I've 4 table for a newsletter. Newsletters, Subscribers, Subscriber Groups and Selected Subscriber Groups. I've choose subscriber groups in campaign edit area, and its save selected groups to tbl_newsletter_groups table like;
tbl_newsletters
NID title details
1 text 1 content 1
2 text 2 content 2
tbl_subscriber_groups
GID group_name
5 group 1
6 group 2
tbl_subscribers
SID GID email name
10 5 sub1#mail.com sub1 name
11 6 sub1#mail.com sub1 name
tbl_newsletter_groups
NGID NID GID
15 1 6
16 1 6
17 1 6
I want to show total selected subscriber count when I list newsletters in my page. My soulution works fine, Im looking for simple and clearly statement, there any faster way available like in single newsletter list statement?
Here my own count style (yes I know its too bad and long way);
$subGID = array();
$list = $myconn->query("SELECT * FROM tbl_newsletters");
while($listRs = $list->fetch_assoc()){
$grps = $myconn->query("SELECT * FROM tbl_newsletter_groups WHERE NID=". $listRs['NID'] ."");
while($grpsRs = $grps->fetch_asscoc()){
$subGID[] = $grpsRs['GID'];
} $grps->free();
$subs = implode(" OR GID=",$subGID);
$count = mysqli_num_rows($myconn->query("SELECT ID FROM tbl_subscribers WHERE GID=". $subs));
echo('Total Selected Subscriber: '.$count);
} $list->free();
Thanks.
The search term you want is "set-based logic".
Your thinking is sound: you need everything from tbl_newsletters, then you need to count results from tbl_subscribers, but in order to get those you need information from tbl_newsletter_groups.
In SQL, that's an indication you want a join. You've already discovered the conditions you need, you just don't know the syntax. A reference manual can help there.
Now you'll have a bunch of records, which you need to smash into a smaller number of records. You need aggregation functions and a GROUP BY clause.
So here's the final query:
SELECT n.NID, n.title, n.details, COUNT(s.SID)
FROM tbl_newsletters AS n
JOIN tbl_newsletter_groups AS g ON n.NID = g.NID
JOIN tbl_subscribers AS s ON g.GID = s.GID
GROUP BY n.NID
Related
I stumbled upon a query that I have never done until now.
Before asking the question I looked for if another user had had the same need as me but nothing.
My goal is very simple:
having two tables:
collaboratori (collaborators)
invite (invitations)
I have to count how many invitations the collaborators have made.
table structure of collaboratori:
ID_Collaboratori | cod_manager
37 4675
150 6675
3 6575
table structure of inviti:
invite_id | invite_code_manager
37 6675
39 6575
40 4675
41 6675
if I execute the join obviously I access the two tables in this way:
$q_stats_prod_manager = $connessione->prepare("
SELECT * FROM invite
LEFT JOIN collaboratori
ON collaboratori.cod_manager = invite.invite_code_manager ");
$q_stats_prod_manager->execute();
$r_stats_prod_manager = $q_stats_prod_manager->get_result();
my need lies in showing in a table:
show me for each manager who has his cod_manager inside the inviti table, the number of times he sent them.
Name Surname Manager 1 | Number of invite: 200
Name Surname Manager 2 | Number of invite: 50
Name Surname Manager 3 | Number of invite: 10
not limiting myself to just one counter but also being able to access other table values like any join
I take the liberty of putting the answer that was partially written by another user, adding a detail and explanation for future users. The resolution query for this case is the same:
$q_stats_prod_manager = $connessione->prepare("
SELECT count(invite.invite_id)
/*name of what you want to call the result you will see in the while*/
AS result_count, /*you can call this value whatever you want*/
/*Start | Values of the tables you are interested in selecting*/
collaboratori.nome,
collaboratori.data_registrazione,
invite.invite_code_manager
/*End | Values of the tables you are interested in selecting*/
FROM collaboratori
LEFT JOIN invite
ON invite.invite_code_manager = collaboratori.cod_manager group by invite.invite_code_manager
");
$q_stats_prod_manager->execute();
$r_stats_prod_manager = $q_stats_prod_manager->get_result();
$count_invite_manager=mysqli_fetch_array($r_stats_prod_manager);
$number_of_invite_manager = $count_invite_manager[0];
Select the id of the table you want to count
Give a name you wish you want to name the counted result
Select the values of the tables on which you will perform the join you want to view
Join the tables
Show the result with while
Code while:
<?php while($rowstatspm = mysqli_fetch_assoc($r_stats_prod_manager)){ ?>
<!-- this is the fancy name you associated with your query when you wrote: AS nameofwhatyouwant -->
<?php echo $rowstatspm['result_count'] ;?>
<?php } ?>
You seem to want aggregation. I assume you want all rows for collaboratori, so that should be the first table for the LEFT JOIN:
SELECT c.cod_manager, COUNT(i.invite_code_manager)
FROM collaboratori c LEFT JOIN
invite i
ON c.cod_manager = i.invite_code_manager
GROUP BY c.cod_manager;
Your question doesn't describe where the name comes from. But those fields should be in both the SELECT and GROUP BY.
SELECT count(invite.invite_id),collaboratori.name FROM collaboratori
LEFT JOIN invite
ON invite.invite_code_manager = collaboratori.cod_manager group by invite.invite_code_manager
I am trying to search two tables, match the results and then concatenate the answer... Only finding results >= today's date. This will then give the user the option to delete the selected from the DB. So...
Table 1 called Prog_name
id prog_name
1 Breakfast
2 Mid Morning
3 Afternoon
Table 2 called talk_ups
id date_tx prog_name (prog_name value = prog_name.id)
1 2017-06-30 2
2 2017-07-03 1
3 2017-07-01 3
The result I am after is something like: "01-07-2017, Afternoon". But I do also need the talk_ups.id to ensure it only deletes the correct record.
I managed to figure out how to get the name to match the talk_ups.prog_name value:
'$sql. = "SELECT talk_ups.prog_name, prog_name.id as progID, prog_name.prog_name as theName FROM prog_name, talk_ups WHERE talk_ups.prog_name = prog_name.id";'
But I can't figure out how to do the two searches and end up with the right result and how to separate out the results to then concatenate them.
You can use JOIN with WHERE condition, e.g.:
SELECT pn.id, pn.prog_name, tu.date_tx
FROM prog_name pn JOIN talk_ups tu ON pn.id = tu.prog_name
WHERE tu.date_tx > NOW();
I think this will be an easy one for those using MYSQL a lot, but I just can't quite get it...mainly through not knowing the right terminology to search for.
Basically I have a table mapping tag ids to photo ids called tag_map. When I perform this query:
SELECT * FROM tag_map WHERE tag_id='1' OR tag_id='5';
I get the following results:
ph_id tag_id
1 1
2 1
5 1
7 5
8 1
9 5
10 5
11 1
12 1
13 1
But what I really want is to only select ph_id that have a tag_id of BOTH '1' and '5'.
So, as you can probably see, I am trying to filter down selections based on multiple tags. I want to end up with:
ph_id tag_id
7 1
7 5
8 1
8 5
11 1
11 5
So ph_id 7, 8 and 11 reference tag_id 1 AND 5.
Hope that makes sense.
Thanks.
Solution
Due to the dynamic nature of my query (user selecting any number of available tags to 'narrow down selection) I went with a PHP solution, as suggested by #Y U NO WORK
Basically I get the tag_id of all selected tags from table 'tags'
Then I selected all photo ids (ph_id) that are mapped to the selected tag_ids from my table tag_map.
Then I reduce this down to ph_ids that occur the same number of times as the number of selected tags:
$numTags = count($arTagId); //$arTagId is an array of the selected tags
// get only photo ids that match both tags
$arPhId = array();
// in arPhId, find ph_ids that have occurances equal to $numTags
$arPhIdCnt = array_count_values($arPhIdAll); //$arPhIdAll is array of all ph_id that match all selected tag_ids
foreach($arPhIdCnt as $pid => $pidQty) {
if($pidQty == $numTags) {
$arPhId[] = $pid;
}
}
So I end up with an array of only the ph_ids that match both tag_ids.
Thanks for everyone's help.
You will have to join the table with itself, the code could be kinda complicated. PHP would be an easier, but not such a performant solution.
You have to join the table with itself based on ph_id, then check that the tab_id col of table1 instance equals 1 and that tab_id of table2 instance equals 5.
SELECT t1.* FROM tag_map t1, tag_map t2
WHERE t1.ph_id = t2.ph_id
AND t1.tag_id='1'
AND t2.tag_id='5';
with inner join if you prefer
SELECT t1.* FROM tag_map t1
INNER JOIN tag_map t2 on t2.ph_id=t1.ph_id
WHERE t1.tag_id='1'
AND t2.tag_id='5';
I'm currently working on a project where I have information stored in several tables that all connect to each other. I believe that the table and column format is logical and the best choice. The problem though, is that I don't have enough knowledge to build queries advanced enough to fetch all the information I need.
The main table is ab_ads, where advertisements are stored. These ads can be assigned several formats (ie. 250x360, 980x120 etc), and you can also select the region where they should be showing (ie. Skåne, Stockholm, Kalmar, Dalarna, Jämtland etc).
This is how I store my data. I'm not showing all tables but I hope this is sufficient.
Advertisements column (ab_ads): (There are more columns but they are not relevant)
ID orgnum company_name title content link
1 556664-7524 Company Inc Lorem ipsum Lorem ipsum URL
Advertisement states (ab_ads_states):
ID adID stateID
1 1 2 // Skåne
2 1 5 // Kalmar
3 1 8 // Stockholm
4 1 10 // Värmland
5 2 2 // Skåne
6 2 5 // Kalmar
7 3 8 // Stockholm
8 4 10 // Värmland
Advertisement formats (ab_ads_formats)
ID adID formatID
1 1 1 // 250x360
2 1 2 // 980x120
3 2 1 // 250x360
4 3 2 // 980x120
Formats table (ab_formats)
ID name width height
1 Format 1 250 360
2 Format 2 980 120
So, I have two flash banners both are supposed to call a PHP-script which in turn is supposed to deliver an XML-file back with all the results.
I know how to select data from different tables, but I've never worked with selecting multiple rows from another table and merging them into one, which I suppose is that I need to do here. I'm very thankful for any help I can get.
The flash banners will send two parameters to the PHP file, stateID and formatID. Which means I have to SELECT ad WHERE state = param AND format = format. But since I store multiple entries for the ad states I don't know how to do it.
EDIT:
I would also like to fetch the format names in the query and get them in the following format: "Format 1,Format 2" in a column named "formats". I guess this would require some kind of join?
Thanks in advance!
I think this will work:
select ab.name as formats, aa.* from ab_ads as aa
inner join ab_ads_states as aas on aa.id = aas.adid and aas.stateId = stateIdParam
inner join ab_ads_formats as aaf on aa.id = aaf.adid and aaf.formatId = formatIdParam
inner join ab_formats as ab on aaf.formatid = ab.id
Edit:
I'm not very good with mySql, and don't have anything to test this on, but I think group_concat may be what you are looking for. If so, it will probably look something like this:
select group_concat(ab.name separator ", ") as formats from ab_ads aa
inner join ab_ads_states as aas on aa.id = aas.adid and aas.stateId = 2
inner join ab_ads_formats as aaf on aa.id = aaf.adid and aaf.formatId in(1,2)
inner join ab_formats as ab on aaf.formatid = ab.id
group by ab.id
Please try below SQL:
SELECT count(aaf.ID) AS TotalFormat,
group_concat(ab.name) AS formats
FROM ab_ads aa
INNER JOIN ab_ads_states AS aas ON aa.ID = aas.adID
AND aas.stateID = 2
INNER JOIN ab_ads_formats AS aaf ON aa.id = aaf.adID
AND aaf.formatID in(1,2)
INNER JOIN ab_formats AS ab ON aaf.formatID = ab.ID
GROUP BY aaf.adID HAVING TotalFormat >=2
SQL Demo: http://sqlfiddle.com/#!2/9f0ab/10
Here is the mySQL I got
id terms
1 a
2 c
3 a
4 b
5 b
6 a
7 a
8 b
9 b
10 b
I want to get an alphabetized list sorted by count as follows
terms count
a 4
b 5
c 1
What mySQL statement do I need for that?
I believe something like this will work:
SELECT terms, COUNT( id) AS count
FROM table
GROUP BY terms
ORDER BY terms DESC
Read : GROUP BY (Transact-SQL)
Groups a selected set of rows into a set of summary rows by the values of one or more columns or expressions in SQL. One row is returned for each group. Aggregate functions in the SELECT clause list provide information about each group instead of individual rows.
You just need to apply group by clause for getting result
select terms, count (id) as count from table
group by terms
order by terms
I had a very similar need for a used record store to display artists in stock alphabetically with their count in parenthesis e.g.:
Smokey Robinson and The Miracles (2) | Sonic Youth (2) | Spoon (3) | Steely Dan (1) | Stevie Wonder (2) | Sufjan Stevens (1) |
Note that I used SELECT DISTINCT when pulling from my table "records". Here are the relevant code snippets:
//QUERY
$arttool = mysql_query("SELECT DISTINCT * FROM records GROUP BY artist ORDER BY artist ASC");
//OUTPUT LOOP START
while($row = mysql_fetch_array($arttool)){
//CAPTURE ARTIST IN CURRENT LOOP POSITION
$current=$row['Artist'];
//CAPTURING THE NUMBER OF ALBUMS IN STOCK BY CURRENT ARTIST
$artcount = mysql_num_rows(mysql_query("SELECT * FROM records WHERE artist = '$current'"));
//ECHO OUT.
echo $current . "($artcount)";
The actual code in my site is more complicated, but this is the bare bones of it. Hope that helps...