Deleting img tag from string - php

Question

I've got a string, $content, that contains:
<p>Some random text <img class="alignnone" src="logo.png" alt="" width="1920" height="648"></p>
Now I want to delete the image tag:
<img class="alignnone" src="logo.png" alt="" width="1920" height="648">
I tried strip_tags but that isn't working anymore.
$content = strip_tags($content, '<img></img>');

Answer 1

Here is a complete working example.
<?php
$content = "<p>Some random text <img class=\"alignnone\" src=\"logo.png\" alt=\"\" width=\"1920\" height=\"648\"></p>";
echo strip_tags($content,"<p>");
?>

Answer 2

If <p></p> is the only other tag you'll have you can use strip_tags like this:
$content = strip_tags($content, '<p></p>');
If there may be other tags you want to keep, just add them to the second argument of strip_tags
You can also use a combination of string functions to achieve this:
$count = substr_count($c, '<img ');
while($count >= 1){
$i = strpos($c, '<img ');
$j = strpos($c, '>',$i)+1;
$c = substr($c, 0,$i) . substr($c,$j);
$count--;
}
echo $c;
This also takes care of multiple <img> tags

Answer 3

You could search for the img-Tags with the strpos()-function:
http://www.w3schools.com/php/func_string_strpos.asp
Once you know the start- and ending-position inside the string you can access the parts you need with the substr()-function:
http://php.net/manual/de/function.substr.php
In your example:
$left = strpos($content,'<img');
//$left should now be "20"
//to find the closing >-tag you need the string starting from <img... so you assign that to $rest:
$rest = substr($content,(strlen($content)-$left+1)*(-1));
$right = strpos($rest,">")+$left;
//now you know where the img ends so you can get the string surrounding it with:
$surr = substr($content,0,$left).substr($content,(strlen($content)-$right)*(-1));
Edit: Tested, will work for deleting the first img-Tag