Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
so I would like to use something like /action=productSpec?product=1
And then echo the value "1".
I have this:
case "productSpec":
$show = $_GET['product']
echo $show;
break;
But it doesn't work.
Why? Thank you.
"Case is also GET";
Change that part in the URL to ?action=productSpec&product=1
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 days ago.
Improve this question
i have url with string like this
example.com/?id=
i want to create a condition when my url looks like this in a search query
Thank you to all of you
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
Improve this question
Is there a way to make something like this:
$bob = $request->bob;
return $bob in_array()....
to resolve to something like
return ! in_array()....
or
return in_array()....
base on the variable value...
You can use ?:
return $variable ? in_array('x', $some_arr) : !in_array('x', $some_arr);
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
Exist any way to know the source page that is calling the query and store it?
Are you looking for $_SERVER['PHP_SELF'] ?
Check also print_r($_SERVER) if something is more accurate for what you need
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
http://example.com/geturl.php?url=http://example.org/index.php?parafile=1698%3A1562%3A0%3A0¶_action=print_ticket¶file=dance://here.kodas/print&token=3ec2b0d3e6e0ca152bc024cc3f30f16c
So i want each of this parameters in a different varaible in the geturl.php file. I am using the regular get url
You can use anything like this :
$url = "http://example.com/geturl.php?url=".urlencode($urlPart);
$_server[QUERY_STRING] solved my problem
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
is there any way i can get the id inside this code:
header('Location: assigned.php?success?$ticket_id');
I am new to PDO. sorry for the simple question
You are adding ? twice. it should be like..
header('Location: assigned.php?success='.$ticket_id);