Outputting SQL query as line by line JSON - php

Question

My SQL query is selecting date and doing a count, as well as grouping by date.
I don't know how to output line by line JSON output.
$sql = "SELECT DATE(timestamp), COUNT(eventid)
FROM `tablex`
WHERE timestamp >= date_sub(CURRENT_DATE, interval 30 day)
GROUP BY DATE(timestamp) ";
$stream = mysqli_query($conn, $sql);
if (mysqli_num_rows($stream) > 0) {
while($row = mysqli_fetch_assoc($stream)) {
// Is this where I should echo JSON?
// The problem is I'm not retrieving records but count and doing
// a grouping
}}

Answer 1

Use mysqli_fetch_array(), also take the count with mysql_num_rows():
$sql = "SELECT DATE(timestamp), COUNT(eventid)
FROM `tablex`
WHERE timestamp >= date_sub(CURRENT_DATE, interval 30 day)
GROUP BY DATE(timestamp) ";
$stream = mysqli_query($conn, $sql);
if (mysqli_num_rows($stream) > 0) {
$rowCount = mysql_num_rows($result);
while($row = mysqli_fetch_array($result, MYSQLI_NUM)){
// Process JSON here use $row[0], $row[1], and so
}
}

Answer 2

Whatever you like to return as a JSON-string, you should always write your data into a single array, then use this nice little PHP-function called json_encode(). For example:
$sql = "SELECT
DATE(timestamp) as date_timestamp,
COUNT(eventid) as count_eventid
FROM `tablex`
WHERE timestamp >= date_sub(CURRENT_DATE, interval 30 day)
GROUP BY DATE(timestamp);";
$stream = mysqli_query($conn, $sql);
// prepare return array
$mydata = array(
'eventcount' => 0
);
if (mysqli_num_rows($stream) > 0) {
while($row = mysqli_fetch_assoc($stream)) {
// just collect your data here, do not JSONify here
$mydata['eventcount'] += $row['count_eventid'];
}
}
// We got all our data, so return JSON encoded array
echo json_encode($mydata);
You will get something like
{"eventcount":"1234"}

Answer 3

I managed to get an output:
$stream = mysqli_query($conn, $sql);
$lines = array();
while($line = mysqli_fetch_assoc($stream)) {
$llines[] = $line;
}
print json_encode($lines);