My database structure is like this:
Movie Name GenreID**
Movie1 1,2,3
Movie2 2,4
Movie3 4,5,16
I need to select a Movie name based on the Genre ID the user selected which I put inside the genreIDArray[]
Let's say for example the genreIDArray has values: $genreIDArray = ['1','2','3'];
My current query method is the ff:
Here I prepared each ID into parts so the result won't become genreID LIKE (%1,2,3%) because I checked this doesn't work.
So I did this separation loop:
$queryParts = array();
foreach($genresIDArray as $genreID) {
$queryParts[] = "'%".$genreID."%'";
}
After the separation loop I put together the final query:
$genreString = implode(" OR genreID LIKE ",$queryParts);
$genreQuery = " SELECT * FROM movies WHERE (genreID LIKE {$genreString}) ";
gave me this final query output:
SELECT * FROM movies WHERE (genreID LIKE '%1%' OR genreID LIKE '%2%' OR genreID LIKE '%3%')
This actually works, but apparently not that efficient because genreID 11,12,13 and so on that start with 1 is also selected. I think I'm missing the MYSQL LIKE logic here. I've tried '%$genreID' which means to select the starting or first number/letter of a table data, but that's still the same thing, $genreID% doesn't and would not work because this only means genreid ENDING letters/number will be selected.
I hope I spelled that out clear enough. I'm in a bind here. Please help.
Thank you so much.
There is a very cool function for that. You can use FIND_IN_SET.
SELECT * FROM test WHERE FIND_IN_SET(1,colors)
But if its possible you should avoid such structures in your database and normalize your database.
Related
I am learning how to work with MySQL, and at the moment I succeed to show data from my table, using:
while($objResult2 = mysqli_fetch_assoc($objQuery_product)) {
Results are shown by using this variable $objResult2["id_product"]; this way i can take from DB any field I want like: $objResult2["name"]; $objResult2["email"]; etc.
But what i do if i have in the table more rows with the same id_product?
I want to write a if statment, which counts if id_product repeats. How to do that? If it is a lot of work, atleast please give me an idea of the right tutorial that I must read. Because i am trying second day to fix this, and searched google but i didnt find what i need, or maybe i coulndt understand it....
This is my query
$sql_product = "SELECT * FROM ps_product AS prod";
$join_product = " LEFT JOIN ps_product_lang AS lang ON lang.id_product = prod.id_product";
$join2_product = " LEFT JOIN ps_stock_available AS stok ON stok.id_product = prod.id_product";
$where_product =" WHERE prod.id_category_default = $idp AND lang.id_lang = 8";
$sql_product = $sql_product.$join_product.$join2_product.$where_product;
$objQuery_product = mysqli_query($objConnect, $sql_product) or die ("Error Query [".$sql_product."]");
You can simple remove the same id_product using DISTINCT keyword in your query. Such as:
SELECT DISTINCT id_product FROM my_table
This will give you results with different ids only.
The second way of doing it is taking the output values inside an array.
In your while loop:
$my_array[] = $objResult2["id_product"];
Then using array_filter remove all the duplicates inside the array.
YOu can also use array_count_values() if you want to count the duplicate values.
Ok here we go. For example you are fetching data with this query.
select id_product, name from PRODUCTS;
Suppose above query gives you 5 records.
id_product name
1 bat
2 hockey
2 hockey
3 shoes
4 gloves
Now you got 2,2 and hockey, hockey. Instead of thinking this way that you have to introduce an if statement to filter repeating records or same name or id_product records.
Rewrite your sql query like this.
select distinct id_product, name from PRODUCTS;
Or if you need count of each then my friend you will write your query something like this...
Graham Ritchie, if Andrei needs count of each repeating record then we will do something like this in our query.
SELECT PRODUCT_ID,
COUNT(PRODUCT_ID) AS Num_Of_Occurrences
FROM PRODUCTS
GROUP BY PRODUCT_ID
HAVING ( COUNT(PRODUCT_ID) > 1 );
SELECT id_product,COUNT(*) AS count
FROM tablename
GROUP BY id_product;
This query will then return you two items in your query
$objResult2["id_product"] //and
$objResult2["count"]
The if statement is then just
if($objResult2["count"] > 1){
//Do whatever you want to do with items with more than 1 occurence.
//for this example we will echo out all of the `product_id` that occur more than once.
echo $objResult2["id_product"] . " occurs more than once in the database<br/>";
}
I am trying to select a record using the LIKE function. However, it does not show results if there are characters in between. I want it to select data that contains those strings. For example:
$value = "Mark Anthony";
$qry ="SELECT * FROM students WHERE name LIKE '%$value%'";
returns these results:
John Mark Anthony
Mark Anthony Philipps
but I also want to have results like these
Mark James Anthony
Mark Gabriel Anthony Fernandez
Marko Julian Anthonyo
Any ideas?
UPDATE: 'Mark' must be before 'Anthony'
I think Full TEXT works
But Full-text searches are supported for MyISAM tables only
SELECT * FROM students
WHERE MATCH (name)
AGAINST ('Mark Anthony' IN BOOLEAN MODE)
UPDATE:- As per question update OP need to search Marko as well, then you can get like this:-
SELECT * FROM students
WHERE
(
name LIKE '%Mark%'
OR name LIKE '%Anthony%'
)
You could split the value string into two parts. Like so:
WHERE name LIKE '%Mark%' AND name LIKE '%Anthony%'
last try:
$value = "Mark Anthony";
$value = str_replace(" ","%",$value);
$qry ="SELECT * FROM students WHERE name LIKE '%$value%'";
not tested!
Try this solution -
SELECT * FROM table WHERE column REGEXP '(Mark).+(Anthony)';
The proplem is, you say "bring all results which contains Mark Anthony" so it does. You should set it like
$value = "Mark%Anthony";
I've looked all over the interwebs, and cannot find that simple answer I'm looking for - possibly because it doesn't exist, but.. possibly because I don't know the correct terms to search for.
ok, so, i've got a variable - it's actaully a key value pair in an array that i'm passing into my function. the key is args[comments_mentioned] and the value is dynamically generated for me - it's ALWAYS going to be number, separated by commas (i.e. 1,2,3,4,5)
so, just to be super clear:
$args[comments_mentioned] == "1,2,3,4"; //could be any amount of number, not just 1,2,3,4,5
i'd like to pass this into a sql statement as a variable to use in an "IN" clause, like so:
$sr_sql = <<<SQL
SELECT *
FROM $wpdb->commentmeta
WHERE meta_value = %s
AND comment_ID in ($args[comments_mentioned])
ORDER BY meta_id DESC
SQL;
Then, Prepare it using the wordpress prepare and get results
$sr_query = $wpdb->prepare( $sr_sql, $args[user_id]) );
//receive the correct sql statement, and plug 'er in.
$sr_comment_rows = $wpdb->get_results($sr_query);
and run my foreach loop:
foreach ($sr_comment_rows as $sr_comment) {
$sResults .= 'do something with $sr_comment';
}
now, i realize the code above won't work - i can't just pass the variable in there like that. BUT, i can't pass it as a string (%s), because it wraps it in '1,2,3,45', and so it looks for the entire string, and not each number. I can't pass it as an int (%d), because of the commas...
In other posts, they mentioned create a temp table or variable, but, i'm not sure if that's the correct way to do it in mysql, or how to reference it once I do.
so, how do I do this? preference for actual code that works ;)
Thank you for reading and helping out!
One option, if you cannot normalize your data, is to enclose your string in commas such that it be ",1,2,3,4," and then you could do:
AND LOCATE( CONCAT(',',comment_ID,',') , ($args[comments_mentioned]) )
which will match if it finds a eg. ',3,' in ',1,2,3,4,' (Using 3 as an example)
I believe this should be enough:
$params = $args[comments_mentioned];
$table = $wpdb->commentmeta;
$sr_sql = "
SELECT *
FROM $table
WHERE meta_value = %s
AND comment_ID in ($params)
ORDER BY meta_id DESC
";
It will be result something like:
SELECT *
FROM table_on_variable
WHERE meta_value = %s
AND comment_ID in (1,2,3,4)
ORDER BY meta_id DESC
If your mainly issue is regarding the in clause, so you will not have problems if you use double quotes and single variable as illustrated above.
Hello i Have tableuser, with column id and many more. now i want all id in string form concatenated with comma separation and appending prefix as A.
means suppose i have records with id 1, 2, 3, 4 etc
now i want result like A1,A2,A3 like this
i did it with my way but its too complex i want to do it with single query.
my code are as under its working fine.
$send_idstring='';
$qry="SELECT concat('A',id) as id FROM `admin` WHERE concat(fname,' ',lname) LIKE '%".addContent($searchVal)."%' ";
$send_id=mysql_query($qry);
while($row=mysql_fetch_assoc($send_id)){
$send_idstring.=$row['id'].',';
}
$send_idstring=trim($send_idstring, ",");
echo $send_idstring;
it gives me output as i want but i want another way to do it please suggest.
Try
SELECT GROUP_CONCAT(CONCAT('A', `id`) SEPARATOR ',') AS idList FROM `admin`;
http://dev.mysql.com/doc/refman/5.5/en/group-by-functions.html#function_group-concat
I think I don't understand how 'sort' works, so please don't judge me. I really searched all day long.
I have a movies table with actors column. A column it's named "actors". The actors are links separated by space " ". The order of the links it's very important.
I explode the links into an array which looks like [0]-> link0, [1]->link1, ...
I have the actors table where every actor also has it's movies links. I don't want to make 20 different sql searches so I made a variable with all the links I want, like this ( WHERE actor_link = link1 OR actor_link = link2 OR .. )
The problem is this. The search will probably find first the link7, and so my sorting it's gone. What can I do to keep that order from the movies table. I want to display the actors by popularity in the movie, not the order of my database.
Can you give me another method to search the actors without making 'x' sql searches and still keeping the order?
$actors[] = explode(" ", $row['actors_link']);
$x=0;
$actors2 = '';
while ($actors[0][$x]) {
$actors2 = $actors2 . "`link_imdb_actor` = " . "'".$actors[0][$x]."' OR ";
$x++;
}
$actors2 = substr($actors2, 0, -3);
$sql = "SELECT * FROM `actors` WHERE $actors2";
$sql_result = mysql_query($sql) or die(" ");
while ($row3 = mysql_fetch_array($sql_result)) {
echo $row3['link_imdb_actor'];
}
So, the movie Hotel Transylvania has Adam Sandler, Andy Samberg and Selena Gomez. My search shows Selena Gomez, Andy Samberg, Adam Sandler because this is the order from my database. How can I sort the sql results by the order of the actors array? Thank you!
To expand on Arjan's comment, if you want to be able to actually use the actor data (e.g. search with it) I would recommend at least two more tables. One called actors with the fields actorID, firstName, and lastName. The other table would be castings with the fields castingID, actorID, movieID, and castingOrder.
Each castingID will then link an actor to a movie - this would make for easy searches of every movie a particular actor has been in or every actor in a particular movie.
The castingOrder field can be used to maintain the order you want.
I need your existing code to really get the gist of what's going on.
I will make one suggestion in your query. Instead of saying WHERE actor_link = a OR actor_link = b OR actor_link = c do this instead:
WHERE actor_link IN (link1, link2, link3)