Repitition of selected item in dropdownlist in PHP - php

Question

I have this problem that the selected value in my dropdownlist is showing twice. What should i do so that it will show only once.
<td>
<select class="span8" style="width:100%" name="from_time[]" id="from_time<?php echo $count;?>" value="start_from" onchange="calculate_by_ajax(this.id);">
<option value="<?php
$start_from=$jobs_result['start_from'];
//$date_arr_to= explode(" ", $start_from);
//$date_to= $date_arr_to[0];
//$time_to= $date_arr_to[1];
$sec="SELECT DATE_FORMAT('$start_from', '%H:%i') as tp";
$sec_exe=mysql_query($sec);
$sec_res=mysql_fetch_array($sec_exe);
?>" selected="selected">
<?php echo $sec_res['tp']; ?></option>
<?php include("list.php"); ?>
</select>
</td>

Answer 1

Got it, instead of modifying one of the available options and marking it as selected, you actually add another option with your code.
You could change list.php to look like this (i.e. an array of all the times)
<?php
$drop_down_values = array('11:35', '11:36', '11:27');
?>
Then your code should look like this:
<?php
include("list.php");
$start_from=$jobs_result['start_from'];
$sec="SELECT DATE_FORMAT('$start_from', '%H:%i') as tp";
$sec_exe=mysql_query($sec);
$sec_res=mysql_fetch_array($sec_exe);
?>
<td>
<select class="span8" style="width:100%" name="from_time[]" id="from_time<?php echo $count;?>" value="start_from" onchange="calculate_by_ajax(this.id);">
<?php foreach ($drop_down_values as $value) {
if ($value == $sec_rec) {
echo "<option selected=\"selected\">$value</option>";
} else {
echo "<option>$value</option>";
}
}
?>
</select>
</td>