I'm trying to use SimplePies "$feed->set_feed_url (array());" function but I am having major difficulty understanding why it wont accept my values.
When I add the URLS manually (i.e directly below), they work just fine. The feeds go through ok and displays the feeds as needed.
$feed ->set_feed_url (array(
'http://www.theverge.com/tag/rss',
'http://feeds.ign.com/ign/all'
));
I have URLS in a database table that I am pulling out like normal with a while loop. I then append a comma and remove the trailing comma so its nice for the SimplePie array. Like so:
while($row = mysqli_fetch_array($pullAllAccountsDoIt)){
$result4mdb .= $row[0] . ",";
}
$result4mdb = substr($result4mdb, 0, strlen($result4mdb) -1);
echo "the result is: " . $result4mdb;
When I do this, and echo out "$result4mdb", it prints out: the result is: http://www.gamespot.com/feeds/mashup/,http://www.theverge.com/tag/rss
Meaning that the variable is good and printing out what i need. So far so good.
I then go into the simplePie code, put in my varialble like so:
$feed ->set_feed_url (array($result4mdb));
and nothing happens. I don't get any errors or anything, just that the page stays blank and nothing comes up.
For testing, I do a gettype($result4mdb); and it tells me that the variable is a "string" and again, the output of this variable when echoed is the URLS it got from the database so I KNOW that the whole process so far is working.
For further testing, I go to the database and remove one of the URLS so that when queried, that it returns one value, and all of the sudden SimplePie works.
I've been searching for a good day and a half now, trying different things and googling as much as possible but to no avail. I just cant quite get it.
I'm at my wits end. Any assistance as to why this isn't working is GREATLY appreciated.
Thank you in advance everyone
You're just producing a string containing comma seperated values. What you need is an array, so just explode() your string:
Change:
$feed ->set_feed_url (array($result4mdb));
to
$feed ->set_feed_url (explode(',', $result4mdb));
More elegant version, change:
while($row = mysqli_fetch_array($pullAllAccountsDoIt)){
$result4mdb .= $row[0] . ",";
}
to
while($row = mysqli_fetch_array($pullAllAccountsDoIt)){
$result4mdb[] = $row[0];
}
This way you're not creating a string that needs to be exploeded, but create an array at first.
Related
Hoping this is a simple and easy question. I've seen multiple examples of, and know how to append variables to the URL (i.e. mydomain.com/index.php?id=1&stat=0), but my question is this:
If I have a page on my site that already has variables in the URL (i.e. mydomain.com/tickets.php?stat=Open), how can I append a page number to the end of that URL (i.e. mydomain.com/tickets.php?stat=Open&page=2). This is for pagination purposes of a table with values from my database, that includes a search and select function (select open, closed, or all tickets, and search for a specific ticket number).
I've done several searches with google, and came up dry, as most topics regarding this have you hardcode the url with variables from the get go, and not append them. I may just be using the wrong search parameters as well, and am not sure what to search for exactly.
Any help or insight on this would be greatly appreciated, thank you.
Please note I wish to do this solely in PHP, HTML, and MySQLi. I want to refrain from using javascript or ajax if possible for my clients that may have those features disabled on their browsers.
Using this way:--
<?php
$domain = "mydomain.com";
$page = "tickets.php?";
$full_page_url = $domain.'/'.$page;
$arr = array('stat' => 'Open', 'page' =>2);
$add= http_build_query($arr);
$correct_url = $full_page_url. $add;
echo $correct_url;
?>
output:--mydomain.com/tickets.php?stat=Open&page=2
I would do it like this:
$page = 2;
$url = 'mydomain.com/tickets.php?stat=Open';
if( false !== strpos($url, '?')){
//if url has a ? split it.
$arr_url = explode('?', $url);
//convert query string to array, $array=['stat'=>'Open']
parse_str($arr_url[1], $array);
//add or replace page by array key
$array['page'] = $page;
//convert it back to a query string.
$query = http_build_query($array);
print_r($query);
}
Outputs
stat=Open&page=2
It's a simple matter of putting $query back with $arr_url[0] I'll leave this up to you. But I will give you a hint $arr_url[0].'?'.$query
The advantage here is that you don't have to worry about getting into a situation where you are adding page after page after page after...
Like this:
mydomain.com/tickets.php?stat=Open&page=1&page=2&page=3
You can't simply concatenate it onto the end of the url, and it's probably just as hard to remove it as it is to parse the query string.
As a side note, you could just use $_GET but where is the fun in that, as $_GET is the query string already parsed as an array ( so you could skip parse_str). But it may not be on a request, such as if you were just building the link from a string.
So I thought I would show it with parse_str to cover the "harder" case.
One last thing if you are just building a bunch of urls all the same except the page part. The obvious answer is to setup a base url and then just loop out the numbers.
$url = 'mydomain.com/tickets.php?stat=Open';
$pagedUrls = [];
$numberPages = 10;
for($i=1; $i<=$nubmerPages; $i++){
$pagedUrls[] = $url.='&page='.$i;
}
Or what have you for the number of pages.
It's really not that clear in your question exactly what you are trying to do..
Hope that helps.
I'm trying to pull each of the viewer names from a JSON file in PHP.
I've looked around the Internet extensively for a working example that will offer me the result I desire without much success.
I'm really struggling to find an example that fits my needs on the Internet to help me with what is likely a very simple thing to accomplish.
I've got a JSON file that spits out several values on the Internet and I'm looking to extract every single line from one particular section.
Seeing a working example will likely help me understand what I am doing.
The JSON file that I am using for example is:
https://tmi.twitch.tv/group/user/dansgaming/chatters
I am trying to extract each single line from the "viewers" section in this file.
I've captured the data using the following PHP:
$testviewers = json_decode(#file_get_contents('https://tmi.twitch.tv/group/user/' . $streamName . '/chatters'), true);
var_dump($testviewers['chatters']['viewers']);
It turns out this isn't having the desired result for me.
I simply want each line in the viewer's section to be echoed out with page breaks.
What am I doing wrong? I've tried about two hundred different approaches to this one and have to admit this is my first real time working with JSON.
I've tried to search the Internet for answers and found many tutorials but none have made any sense to me and I know that seeing how to accomplish the result will help me learn exactly what should be going on.
In an ideal world, it will simply output each "viewer" on a separate line that I can work with. If I could echo each of them and then concatenate with a page break or the word "viewer:" before each one this would be a huge help and I'll be able to take it further and likely learn a great deal in the process.
this my way echo from json
$json = json_decode($response, true);
foreach($json['chatters'] as $key => $value)
{
if(!empty($value['viewers']))
{
$VIEWER = $value['viewers'];
$VIEWER = addslashes($VIEWER );
$VIEWER = trim(preg_replace('/\s\s+/', ' ', $VIEWER ));
}
else
{
$VIEWER = '';
}
echo 'VIEWER = '.$VIEWER .'</br>';
}
just make sure the foreach is true, maybe can help.
Turns out the issue here was a PHP error that wasn't displaying. The code was timing out because of how large the JSON file was and a low limit on my machine.
I think this is what you want....
$array = json_decode($your_json,true);
foreach($array['chatters']['viewers'] as $r) echo $r.'<br>';
I am trying to put content into an array. The content, around 100 urls, is already stored in a variable that I call $arraycontents which is formatted with ",". For some reason the array get cuts of when I do this but it works when I put in the urls manually. Very annoying problem.
Here is the code:
$arraycontents = '"http://archive.org/wayback/available?url=' . implode('","http://archive.org/wayback/available?url=',$matches[0]). '"';
$urls = array($arraycontents);
in the error message I get it looks like the array is cut off.
$matches[0] contains "urls" already an array, so prefix all with (if I guess right what OP wants)
$urls = array_map(function($m) {
return 'http://archive.org/wayback/available?url='.$m;
},$matches[0]);
I am trying to convert a drupal installation into a front end driven by Code Igniter. This is an experimental project to check the performance boost I can get. But the biggest problem I am facing is that few fields in Drupal store php string as it is. For example
<?php print "A"; ?>
This is normal
Now I am able to see the text "This is normal" which comes from the query that I run in Code Igniter, but I don't see the php function which is saved inside the table. I can see the text when I view the record through phpmyadmin. But somehow not inside the CI query result.
I hope U've got the solution. But just in case if you haven't try this:
I created a table with two columns
//$result Contains the data fetched from the table using a model.
foreach ($result as $key=>$val) {
if($key == 'code') {
$val = str_replace('<?php','',$val); //Remove PHP's opening tag.
$val = str_replace('?>','',$val); //Remove PHP's closing tag.
$val = rtrim($val); //Remove leading and trailing spaces.
echo $key.': ';
eval($val.';'); //Execute the PHP code using eval.
} else {
echo $key.': '.$val.PHP_EOL;
}
}
I tried
echo $result['code']
print_r($result)
var_dump($result)
highlight_string($result['code'])
eval($result['code'])
and finally str_replace followed by eval($result['code']).
Check the screen shot of the result obtained from: here
There you can see that the Result produced by 1,2, and 5 are empty. But when you inspect element against the empty space It'll clearly show that the string that's echoed/print is commented out.
Screen-Shot. This is has nothing to do with codeigniter. Its done by HTML Parser.
So the solution is to remove the opening and closing tags of PHP and then use eval. I hope this helps.
Thanks for the help. Yes, the last resort was the eval function and that is the one which helped me attain which I was wanting it to do.
The data which was inside the database had PHP function and only eval function was able to treat that part as a PHP code and execute it when I was getting the data inside my view.
I'm having this problem that's driving me nuts.
I've got a MySQL database in which there is a table that contains a text field. I am querying the table in PHP and trying to put the content of the text field for each row into a var.
I am doing something like this:
for ($i=0;$i<$nbrows;$i++){
$id = $data[$i]['ID'];
$description = $data[$i]['DESCRIPTION'];
$mystring .= '<div>'.$id.': '.$description.'</div>';
}
DESCRIPTION is my text field.
I'll pass on the details. The $data array is built from mysql_fetch_array($result). I also tried using objects instead, as I use mysql_fetch_object for all my other routines, but there is no change.
Anyway, the problem is this: if I do "echo $description;" then it works. I am getting my text field data as expected. The problem is that I don't want to output it directly, but add it to a concatenated string, and that is not working. What happens in that case is it seems to be taking $description for some kind of array or object. To make the above example work, I have the replace the string with:
$mystring .= '<div>'.$id.': '.$description[0].'</div>';
So in the concatenated string code, if I treat $description as an array, it works, but obviously I am getting only one letter. (it doesn't actually seem to be an array because I can't implode it).
I tried a million things but I just can't make this work unless I use echo, but that is not what I am trying to do.
There is no issue with fields that aren't text.
Thanks for any ideas!
There is nothing visually wrong with the code you pasted, maybe if you could also add the fetching function as well, we might be able to help you further.
Maybe you could post a var_dump of your $data array?
Have you tried $mystring .= "<div> $id : $description </div>";
Ack, well, you know, hours spent on this and then it becomes obvious after I decide to post for help. This is just because of text encoding/escaping and nothing else. I just didn't see well enough where the problem was actually happening.
Thanks for taking the time to read and respond!