mysql php update with a variable [closed] - php

Question

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
So I've been at this for a while now and anything I do or research turns up more errors. I keep getting this error: Fatal error: Call to a member function query() on a non-object with code that looks like this. the pic column is for a profile picture directory they uploaded.
$newTarget_file = "uploads/picture.png"
....
$sql = "UPDATE users SET pic='$newTarget_file' WHERE username=:username";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}
also this is a php that is submited to that saves the picture they upload and the directory is the $newTarget_file . This is realy frustrating my on how I do this. Thanks in advance for the help.
Basically I want to update the pic column where username=:username with a variable I have already $newTarget_file . what do I do?

Answer 1

As others have said, the error is because your connection object doesn't exist.
Fatal error: Call to a member function query() on a non-object
Based on the tutorial you are following, have you implemented this?
$conn = new mysqli($servername, $dbuser, $dbpw, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
You should have gotten a connection error before the query ever tried to run. Also, as Michael pointed out, you can't used named parameters with mysqli. It's only supported in PDO, but you can still use placeholders. Your new code should look something like this.
if (!($stmt = $conn->prepare("UPDATE users SET pic=? WHERE username=?"))) {
echo "Prepare failed: (" . $conn->errno . ") " . $conn->error;
exit;
}
if (!$stmt->bind_param("ss", $newTarget_file, $username)) {
echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
exit;
}
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
exit;
}
$stmt->close();