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$VAR= 5;
$VAR1=30;
Mathematical expression :- 5 * 60 * 60 + 30 * 60
i.e. 5 and 30 are $VAR and $VAR1 respectively.
how to use this manually in php code and store result in $RESULT.
This will work:
$result = $VAR * 60 *60 +$VAR1 *60;
The following link will give you an idea of order of preferance
Here is your expression
<?php
$VAR = 5;
$VAR1 = 30;
$calc = - $VAR * 60 * 60 + $VAR1 * 60;
echo $calc;
?>
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<?php
$seed = 'COPY_RAFFLE_SEED_HERE'; // Randomly generated seed [Seed:]
$raffle_id = 'COPY_RAFFLE_ID_HERE'; // Raffle ID [Raffle ID:]
$entries = 10; // Number of tickets [Entries count:]
/*
*
* Must +1 return value since it starts with 0
* 28 characters offset to get 4 characters from both hashes
*
*/
$randomNumber = (hexdec(substr(md5($seed) . md5($raffle_id), 28, 8)) % $entries)+1; // Must use +1 as it starts with 0
echo "Ticket with number #$randomNumber won";
apparently this is the code used for the giveaways, and i wanted to see how it works
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I would like to know how can I change
$var = "01:30:00";
to
$var = "1.5";
in PHP ?
Thanks.
Something along these lines...
<?php
function timeToHours($time) {
$hoursMinsSecs = explode(':', $time);
return $hoursMinsSecs[0] + $hoursMinsSecs[1] / 60 + $hoursMinsSecs[2] / 3600;
}
$var = "01:30:00";
echo timeToHours($var);
?>
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I have this a record of: 10/2 * 100%
This is equal to 5
How does it save in PHP?
This not work:
($int1/$int2) * 100
Assuming $int1 = 10 and $int2 = 2, you'd have this sum;
echo (10 / 2) * 1; //1 being 100%
Which outputs 5.
http://codepad.org/twp2TduF
There is nothing wrong - it gives your desired result. I assume you were * 100, which would give 500.
Other percentages
* 0.25 = 25%
* 0.75 = 75%
..and so-on
Or refer to this answer
You cannot use percentage this way.
You will need to divide them by 100:
<?php
$int1 = 3;
$int2 = 6;
echo ($int1/$int2) * 100/100;
this above is 100%
and this:
echo ($int1/$int2) * 25/100;
is 25%
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I have a bit of code but it is not echoing the correct answer, or in the correct format. I tried the round function but that didnt show anything
here is my code
$total_per_year = 308790;
$fat = $total_per_year / 3500;
echo $fat;
it is currently showing it as 0.088, but the correct answer is 88.2257142857
how can i do this so it round up to 88.2
The round function requires two parameters like so:
echo round($fat,1);
The second parameter being the amount of decimal places you require.
I have had issues previously with round not working as expected and I had to use number_format:
echo number_format((float)$fat,1,'.','');
With 1 being the decimal places required, the full stop being the decimal separator and '', being the thousand separator.
Use round()
echo round($fat, 1); //second argument is precision eg. decimals
See this for documentation: http://dk1.php.net/round
right, i worked this out now. I know i kept getting '0.088'. And this is wrong.
Its because i had it like this
$total_per_day = number_format($total_per_cup * $number_of_cups);
$total_per_year = number_format($total_per_day * 365);
$fat = round($total_per_year / 3500, 1);
echo $fat;
echo $total_per_year;
this is the correct code.
$total_per_cup = $type_calorie + $milk_calorie + $sugar_calorie;
$total_per_day = $total_per_cup * $number_of_cups;
$total_per_year = $total_per_day * 365;
$fat = $total_per_year / 3500;
echo json_encode(array('total'=> number_format($total_per_year) , 'perday' => number_format($total_per_day), 'fat'=> round($fat, 1)));
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For example I have this range:
20 to 200
How can I programmatically get the value for a specific percentage, lets say 40% between those 2 numbers?
Simple example:
0 to 200
I want to get the value of 40%. Answer is 80.
Try this:
function percentage_from_range($from, $to, $percentage) {
$result = (($to - $from) / 100 * $percentage) + $from;
return $result;
}
e.g.
echo percentage_from_range(20, 200, 40); //92
$num1=20;
$num2=200;
$percent=40;
$total=$num2-$num1;
$result = (($total/100) * $percent)+$num1;
$lwb = 20;
$upb = 200;
$perc = 40;
$value = $lwb + ($upb - $lwb) * $perc / 100;
Takes perc/100 part of range, and start with the lowerbound.