Sort a php array in a custom order - php

Question

I have a table called "car_owners", it has three columns known as:
id owner cars
1 Greg 1
2 Gary 3
3 Aaron 2
4 Farb 3
5 REX 1
6 Fred 2
In the following code I get it into array and print it:
$exc = $conn->prepare("SELECT name,state from current_state");
$exc->execute();
while($finalResult = $exc->fetch(PDO::FETCH_ASSOC))
{
$tables[] = $finalResult;
}
var_dump($tables);
once i get this into an array, is there a way i could sort it in a custom order where i could get the out put like follows,
first the owners with 2 cars, then with 1 car and who has 3
owner cars
Aaron 2
Fred 2
Greg 1
REX 1
Farb 3
Gary 3
P.S doing it from the table is not going to work, because im using a loop above the code which makes it impossible to do it from the SQL, can anybody tell me a way to do it from the php

Answer 1

select * from your_table
order by case when cars = 2 then 1
when cars = 1 then 2
when cars = 3 then 3
else 4
end

Answer 2

You can use usort to sort the values. This will also sort by name if two owners have the same number of cars. I have changed the SELECT statement to match the given database definition.
$exc = $conn->prepare("SELECT owner, cars from current_state");
$exc->execute();
while ($finalResult = $exc->fetch(PDO::FETCH_ASSOC))
{
$tables[] = $finalResult;
}
usort(
$tables,
function($a, $b) {
// If same number of cars, sort by name
if ($a['cars'] == $b['cars']) return strcmp($a['owner'], $b['owner']);
// If owner a has two cars, place before b
if ($a['cars'] == 2) return -1;
// If owner b has two cars, place below a
if ($b['cars'] == 2) return 1;
// Neither owner a nor owner b has two cars, sort by number of cars
return ($a['cars'] < $b['cars']) ? -1 : 1;
}
);
foreach ($tables as $row) {
echo $row['owner'], ' => ', $row['cars'], PHP_EOL;
}
Output:
Aaron => 2
Fred => 2
Greg => 1
REX => 1
Farb => 3
Gary => 3

Answer 3

If you have the array prepared from the mysql table, then you can use the following code-
$car_array=array(
"Aaron"=>2,
"Fred"=>2,
"Greg"=>1,
"REX"=>1,
"Farb"=>3,
"Gary"=>3,
);
$sort_array=array("2","1","3");
$new_array=array();
foreach ($sort_array as $key => $value)
{
foreach ($car_array as $key1 => $value1)
{
if ($value1 == $value )
$new_array[$key1]=$value1;
}
}
print_r($new_array);

Answer 4

Consider sorting the resultset through sql itself. The sql provided by #juergen would meet the purpose. The only change I would like to do in the query is that 'add owner field in the order by clause'. Consider the below code snippet
select * from car_owners
order by (case when cars = 2 then 1
when cars = 1 then 2
when cars = 3 then 3
else 4
end), owner
This should meet the purpose and give you the resultset exactly as you needed.
Also, if you explicitly need to sort it through php then you use the php usort() function and sort the array writing a custom defined function.

Answer 5

Using PHP only, you can use uksort function to sort the array using a user-defined comparison function. The following code requires a copy of your $tables variable.
<?php
$tables2=$tables;
uksort($tables2, function($r1, $r2) use ($tables) {
return ($tables[$r1]["cars"]%3) < ($tables[$r2]["cars"]%3);
});
print_r($tables2);