I am trying to calculate the total of today's sales but this doesn't work.
It works, if I remove the date part...
# This works and will gives out the total:
$result = mysql_query("SELECT SUM(grand_total) AS value_sum FROM order");
$row = mysql_fetch_assoc($result);
$sum = $row['value_sum'];
# This doesn't work:
$result = mysql_query("SELECT SUM(grand_total) AS value_sum FROM new_order WHERE date = CURDATE()");
$query = mysql_query($result) or die ('Error: ' . mysql_error());
$row = mysql_fetch_assoc($result);
$sum = $row['value_sum'];
Also, how can I get the monthly total of this column after this?
If date field is DATETIME type, then try this sql statement:
SELECT SUM(`grand_total`) AS value_sum
FROM `order`
WHERE DATE(`date`) = CURDATE()
Related
I am trying to create an array in $data, but it is not happening. I am using this code to make a day wise sale chart.
$data = array();
for ($i = 0; $i <= 10; $i++) {
$billdate = date('d-m-Y', strtotime("-$i day"));
$sqlQuery = "select sum(amount),bill_date from msr_bills WHERE bill_date='$billdate' ";
$result = mysqli_query($con, $sqlQuery);
$fetchamount = mysqli_fetch_row($result);
$sum = $fetchamount[0];
$data = new \stdClass();
$data->bill_date = $billdate;
$data->amount = $sum;
$report_JSON = json_encode($data);
echo $report_JSON.",";
}
You can merge your loop into one query, and then iterate over the results instead:
$data = array();
$billdate = date('Y-m-d', strtotime('-10 day'));
$sqlQuery = "SELECT bill_date, SUM(amount) AS amount
FROM msr_bills
WHERE bill_date >= '$billdate'
GROUP BY bill_date";
$result = mysqli_query($sqlQuery);
if ($result) {
while ($row = mysqli_fetch_assoc($result)) {
$data[] = (object)$row;
}
$report_JSON = json_encode($data);
echo $report_JSON;
}
Note that your date format is not compatible with MySQL dates, which are stored in Y-m-d format, and I have changed that in the code. If your bill_date column is actually a text field stored in d-m-Y format, you will need to convert it in the query like so:
$sqlQuery = "SELECT bill_date, SUM(amount) AS amount
FROM msr_bills
WHERE STR_TO_DATE(bill_date, '%d-%m-%Y') >= '$billdate'
GROUP BY bill_date";
Note also that you can in fact do the computation of $billdate internal to your SQL query using date arithmetic:
$sqlQuery = "SELECT bill_date, SUM(amount) AS amount
FROM msr_bills
WHERE STR_TO_DATE(bill_date, '%d-%m-%Y') >= CURDATE() - INTERVAL 10 DAY
GROUP BY bill_date";
And if you are running MySQL 8.0+, you can do the entire operation in MySQL:
$sqlQuery = "SELECT JSON_ARRAYAGG(data) AS data
FROM (SELECT JSON_OBJECT('bill_date', bill_date, 'amount', SUM(amount)) AS data
FROM msr_bills
WHERE bill_date >= CURDATE() - INTERVAL 10 DAY
GROUP BY bill_date) d";
$result = mysqli_query($sqlQuery);
if ($result) {
$row = mysqli_fetch_assoc($result);
$report_JSON = $row['data'];
echo $report_JSON;
}
Demo on dbfiddle
Put your echo outside loop. remove code $report_JSON = json_encode($data);
$respnseArr = array();
{
.
.
.
$respnseArr[] = $data;
}
echo json_encode($respnseArr);
I want to get the sum total of the table columns in my database.
I've tried using the following code but have not been successful.
$link=mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_NAME);
$result = mysqli_query($link,'SELECT SUM(value) AS value_sum FROM User_Table');
$row = mysqli_fetch_assoc($result);
$sum = $row['value_sum'];
echo $sum;
Thank you very much!!
I hope you try to find total number of record of a table of User_Table
$link=mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_NAME);
$result = mysqli_query($link,'SELECT SUM(your_column_name) AS value_sum FROM User_Table');
//or like the query for return last row that indicate total number of record
// id auto increment
$result = mysqli_query($link,'SELECT * FROM User_Table ORDER BY id DESC LIMIT 1;');
$row = mysqli_fetch_assoc($result);
$sum = $row['id'];
echo $sum;
// or using count
$result = mysqli_query($link,'SELECT COUNT(*) total_row FROM User_Table;');
$row = mysqli_fetch_assoc($result);
$sum = $row['total_row '];
echo $sum;
As of my understanding you need count the number of columns your database have. If I am not wrong, you may please use the query below
select * from information_schema.columns
where table_schema = '<YOUR DATABASE NAME>'
order by table_name,ordinal_position
Hope this helps. Thanks
I was able to apply this line onto phpMyAdmin and it worked just fine.
SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY date DESC LIMIT 1
The problem is that when I added the rest of the code, the recent date shows up blank on the webpage. Am I missing something in this code?
<?php
$query = "SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY date DESC LIMIT 1";
$result = mysql_query($query);
echo "$date";
?>
Any help is appreciated. Thank you.
. Try this
$query = "SELECT id, date_format(`date`, '%m.%d.%Y') as `date` FROM TABLE ORDER BY. date DESC LIMIT 1";
$result = mysql_query($query);
$r = mysql_fetch_assoc($result);
$date = $r['date'];
echo "$date";
You didn't set $date variable. You need to use mysql_fetch_array function for your $result variable.
Ex:
`
$query = "SELECT id, date_format('date', '%m.%d.%Y') as 'date' FROM TABLE ORDER BY date DESC LIMIT 1";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
print_r($row); }
`
hello im having some problem with this sum select does anyone know whats wrong with this, it seems that im getting no result from it
$result = mysql_query("SELECT SUM(total)
FROM table1 where date BETWEEN '".$date1." 00:00:00' AND '".$date2." 23:59:59' and username = ".$user."");
while($row=mysql_fetch_array($result))
{ $sum = $row['SUM(total)'];}
Try
$query = "SELECT SUM(total) AS result
FROM table1
WHERE DATE(date) BETWEEN '$date1' AND '$date2'
AND username = '$user'";
$con = \\your db connection string
$result = mysql_query($con,$query);
while($row=mysql_fetch_array($result))
{$sum = $row['result'];}
I'm trying to sort this query by time.
I have a gaming match system. And I want to get a list of next 5 matches from my local time zone.
<?php
include_once "include/dbcompo.php";
$q=mysqli_query($con, "SELECT * FROM kamper ORDER BY tid LIMIT 5");
while($row = mysqli_fetch_array($q))
{
$clan1 = $row['clan1'];
$clan2 = $row['clan2'];
$server = $row['server'];
$tid = $row['tid'];
echo $clan1." ".$clan2." ".$server." ".$tid;
echo "<br />";
}
?>
Add a WHERE clause in your query: WHERE tid > NOW().
With NOW() you take the time of the server, maybe you should replace it with new DateTime(null)->getTimestamp()
Something like that:
<?php
mysqli_query($con, 'SELECT * FROM kamper WHERE tid > NOW() ORDER BY tid LIMIT 5');
// or
mysqli_query($con, 'SELECT * FROM kamper WHERE tid > '.new DateTime(null)->getTimestamp().' ORDER BY tid LIMIT 5');
?>
Two options:
1st option: Make the time field a numeric field and sort in PHP:
$queryResult = mysqli_query($con, $query);
while($row = mysqli_fetch_array($queryResult) {
$oldArray[$row['time'] = $row;
}
$array = ksort($oldArray);
foreach($array as $time=>$row) {
// do something
}
2nd option: Make a subquery
SELECT * FROM (
SELECT * FROM kamper WHERE timezone = 'UTC' ORDER BY tid
) LIMIT 5