I tried to print the Mysql fetched rows into html table using php. However, when using the following code, the first fetched row is repeatedly printing. It looks like the $row hold the first fetched value. I found a similar problem here. But I would like to know about working with the for loop. Thanks
for ($j=0;$j<=$len2;$j++)
{
$sql = "SELECT * FROM database_search WHERE gene_id LIKE'%$key%'";
$qry = $dbo->prepare($sql);
$qry->execute();
$row = $qry->fetch(PDO::FETCH_ASSOC);
$val = array_values($row);
echo "<tr>";
for ($k=0;$k<=4;$k++)
{
$x=$val[$k];
echo "<td style=font-size:7.9px>$x</td>";
}
echo "</tr>";
}
<table>
<?php
while($row = $qry->fetch(PDO::FETCH_ASSOC)){
echo '<tr>';
foreach($row as $cell){ echo '<td>'.$cell.'</td>'; }
echo '</tr>';
}
?>
</table>
After fetching the query as $row variable, you need to use the following code instead
foreach($row as $tr) {
echo "<tr>";
echo "<td style=font-size:7.9px>".$tr['col1']."</td>";
echo "<td style=font-size:7.9px>".$tr['col2']."</td>";
echo "</tr>";
}
This is possible that $row only have one record fetching from database and than your for ($k=0;$k<=4;$k++) loop print that only one record 5 time
because you are using print under this loop, this loop will run 5 time.
Try the following code.
foreach($row as $val) {
echo "<tr>";
echo "<td style=font-size:7.9px>".$val['column Name']."</td>";
echo "</tr>";
}
Related
I use a MySql query to select data from my DB and then print it in the form of a HTML Table. It works perfectly, fine but sometimes the table consists of hundreds of rows and the webpage looks incredibly akward. Is there a way to split the table side by side into 2 or 3 halves.
Present Output
Desired output
PHP
<?php
....
echo "<h3>Classes attended :</h3>";
echo "<table class='dates' border='1'>";
foreach ($results as $dates) {
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
}
echo "</table>";
?>
What would be the best way to achieve it?
Help would be appreciated.
You can use PHP to determine in your loop if the loop index is divisible by a certain number using something like this:
echo "<h3>Classes attended :</h3>";
echo "<table class='dates' border='1'>";
$rowCount = 1;
$numRows = count($results);
$maxRows = 12;
foreach ($results as $dates) {
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
if($rowCount % $maxRows == 0 && $rowCount != $numRows) {
echo "</table><table class='dates' border='1'>";
}
$rowCount ++;
}
echo "</table>";
That's the basics of doing this. Basically in your loop you're testing each index to see if it's divisible by $maxRows, and if so then you're going to close your table and open a new one. You'll have to add the styling to place the tables side by side.
If you wanted to expand upon this concept you can set $maxRows to be an evaluation of $numRows. For instance if you wanted to split the items as close as possible to half in order to show just two tables, you could do... $numRows = count($results); $maxRows = round($numRows / 2);
Inspired by Robert Wade's answer:
<?php
....
echo "<h3>Classes attended :</h3>";
$i=0;
$maxRows=10;
foreach ($results as $dates) {
$a=$i/$maxRows == 0 ? "<table class='dates' border='1'>":"";
$b=$i/$maxRows == 0 ? "</table>":"";
echo $a;
echo "<tr><td width='50%'>";
echo $dates->db_date;
echo "</td>";
echo "<td width='50%'>";
echo $dates->day_name;
echo "</td>";
echo "</tr>";
echo $b;
$i++;
}
?>
At last, add some css style to the tables.
You can also use array_chunk() for splitting your results. Or instead of displaing a lot of tables next to each other you can make pagination and get only some range in your query. For example:
SELECT * FROM `clients` LIMIT 5, 10
Selects 10 rows beggining from row 5. Now, when you change your page, just change limit values.
When I add my first record into the database table, it doesn't show on the page where the records are displayed. But when I add the second record and on, they are displayed on the page except the first record that I entered.
Here is my code:
$result = mysql_query("SELECT * FROM members ORDER BY player_role DESC", $db);
while ($row = mysql_fetch_array($result))
{
echo "<table>";
echo"<tr><th><B>Player Name</B><Th><B>Role</B></TR>";
while ($myrow = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>". $myrow['player_name']. "</td>";
echo "</td>";
echo "<td>" .$myrow['player_role']. "</td>";
echo "</tr>";
}
echo "</table>";
}
Can someone please tell me what is wrong?
It may be caused by nested while() loop. No need to use nested while(). Use one while() instead. Example:
$result = mysql_query("SELECT * FROM members ORDER BY player_role DESC", $db);
echo "<table>";
echo"<tr><th><B>Player Name</B></th><th><B>Role</B></th></tr>";
while ($row = mysql_fetch_array($result))
{
echo '<tr><td>'.$row['player_name'].'</td><td>'.$row['player_role'].'</td></tr>';
}
echo "</table>";
Player Name and Role should not be inside while() loop.
MOST IMPORTANT Do not use mysql, it is deprecated. Instead use mysqli
Your code (changed)
$result = mysqli_query($db,"SELECT * FROM members ORDER BY player_role DESC");
echo "<table>";
echo"<tr><th><B>Player Name</B></th><th><B>Role</B></th></tr>";
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo '<tr><td>'.$row['player_name'].'</td><td>'.$row['player_role'].'</td></tr>';
}
echo "</table>";
Is there a php or html code to dynamically generate a table.
query :
"SELECT * FROM table1;
Can I display this grid of info without any specifics.
IF there are 4 rows and 4 columns I want the table to be that size; if 5x5 than that.
It seems like this should be possible, but all code I can find wants me to specify names or columns.
Yes. There are a couple different ways to do this, but for illustration I will assume that the result of your query is stored in a variable called $results, which is simply a multidimensional array that you can loop through using a double foreach to dynamically produce your table.
echo '<table>';
foreach ($results as $row) {
echo '<tr>';
foreach ($row as $col) {
echo '<td>' . $col . '</td>';
}
echo '</tr>';
}
echo '</table>';
OR if you don't have a $results array and are instead getting query results and building the table at the same time, something like this might be more appropriate for your needs:
echo '<table>';
while ($row = mysqli_fetch_array($query)) {
echo '<tr>';
foreach ($row as $col) {
echo '<td>' . $col . '</td>';
}
echo '</tr>';
}
echo '</table>';
echo'<table>';
while($row = mysql_fetch_array($result))
{
echo'<tr>';
echo '<td>'.$row[colname].'</td>';
echo '</tr>';
}
echo'</table>';
The code below creates html table data.
Row 1 is correct and returns column1 with $row['LNAME'] and then column2 with ALL of the $row1['NAME'] results (there are four).
Row 2 and onwards echo only column1 and an empty cell in column2.
while ($row = $sql->fetch_assoc()){
echo "<tr>";
echo "<td>";
echo $row['LNAME'];
echo "</td>";
echo "<td>";
while($row1 = $sql1->fetch_assoc()){
echo $row1['NAME'] . "<br>";
}
echo "</td>";
echo "</tr>";
}
It would seem that after the inner loop has completed it evaluates as false in future iterations of the outer loop where I would like it to evaluate as true.
What should I change so that the inner loop does not evaluate as false until the outer loop does?
This is because you're at the end of $sql1. You can seek to the beginning of it again, but my preference is to separate pulling the data from the DB and the iterations, so I'd write it like this (using your code as the starting point):
$lname = array();
while($row = $sql->fetch_assoc()){
$lname[] = $row;
}
$name = array();
while($row1 = $sql1->fetch_assoc()){
$name[] = $row1;
}
foreach($lname as $lvalue) {
echo "<tr>";
echo "<td>";
echo $lvalue;
echo "</td>";
echo "<td>";
foreach($name as $value) {
echo $value . "<br>";
}
echo "</td>";
echo "</tr>";
}
you will need to use mysql_data_seek($rs, 0) to reset your result pointer at the first row. this is under the assumption that mysql is hidden behind your object. for mysqli use mysqli_data_seek respectively
I have a database of images which I want to output as a gallery ...
I want to display each image in its own cell <td>image1</td> and limit the number of cells to 7 per row.
<tr>
<td>image1</td><td>image2</td><td>image3</td><td>image4</td><td>image5</td><td>image6</td><td>image7</td>
</tr>
Then a new row would be created and continue to output all the images.
<tr>
<td>image8</td>
and so on ..
I know how to do a query, but I am lost as to how to assemble the rows into the format I am looking for.
Can anyone please help me it would be greatly appreciated. Thanks.
First run your query, then get the mysql_fetch_assoc in a variable. Then echo your beginning tags for the table and tr. Then create a foreach loop of the query assoc, as another variable such as row, and echo $row['image'] in a td. This will add a new td with the image for every entry in the database. Then echo your closing tags for the tr and table.
$query = mysql_query("SELECT image FROM table_name");
$query_a = mysql_fetch_assoc($query);
echo "<table><tr>"
foreach ($query_a as $row)) {
echo "
<td>" . $row['image'] . "</td>
";
}
echo "</tr></table>";
Not tested, but try something like this
<table>
<?php
// make sure there is at least 1 row first
$cnt = 0;
$while($row = mysql_fetch_assoc($query))
{
if(++$cnt == 1) {
echo '<tr>';
} elseif($cnt % 7 == 0) {
echo '</tr><tr>';
}
// show images in <td>'s
echo "<td>" . $row['image']. "</td>";
}
echo '</tr>';
?>
</table>
Keep it simple:
Query the database to get the desired information, loop through the results, construct a new row come each new loop.
$sql = "Select * from table";
mysql_query($sql) or die(mysql_error());
if(mysql_num_rows !=0)
{
// Found at least one record, create table
echo "<table>";
echo "<tr>";
while($row = mysql_fetch_assoc($sql)
{
$cell_count = 0;
// Create a new row for each record found
echo "<td>" . $row['image_column']. "</td>";
$cell_count++;
if($cell_count == 7)
{
echo "</tr>";
echo "<tr>";
$cell_count = 0;
}
}
// Close the table
echo "</tr>";
echo "</table>";
}