = $('.check_box:checked').map(function() {
return this.id;
}).get().join(',');
console.log(cat_id);
$.ajax({
type: "POST",
url: "checkbox.php",
data: { "kw ":cat_id },
datatype:'json',
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
Use ".check_box" instead of "element" in jquery to prevent checks for all checkboxes, instead of desired ones.
Hope it helps.
Why you don't use an array for sending the checkboxes like:
HTML part:
<?php
if (isset($_POST['check_box'])) {
var_dump($_POST['check_box']);
echo "ajax call is working";
}
?>
<form id="form">
<table width="200" border="1">
<tr>
<td>select</td>
<td>NAme</td>
<td>Action</td>
</tr>
<?php
while ($selectnumberarr = mysql_fetch_array($selectnumber)) {
?>
<tr>
<td><input type="checkbox" name="check_box[]" class="check_box" value="<?php echo $selectnumberarr[0]; ?>" /> </td>
<td><?php echo $selectnumberarr[1]; ?></td>
</tr>
<?php
}
?>
</table>
<input type="button"name="delete" id="delete" value="Delete" />
</form>
JQuery part:
<script type="text/javascript">
$(document).ready(function(){
$('#delete').click(function() {
$.ajax({
type: "POST",
url: "checkbox.php",
data: $('#form').serialize(),
cache: false,
success: function(html)
{
alert("true");
}
});//end ajax
});
});
</script>
So you can easily get an array of the selected checkboxes in php with:
$idsArray = $_POST["check_box"];
this looks now like:
array(
"1", "2","etc.."
);
so this array contains all the ids of the selected checkboxes for delete.

Working with checkbox which is creating by Ajax

I am working with ajax project.
I have a form of user in with name, address , postcode .
on entering the name, address or postcode the matching rows is shown by ajax file in .
so on select the checkbox i want to do some further activity.
my html code is
Address : <input type="text" name="user_name" id="from_location" value="" class="in_form" />
<div id="user"></div>
and jQuery code is
$.ajax({
url: "ajax_user.php",
data: {
address: address,
},
dataType: "html",
type: "POST",
success: function(result){
$("#user").append(result);
}
})
}
and ajax user php is
$sql= "SELECT * FROM instructor_mst WHERE sex='$sex' AND car_type='$car_type' AND address Like '%$address%' ";
if (!$sqli=mysql_query($sql)){
echo mysql_error();
}
$num_rows= mysql_num_rows($sqli);
if($num_rows != 0)
{?>
<table border="0" class="form_ins" >
<?
while ($row = mysql_fetch_array($sqli))
{
?>
<tr>
<td>
</td>
<td>
Name
</td>
<td>
Address
</td>
</tr>
<tr>
<td>
<input type="checkbox" name="select" value"<?php echo $row['id'];?>">
</td>
<td>
<?php echo $row['name'];?>
</td>
<td>
<?php echo $row['address'];?>
</td>
</tr>
</table
<?}
in result i got like
checkbox | user name | address
now on selecting the checkbox i want to submit for other activity....
I am not getting how can i do this...All answer will be appreicieted
As your checkbox being dynamically added -
$(document).on('change','input[type=checkbox]',function(){
if($(this).is(':checked')){
// do something
}
});
Or if you have an ID of your checkbox -
$(document).on('change','#checkBoxID',function(){
if($(this).is(':checked')){
// do something
}
});
you need to delegate the click event using on for dynamically added element which is checkbox in your case
$(document).on('click','input[name="select"]',function(){
//this is called when you select the checkbox
//do your stuff
})
or delegating it to the closest static element
$('#user').on('click','input[name="select"]',function(){
//dou your stuff
});
updated
checkbox might have multiple values so to get all the values that is checked you need to loop through the values or use map()
try this
$('#user').on('click','input[name="select"]',function(){
var selectedValue = $("input[name='select']:checked").map(function(n){
return this.value;
});
console.log(selectedValue ); //this will print array in console.
alert(seletedValue.join(',')); //this will alert all values ,comma seperated
});

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