how to variable pass mail function in php - php

Question

I am new to php and i want solution for variable pass in mail function
I am using this way to variable pass mail function but getting issue Code:
<?php
require 'PHPMailer/PHPMailerAutoload.php';
function Send_Mail($to,$subject,$body,$cc = "",$bcc = "")
{
$mail = new PHPMailer;
$mail->isSMTP();
$mail->Host = 'smtp.gmail.com';
$mail->SMTPAuth = true;
$mail->SMTPDebug = false;
$mail->Username = 'xyz#gmail.com'; // Your Gmail Address
$mail->Password = '123456'; // Your Gmail Password
$mail->SMTPSecure = 'ssl';
$mail->Port = 465;
$mail->From = 'xyz#gmail.com'; // From Email Address
$mail->FromName = 'gfgg'; // From Name
$mail->addAddress($to);
$mail->addReplyTo('xyz#gmail.com', 'dfg'); // Same as From Email and From Name.
$mail->WordWrap = 50;
$mail->isHTML(true);
$mail->Subject = $subject;
$mail->Body = $body;
if(!$mail->send()) {
return array('status' => false, 'message' => $mail->ErrorInfo);
}
return array('status' => true, 'message' => 'Email Sent Successfully');
}
if (isset($_REQUEST['submit']))
{
$name=$_POST['name'];
$email=$_POST['email'];
$contact=$_POST['contact'];
echo $name, $email, $contact;
$result = Send_Mail('$name','$email','$contact');
}
pls give me soltution
?>

Answer 1

The Send_Mail function requires minimum 3 parameters, which are $to, $subject and $bodyin this order.
So first of all you are calling your parameters within strings
$result = Send_Mail('$name','$email','$contact');
and in the wrong order.
You should probably try this
$result = Send_Mail($email, "Subject", "Message");
You will have to define $subject and $message variables and replace them with "Subject" and "Message"

Answer 2

Try with -
echo "$name, $email, $contact";
$result = Send_Mail($name,$email,$contact);