update database record in while loop php - php

I am trying to develop a simple page in php to update attendance days.I have set the query to display the records from db and added a check box with data displayed from db.I want to update the specific record of db on which check box is checked.i want to update the the attendance column with 1 to existing value.for this i just tried written code to display the data from db and added a check box but dnt know to update the record where check box is checked on submit button.here is my initial code.any one help
<?php
require_once("../db/db_connect.php");
$db = new DB_CONNECT();
$sql = "SELECT cv_id, cd_id, cv_fomfeeback FROM candidateverification;";
$res = pg_query($sql) or die ($sql);
// output data of each row
while($row = pg_fetch_row($res)){
echo "cd id: " . $row[0]. " cv id: " . $row[1]. " atn: " . $row[2]. "<input type='checkbox' value='1'/> <br>";
}
?>
<html lang="en">
<head>
<body>
<input type="button" action="update" value="Submit"/>
</body>
</html>
I want to update cv_fomfeeback column with +1 if check box is checked.

First you need to name your checkbox. You must do this in a way, so that you get all the checkboxes (-> array) and know the row id of the checkes boxes (-> associative array).
Your checkbox could look like this:
echo "<input type=\"checkbox" name=\"boxes[{$row[0]}]\" value=\"1\">";
On the page that is called after submit has been done (see the comment of #TheNAkos) you will find all checked boxes in the associative array accessible via
$_POST["boxes"]
From there you need to loop through the array and update the rows accordingly.
I will not post a complete example, but those hints should help you find the solution by yourself.

Related

How to INSERT multiple rows with multiple values, but only for items that have checkboxes ticked next to them

I am coding a discography tool for a music database.
Artists are able to insert tracks, singles, EPs, and albums all into separate tables on the database.
Having tracks be in their own separate table allows the same tracks to be attached to multiple singles, EPs and albums while only requiring there to be one record for that track in the database.
Which means individual track pages can have an automatically generated list of links back to the Singles, EPs and albums that they appear on. Making navigating the database through the website a much smoother experience.
I have come to the point where I am coding a tool to attach any existing tracks in the database for a given artist onto an album page.
I am using another table in the database called 'trackconnections' to create the relational links between the track ids from the track table and the album id from the album table, with an additional column called albumtracknum available to be able to output the tracks in the right order when queried on the album page.
The code for the tool is behind a button labelled 'Attach existing track(s) to album'. The code for this tool is as follows:
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "includes/db_connect.pdo.php";
$artistid = $_POST["artistid"];
$albumid = $_POST["albumid"];
echo '<strong>Select each track you would like to add to this album below and type in the track number you want it to have on the album in the box underneith the name of each selected track.</strong><br><br>';
$stmt = $pdo->query("SELECT * FROM track WHERE artist_id = '$artistid'
order by trackname");
while ($row = $stmt->fetch())
{
echo '<form action="includes/attachexistingtracktoalbum.inc.php" method = "post">';
echo '<div class="checkbox">';
echo '<label>';
echo "<input type='checkbox' name='trackid[]' value='".$row['id']."' />";
echo '<span class="cr"><i class="cr-icon glyphicon glyphicon-ok"></i></span>';
echo ' '.$row['trackname'];
echo '</label>';
echo "<br><label for='albumtracknum'>Track number:</label><br>
<input type='text' name='albumtracknum[]'>
<input type='hidden' name='albumid[]' value='".$albumid,"'>
<br><br>";
echo '</div>';
}
?>
<input type="hidden" name="albumidforreturn" value="<?php echo $albumid;?>">
<button type="submit" name="attachexistingtracktoalbum-submit">Attach track(s) to album</button>
<?php }
else {
header("Location: /index.php");
exit();
}?>
(NB: The post data here is not sanitised for the sql query as it has been passed along in a hidden form from the original album page)
This generates a page with all track names for the current artist available on a list with checkboxes, with each track name being followed by a data entry box to enter the track number for the album being added to.
Submission of the form then hands off to the following include code:
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "db_connect.pdo.php";
$albumid = implode(',',$_POST['albumid']);
$trackid = implode(',',$_POST['trackid']);
$albumtracknum = implode(',',$_POST['albumtracknum']);
$albumidforreturn = $_POST['albumidforreturn'];
// echo 'albumid: '.$albumid.'<br>';
// echo 'trackid: '.$trackid.'<br>';
// echo 'albumtracknum: '.$albumtracknum.'<br>';
$sql = "INSERT INTO trackconnections (albumid, trackid, albumtracknum) VALUES (?,?,?);";
$stmt= $pdo->prepare($sql);
$stmt->execute([$albumid,$trackid,$albumtracknum]);
header("Location: ../albumdetail.php?albumid=$albumidforreturn");
exit();
}
else {
header("Location: ../index.php");
exit();
}
(NB: The commented out echos are there to test what the output is from the previous form)
The 2 problems I am having are that my 'Attach existing tracks to album' form submit:
1. Passes on too much data.
The generated form should only pass on the track ids, album number, and track numbers that have had their checkboxes ticked. For insertion into the 'trackconnections' table.
Instead it narrows down the ticked checkbox track ids only and then creates comma separated values for every available track to select, rather than just those actually selected.
Which leads to annoying outputs such as the following when passing on data from form to include:
albumid: 4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4
trackid: 30,14
albumtracknum: ,2,3,,,,,,,,,,,,,,,,,,,,,
Where it should only read as:
albumid: 4,4
trackid: 30,14
albumtracknum: 2,3
Having too much data get passed through means that the row inserts won't be correct on multiple INSERTS once I do get this working, as they won't align with one another in the correct order.
2. The include only INSERTS 1 row to the 'trackconnections' table.
It seems I am misunderstanding how to add multiple rows to the database with my code here.
As having multiple checkboxes ticked on my 'Attach existing tracks to album' form only inserts 1 single row to the database on submission of the form each time.
Consistently the only track that gets added to the 'trackconnections' table is the first track with its checkbox ticked and, because of issue no. 1 above, the albumtracknum is always 0 unless I type a number into the first albumtracknum box on the available checklist.
I need to make tweaks to this code so that both problem 1 and 2 are addressed together, meaning that ticking the checkboxes & adding track numbers into each box following the track names actually adds multiple rows to the database along with their corresponding album track numbers.
I hope someone can help.
EDIT TO SHOW REFINED AND WORKING CODE:
New code for checkbox and textbox sections -
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "includes/db_connect.pdo.php";
$artistid = $_POST["artistid"];
$albumid = $_POST["albumid"];
echo '<strong>Select each track you would like to add to this album below and type in the track number you want it to have on the album in the box underneith the name of each selected track.</strong><br><br>';
$stmt = $pdo->query("SELECT * FROM track WHERE artist_id = '$artistid'
order by trackname");
echo '<form action="includes/attachexistingtracktoalbum.inc.php" method = "post">';
while ($row = $stmt->fetch())
{
echo '<div class="checkbox">';
echo '<label>';
echo "<input type='checkbox' name='trackid[]' value='".$row['id']."' />";
echo '<span class="cr"><i class="cr-icon glyphicon glyphicon-ok"></i></span>';
echo ' '.$row['trackname'];
echo '</label>';
echo "<br><label for='albumtracknumber'>Track number:</label><br>
<input type='text' name='albumtracknumber_".$row['id']."'>
<input type='hidden' name='albumid[]' value='".$albumid,"'>
<br><br>";
echo '</div>';
}
?>
<input type="hidden" name="albumidforreturn" value="<?php echo $albumid;?>">
<button type="submit" name="attachexistingtracktoalbum-submit">Attach track(s) to album</button>
</form>
<?php }
else {
header("Location: /index.php");
exit();
}
New code for the include INSERT processing -
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "db_connect.pdo.php";
$albumid = implode(',',$_POST['albumid']);
$trackid = implode(',',$_POST['trackid']);
$albumidforreturn = $_POST['albumidforreturn'];
foreach($_POST['trackid'] as $trackidloop) {
$albumtracknum = $_POST["albumtracknumber_{$trackidloop}"];
$sql = "INSERT INTO trackconnections (albumid, trackid, albumtracknum) VALUES (?,?,?);";
$stmt= $pdo->prepare($sql);
$stmt->execute([$albumid,$trackidloop,$albumtracknum]);
}
header("Location: ../albumdetail.php?albumid=$albumidforreturn");
exit();
}
else {
header("Location: ../index.php");
exit();
}
This isn't an entire solution but I see some problems:
You are looping through tracks and creating a new form for each one. The first problem is , you are missing the closing form tag. I guess the browser is automatically creating one, when it sees the next form start tag. ?? That's why you only get one single posted checkbox.
I would put all the track checkboxes into a single form. Then the posted trackid[] array will contain all the checked items.
[EDIT after your comment: The hidden fields albumid[] post the entire array, whereas the trackid[] checkboxes only post the actual checked boxes (HTML spec).
Instead of having albumid[], You could put the trackID and albumID together for the checkbox value, then parse them apart when you handle the post:
$value = $row['id']. ',' . $row['albumid'];
echo "<input type='checkbox' name='trackid[]' value='".$value."' />";
ALSO, the SQL, "INSERT INTO (..) .. VALUES (...) " only inserts one row.
It's easy to do that SQL in a loop for all the checked boxes.
foreach($_POST['trackid'] as $value) {
// parse the $value...
// SQL Insert...
}
EDIT 2: From my own comment:
Like hidden fields, input (text) field arrays also post the entire array (with empty values for blank inputs). (Again, this is not a PHP thing, it's a web browser standard to only post checked checkboxes and radio buttons. But ALL text and hidden INPUTs are posted.) So in your example, you need to code a mechanism to know which textbox goes with each checkbox. Quick and dirty...You could add a row index (0,1,2,3...) as another comma-separated number in your checkbox values, then you'll have the index into the posted textbox array. Alternatively, you could name the textboxes ' .. name="textinput_' . $row['trackid'] . '" ...' (not an array), then upon post, read them in your foreach loop with
$val = $_POST["textinput_{$trackid}"];

Trying to copy data to a table with checkboxes, a form, and php

My webpage is pulling data from two tables - applications and archiveapps - and displays them using the following:
$sql = "SELECT * FROM applications";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "Lots of info, including some html thrown in for style."
I want users to be able to click a checkbox listed next to each row and then hit an "Archive Selections" button that then moves all the selected entries from the applications table to the archiveapps one.
So far I've tried a form with it's code half in the echo above (so that a checkbox would go by each listed row from the $sql query) with the submit button outside (so that there would only be one "Archive Selections" button) but I'm sure this isn't proper syntax.
To actually move the data, I had this for the checkbox:
<form method='post' action=''><input type='checkbox' name='archname' value=".$row["charname"].">
(The above was inside an echo statement, so I assume it was able to pull the $row["charname"] no problem, but am unsure how to verify that.)
A little further down the page is the submit button and </form>.
And then I've got the function I want it to run when the submit button is clicked, to check if boxes have been selected and copy them into the archiveapps table. I'm sure there's something I'm missing here, probably in referencing what exactly is selected, and then copying that row's data to the other table... but honestly I just don't know enough about php to know what I'm missing.
if(!empty($_POST['archname'])) {
foreach($_POST['archname'] as $check) {
function archiveapp() {
$sqli="INSERT INTO archiveapps SELECT * FROM applications";
if ($conn->query($sqli) === TRUE) {
echo "<i>Archived</i>";
} else {
echo "Error: " . $sqli . "<br>" . $conn->error;
}}}}
Most of this has just been gathered from google searches and kind of mushed together, so I'm sure there are a lot of things done wrong. Any pointers or advice would be greatly appreciated!
Oh and my end goal is to copy the data to the archiveapps table and then delete it from the applications table, but for now I've just been focusing on the copying part, since I assume deleting a row will be fairly simple? Either way it's not the priority for this question.
Thanks in advance for any help!
Use a tool like FireBug to see what you are actually posting to server. You have multiple checkboxes with the same name, so you are sending only 1 value (the last checked, I think).
You need to send all of them, so use brackets after the name:
<!-- this is just an example -->
<input type="checkbox" name="archname[]" value="1">
<input type="checkbox" name="archname[]" value="2" checked>
<input type="checkbox" name="archname[]" value="3" checked>
Then on PHP, inside $_POST['archname'] you will get this:
Array(2, 3)
After this, you can do a foreach(...) loop like you are already doing, inserting only the ID you get from the $_POST variable:
foreach($_POST['archname'] as $id){
$sqli = "INSERT INTO archiveapps (id) VALUES (".(int)$id.")";
}

loading data from a mysql database table and using it within <input type="checkbox"> as an option

so i have this table in mysql called colegue in database addressbook1. it has the following fields: colegue_id, firstname, lastname, telephone and email. what i want is to get the data within the firstname column and display it within a form that uses checkboxes.for example:
checkbox jerry
checkbox mary
checkbox cindy
and so on. then, the checked data is supposed to be sent to a script which echoes the data selected. here's the code that loads data onto the page:
<?php
//connect to mysql
mysql_connect("localhost", "root", "");
//select database
mysql_select_db("adressbook1");
//select data from table
$query=("SELECT * FROM colegue");
//perform query
$result=mysql_query($query);
?>
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>testing</title>
</head>
<body>
<h3>testing a checkbox form</h3>
<?php
//start the form
echo "<form method=\"post\" action=\"process.php\">";
while($row=mysql_fetch_array($result))
{
//assign value from associative array to variable
$data=$row['firstName'];
/*echo data and assign the value in the input the current value of $data while loading onto array*/
echo "<input type=\"checkbox\" name=\"firstname[]\" value=\"<?php $data;?>\">".$data." <br>";
}
echo "<br>";
//send data to process.php when clicked
echo "<input type=\"submit\" name=\"sent\" value=\"add\">";
echo "</form>";
?>
</body>
</html>
now for the script that processes the data:
<?php
//get the data from the form in an array
$entry=$_POST['firstname'];
//check if the array is empty or not
if (empty($entry))
{
echo("execution failed");
}
//if not empty, continue
else
{
//get the array size
$N=count($entry);
//display the size of the array
echo "$N"."<br>";
//this loop should display all the data in the array
for($i=0; $i<$N; $i++)
{
echo "$entry[$i]"."<br>";
}
//end script by showing successful result
echo ("request successful!");
}
?>
the code runs fine when i check the names i want sent and submit them to the script. the script does show me the size of the array, (e.g. if i clicked on four names, it shows me the number four) but it doesn't show me anything else, it doesn't display the actual names that i clicked on the page. could anyone kindly help me solve this? i'm thinking that maybe i haven't properly assigned values in the array firstname[].
Please note that i have to use this method (checkboxes) to submit the data gotten from the database so that it is displayed in the script-page. i am very new to programming, so i kindly ask for help, thanks.
You need to concatenate $data with the string, just alter
value=\"<?php $data;?>\"
too
value=\"".$data."\"

Generate a query that changes a single element on multiple rows PHP MySQL

I'm working on a homework assignment that involves PHP. Basically, I have a page that contains a web form that renders items pulled from a database. There's checkboxes on each row and 2 radio buttons. The user selects "accept" or "deny" and when submit is clicked, the items that are checked are supposed to change to that approval status. All of the items in the form are submitted into post. I thought that post is an array so I could just use a while loop with a counter so that the loop traverses through the array and when it gets to the last index (which should contain approve or deny). A query is generated that changes all of the previous indexes to approve or deny. I'm sorry if this isn't making much sense.
Here's a picture for more clarification
Here's the code I used to generate the webform:
<?php
#create a query string
$query = "SELECT * FROM Request WHERE superemail = '$user'";
#echo $query;
#run the query
$result = mysqli_query($link, $query) or die('error querying');
while($row = mysqli_fetch_array($result)){
#print out each row of the queryi
#line up the query results with temporary strings
$change = $row['KEY'];
$name = $row['first']. " " . $row['last'];
#echo $name;
$email = $row['email'];
#echo $email;
$type = $row['type'];
#echo $type;
$duration = $row['duration'];
$status = $row['status'];
#create a table row with the query results
echo "<tr><td><input type=checkbox name=$change /></td>
<td>$name</td>
<td>$email</td><td>$type</td>
<td>$duration</td><td>$status</td></tr>";
} #end while
?>
<label for=update>Change status to:</label><br />
<input type=radio name=update value=A />Approved<br />
<input type=radio name=update value=D />Denied<br />
<input type = submit value = "Change Status" />
Each input tag (your checkboxes and your radio button) in your html should have a name attribute, such as: <input type='radio' name='accept' value='1' />. When the form is submitted and processed by PHP, your script will be able to access that info at $_POST['accept'] (or $_GET['accept'] depending on the form's method).
So you should be able to specify a name for the radio button, then check to see if there is a value in the POST array at that index.
I am going to assume a few things. First, that it is a design goal of yours to only process items in your approval queue that you choose to select, leaving the others alone. Second, that you want to change their status to what is chosen in a radio button. Third, that you want both a code snippet and an explanation as to how the task got accomplished.
So, here goes.
You have a series of checkboxes; I assume they have the same name. If you wish for the values to be passed to PHP as an array, you absolutely need to name the inputs whatever[] with emphatic emphasis on the []! This is what creates an array from the checkbox to appear in the $_POST/$_GET. Only those items selected will appear in the array. The value ought to be something useful (A value in the corresponding database table, say) which you can select for and query on...after sanitizing the input, of course.
So, your HTML input tag should look like this:
<input type="checkbox" name="process[]" value="<?php echo $employeeName ?>" >
You should have this coming back at you...
$_POST['process'][array(0=>name1, 1=>name2/*...etc*/)]
...which you can loop through with a foreach at your leisure.

how to retrieve checked values in php

I am a newbie in php. I have a form with multiple checkbox values. I wanna retrieve the checked values and diplay these values on other php form.
Below is the code which works perfectly fine if we add the checkboxes without while loop.
But when added through while loop I am not able to fetch the selected items.
xyzhtml.php(html form)
<?PHP
require ("DBConnect.php");
$selectQuery =mysql_query( "SELECT * FROM fruits where approved = 0");
while($row = mysql_fetch_array($selectQuery))
{
$fruit_name = $row['fruit_name'];
echo "<input type=\"checkbox\" name=\"things[]\" value=\"$fruit_name\">";
echo "<br>";
}
?>
On click of submit I call other php clled "xyz.php".
Below is the code used in it.
<?php
$checkBox = $_POST['things'];
echo $checkBox[0];
for($i=0; $i<sizeof($checkBox); $i++){
echo($checkBox[$i]);
}
?>
Please help.
Thanks in advance.
two things to check:
are you getting right values from the MySQL SELECT statement (check your HTML for empty checkboxes values and check your MySQL database for fruits that have approved field set to 0 to see if there are any)
when you don't tick a checkbox and submit the form, unticked checkboxes' values do not get submitted - have you thought about that?
Use foreach to record $_POST['things']
if (!empty($_POST['things'])) {
foreach ($_POST['things'] as $value) {
echo "the value are: ".$value;
}
}
Note: teh $_POST['things'] not $_POST['things[]']
I think your code should work, but it won't display anything if no checkboxes are selected.
I would however remove the explicit echo $checkbox[0] (unless this is for testing purposes).
Try a print_r($checkbox) to see what's actually in that array.

Categories