Insert an array and show value in PhpMyAdmin - php

Question

I am using checkboxes to see if a user wants "Breakfast,Dinner and Supper"
This is my code for that
<div id="checkboxesFood">
<p>Please select if you want breakfast, dinner and supper</p>
<input type="checkbox" class="food" name="foodboxes[]" value="Breakfast"/>Breakfast
<input type="checkbox" class="food" style="margin:0 0 0 19%;" name="foodboxes[]" value="Dinner"/>Dinner
<input type="checkbox" class="food" style="margin:0 0 0 19%;" name="foodboxes[]" value="Supper"/>Supper
</div>
I'm using PHP to connect to a DB and store the value there.
This is my PHP code
$username = $_POST['userName']; //Username
$view = $_POST['roomChoice']; //View Of Room
$paymentMethod = $_POST['payment']; //How user want's to pay
$selectedFood = $_POST['foodboxes']; //Food they have selected(Breakfast, Dinner or Supper)
//$foodData = array($selectedFood);
$con = new mysqli('localhost','username','mypw','DB');
if($con->connect_error){
die("Connection failed: " .$con->connect_error);
}
//$implodedData = implode(",",$foodData);
$sql = "INSERT INTO Hotellbokning(Name,Room,Food,Payment) VALUES('$username','$view','$implodedData','$paymentMethod')";
if($con->query($sql) == true){
echo "You did it John!";
}
else{
echo "Error: " . $sql . "<br/>" .$con->error;
}
Just ignore the variables that is not an issue. When I insert this array $selectedFood into my DB, I recieve the value "Array" on my Food-field.
Is there a way to see the value of this array(the three values Breakfast,Dinner and Supper) in PhpMyAdmin, or is it only possible to echo them out from my DB?
P.S. I tried using implode but it didn't work. I've also tried $foodData = array($selectedFood) But it didn't work either.

Answer 1

You're imploding the wrong thing. $selectedFood is already an array, you don't need to wrap it in another array. So it should be:
$implodedData = implode(',', $selectedFood);
Then you can store $implodedData in the database.
However, putting comma-separated lists in a database is generally poor design. You should use a relation table with a separate row for each item.