checkboxes generated dynamically not inserting all values into array - php

Question

I have a query that selects all of the users in a database that are not approved.
$query = "SELECT * FROM users WHERE approved = '0';
$data = mysqli_query($dbc, $query);
Then, what I want to do is display that list of people in a table that has a column with a checkbox to approve that person.
<table class="table mb-none">
<thead>
<tr>
<th>Picture</th>
<th>Username</th>
<th>Profile Type</th>
<th>First Name</th>
<th>Last Name</th>
<th>Email</th>
<th>Phone Number</th>
<th>Approve</th>
<th>Deny/Delete</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_array($data)){
echo '<tr>'
echo '<td><img width="70px" height:"90px" src="' . EHS_UPLOADPATH_STUDENTS . $row['picture'] . '"/></td>';
echo '<td>' . $row['username'] . '</td>';
echo '<td>Student</td>';
echo '<td>' . $row['first_name'] . '</td>';
echo '<td>' . $row['last_name'] . '</td>';
echo '<td>' . $row['email'] . '</td>';
echo '<td>' . $row['phone_number'] . '</td>';
echo '<td style="text-align:center; padding:20px; background-color:#DFF0D8;">';
echo '<input type="checkbox" name="approve[]" value = "'.$row['user_id'].'"></td>';
echo '<td style="text-align:center; padding:20px; background-color:#FCDEDE;"><button type="button" class="mb-xs mt-xs mr-xs btn btn-danger">Deny/Delete</button> </td>';
echo '</tr>';}
This is how I am trying to process this:
if(isset($_POST['submit'])){
if(!empty($_POST['approve'])){
$users = $_POST['approve'];
foreach($users as $user){
$query = "UPDATE users SET approved = '1' WHERE user_id = '". $user . "'";
mysqli_query($dbc, $query);}}} ** here goes the rest of the code
Now, the problem I am having is that when I click on the "approve" checkboxes and hit "Submit" only the first item in the array approve[] is being processed and not the rest. I have no idea why. I have been thinking about this for the last 2 hours and can't figure it out.

Answer 1

try the following approach :
if(isset($_POST['submit'])){
if(!empty($_POST['approve'])){
foreach($_POST['approve'] as $user){
$query = "UPDATE users SET approved = '1' WHERE user_id = '". $user . "'";
mysqli_query($dbc, $query);}}} ** here goes the rest of the code
If that does not work ,do a print_r($_POST['approve']) and see what the contents of the array are.

Answer 2

I found the solution... I put the closing bracket for the "foreach" in the wrong place. Thanks for your help!