Now I have one table and copy this table into another table and this work... But now I have one new array in new table and I need to save now date... How to connect this 2 queries into one..
$sql = "INSERT INTO $tbl_name2(name, money) SELECT name, money FROM $tbl_name WHERE id='$idd'";
$sql ="INSERT INTO $tbl_name2(time)VALUES('$time')";
$result = mysql_query($sql);
Simply add the parameter to your first query.
$sql = "INSERT INTO $tbl_name2(name, moneytime) SELECT name, money,$time FROM $tbl_name WHERE id='$idd'";
But you shouldn't use the mysql_* API because these is depricated. And also you should use prepared statement. TThese are much more safty and readable.
If I am understanding it correctly this is what you need.
$sql = "INSERT INTO $tbl_name2(name, money, time) SELECT name, money, '".$time."' FROM $tbl_name WHERE id='$idd'";
$result = mysql_query($sql);
Related
I've been trying to get this INSERT to work correctly, so I worked through the undefined variable and index problems and now I think I am nearly there.
Below is the code:
<?php
session_start();
require "../dbconn.php";
$username = $_SESSION['username'];
$query1 = "SELECT user_table.user_id FROM user_table WHERE user_table.username ='".$username."'";
$query2 = "SELECT department.department_id FROM department, user_table, inventory
WHERE user_table.user_id = department.user_id
AND department.department_id = inventory.department_id";
//Copy the variables that the form placed in the URL
//into these three variables
$item_id = NULL;
$category = $_GET['category'];
$item_name = $_GET['item_name'];
$item_description = $_GET['item_description'];
$item_quantity = $_GET['quantity'];
$item_quality = $_GET['quality'];
$item_status = NULL;
$order_date = $_GET['order_date'];
$invoice_attachment = NULL;
$edit_url = 'Edit';
$ordered_by = $username;
$user_id = mysql_query($query1) or die(mysql_error());
$department_id = mysql_query($query2) or die(mysql_error());
$price = $_GET['price'];
$vat = $_GET['vat%'];
$vat_amount = $_GET['vat_amount'];
$create_date = date("D M d, Y G:i");
$change_date = NULL;
//set up the query using the values that were passed via the URL from the form
$query2 = mysql_query("INSERT INTO inventory (item_id, category, item_name, item_description, item_quantity, item_quality, item_status, order_date,
invoice_attachment, edit_url, ordered_by, user_id, department_id, price, vat, vat_amount, create_date, change_date VALUES(
'".$item_id."',
'".$category."',
'".$item_name."',
'".$item_description."',
'".$item_quantity."',
'".$item_quality."',
'".$item_status."',
'".$order_date."',
'".$invoice_attachment."',
'".$edit_url."',
'".$ordered_by."',
'".$user_id."',
'".$department_id."',
'".$price."',
'".$vat."',
'".$vat_amount."',
'".$create_date."',
'".$change_date."')")
or die("Error: ".mysql_error());
header( 'Location:../myorders.php');
?>
Error:
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VALUES( '', 'adasd', 'dsadsa', 'dsad', 'sadsad', '' at line 2
Could anyone please let me know where I am going wrong? :(
Been staring at this for 3-5 hours already :(
You are not actually trying to insert any data into your table. You only craft and assign the query in string form to a variable. You need to use the function mysql_query to actually run the code.
As pointed out you will also have to specify the columns you are inserting data into in the MySQL query if you don't supply data for every column (in the correct order). Here you can look at the MySQL insert syntax.
I would also urge you to look into using the MySQLi or the MySQL PDO extensions for communicating with your MySQL database since the MySQL extension is deprecated. Look here for additional information and comparisons.
Here, you only assign the values to the $query var:
$query = "INSERT INTO inventory VALUES (
'".$item_id."',
'".$category."',
'".$item_name."',
'".$item_description."',
'".$quantity."',
'".$quality."',
'".$item_status."',
'".$order_date."',
'".$invoice_attachment."',
'".$edit_url."',
'".$ordered_by."',
'".$price."',
'".$vat."',
'".$vat_amount."',
'".$create_date."',
'".$change_date."')"
or die("Error: ".mysql_error());
You do not actually run the query.
try:
$query = mysql_query("INSERT INTO inventory (column_name1, column_name 2, column_name3 ... the column name for each field you insert) VALUES (
'".$item_id."',
'".$category."',
'".$item_name."',
'".$item_description."',
'".$quantity."',
'".$quality."',
'".$item_status."',
'".$order_date."',
'".$invoice_attachment."',
'".$edit_url."',
'".$ordered_by."',
'".$price."',
'".$vat."',
'".$vat_amount."',
'".$create_date."',
'".$change_date."')")
or die("Error: ".mysql_error());
Also, you should use mysqli_* or any other PDO as the mysql_* functions are deprecated
If you are not inserting in all columns you need to specify the columns you are going to insert. Like this:
INSERT INTO Table(Column1, Column6) VALUES (Value1, Value6)
You are missing the column names in your INSERT
I want to execute these queries
$q1 = "INSERT INTO t1 (id,desc) VALUES (1,'desc');" <br>
$q2 = "SET #last_id = LAST_INSERT_ID();" <br>
$q3 = "INSERT INTO t2 (parentid,desc) VALUES (#last_id, 'somedesc');"<br>
Will this work correctly 3 mysqli_query something like this?
$res = mysqli_query($q1);
$res2 = mysqli_query($q2);
$res3 = mysqli_query($q3);
To start, desc is a MySQL reserved word
http://dev.mysql.com/doc/refman/5.5/en/reserved-words.html
and must be wrapped in backticks if you're going to decide on using it, without renaming it to something else than desc, say description for instance.
Therefore, you will need to change it to the following, assuming your DB connection is established, and using $con as an example, which you haven't shown us what your DB connection is.
$q1 = "INSERT INTO t1 (id,`desc`) VALUES (1,'desc')";
$q2 = "SET #last_id = LAST_INSERT_ID()";
$q3 = "INSERT INTO t2 (parentid,`desc`) VALUES (#last_id, 'somedesc')";
minus all of your <br> tags, since you are inside PHP, unless that wasn't part of your code, but in trying to format your code in your question.
Sidenote: Your semi-colons were misplaced.
and passing DB connection to your queries:
$res = mysqli_query($con,$q1);
$res2 = mysqli_query($con,$q2);
$res3 = mysqli_query($con,$q3);
Plus, adding or die(mysqli_error($con)) to mysqli_query() to check for possible errors in your queries.
I am trying to insert values into a database table, a row is inserted but blank no values are inserted. Only the order_id which is the primary key with auto increment increase.
php code:
<?php
$user_get = mysql_query("SELECT * FROM users");
while($row_user = mysql_fetch_assoc($user_get)){
if($row_user['username'] == $_SESSION['username']){
$row_user['first_name'] = $res1;
$row_user['last_name'] = $res2;
$store_order ="INSERT INTO oko (user, product) VALUES ('$res1', '$res2')";
mysql_query($store_order);
}
}
?>
Your assignments are backwards. I think you meant to:
$res1 = $row_user['first_name'];
$res2 = $row_user['last_name'];
Don't you mean:
$res1 = $row_user['first_name'];
$res2 = $row_user['last_name'];
You could also update the SELECT to have a WHERE clause that checks $_SESSION['username'].
You could also just do an INSERT/SELECT:
INSERT INTO oko (user, product)
SELECT
first_name, last_name
FROM
users
WHERE
username = '$_SESSION["username"]'
Your code is vulnerable to injection. You should use properly parameterized queries with PDO/mysqli
Here is an easy one, but can't figure out why is not working. Need another set of eyes.
3 queries. 1 insert, 1 select, then 1 insert again. My select query is supposed to grab a value from the data recently inserted, and then store that value in a variable, then run the second insert for another table. Well, everything works, except the select. I even tryied to add a mysql_query("COMMIT",$conn) and still nothing.
Any help is very appreciated.
Thanks!!!
$customerQ = "INSERT INTO
customerData(fname, mname, lname, email, homePhone, cellphone, address,
city, county, state, zip, gascompany, eleccompany, addedBy)
VALUES('$fname', '$mname', '$lname', '$emailCustomer', '$hphone', '$cellphone',
'$address', '$city', '$county', '$state', '$zip', '$gas', '$electric',
'$userName'
) ";
//General WO# calculation
$calcWO = "SELECT
auditRequest.workOrderNum
FROM
auditRequest
ORDER BY
auditRequest.workOrderNum DESC
LIMIT 1
";
//General Customer number calculation. For the Work Order Insert
$calc = "SELECT
customerData.custnumber
FROM
customerData
WHERE
fname = '$fname' and
mname = '$mname' and
lname = '$lname'
ORDER BY
customerData.custnumber DESC
LIMIT 1
";
//Customer Information Insert (from Insert Query)
$resultCustQ = mysql_query($customerQ, $connection);
mysql_query("COMMIT", $connection); //make sure to commit to be able to query new records
// Test the query
if(!$resultCustQ) die ("error 1". mysql_error());
//Customer Information Insert (from Insert Query)
$resultCustQ = mysql_query($customerQ, $connection);
mysql_query("COMMIT", $connection); //make sure to commit to be able to query new records
// Test the query
if(!$resultCustQ) die ("error 1". mysql_error());
//Calculate new customer number
$calc_result = mysql_query($calc, $connection);
// Test the query
if(!$calc_result) die ("error 1". mysql_error());
$row=mysql_fetch_array($calc_result);
$custnum = $row['custnumber']; // This is the new Customer.
//Work Order Information (run SQL Insert)
$resultWOQ = mysql_query($workOrderQ, $connection);
// Test the query
if(!$resultWOQ) die ("error 1". mysql_error());
I would avoid the crutch of INSERT followed by SELECT to find the inserted record altogether and use MySQL's ability to return the ID of the most recently inserted row (provided your table as an AUTO INCREMENT primary key) via PHP's mysql_insert_id, also available through PDO via lastInsertId.
Can I get from PHP a value back like the new id from the row I've just added to the database or should I make a SELECT to retrieve it?
<?php
$sql = "INSERT INTO my_table (column_1, column_2) VALUES ('hello', 'ciao')";
$res = mysql_query ($sql) or die (mysql_error ());
$sql = "SELECT column_id FROM my_table WHERE column_1 = 'hello'";
$res = mysql_query ($sql) or die (mysql_error ());
$row = mysql_fetch_assoc ($res);
$id = $row["column_id"];
print "my id is = $id";
?>
Use this: http://php.net/manual/en/function.mysql-insert-id.php
Selecting can be dangerous because an auto-increment often means that records may not otherwise be unique, and therefore not uniquely selectable without the id.
The proper way of getting the id is via mysql_insert_id(), as others have stated. The reason for this is that you may have other inserts taking place immediately following yours, and simply requesting the last id is not guaranteed to return the id that you expected.
$result = mysql_query("INSERT INTO tableName (col1) VALUES ('foo')");
print mysql_insert_id();
There is builtin support for it, mysql_insert_id() or something.