I have an issue with a json string.
I send this json string in Postman,
{
"places": [
{
"longitude": "79.9304633",
"latitude": "6.720229199999999",
"city": "Panadura"
},
{
"longitude": "79.86296829999999",
"latitude": "6.855948499999999",
"city": "Dehiwala"
}
]
}
But in the server side, when I get this value using this,
$jsonPlaces = $_POST['jsonplaces'];
and the value of $jsonPlaces looks like this,
{\\\"places\\\":[{\\\"longitude\\\":\\\"79.9304633\\\",\\\"latitude\\\":\\\"6.720229199999999\\\",\\\"city\\\":\\\"Panadura\\\"},{\\\"longitude\\\":\\\"79.86296829999999\\\",\\\"latitude\\\":\\\"6.855948499999999\\\",\\\"city\\\":\\\"Dehiwala\\\"}]}
therefore json_encode() function doesn't work for the above string since json syntax is changed.
How to fix this issue?
Thanks
Use stripslashes($_POST['jsonplaces']) to remove additional slashes.
Probably Postman uses the addslashes method to escape the (JSON) string before inputing it in the DB, as mentioned in comment, you should use the inverse function stripslashes to un-escape the string before doing the json_decode function
Related
when i use....
var jsonData = JSON.parse(xhttp.responseText);
i get an error => "JSON.parse: unexpected non-whitespace character after JSON data at line 1 column 50 of the JSON data"
this is my JSON data from a php script
{"results":[{"oldID":5,"oldMain":"News papers"}]}{"results":[{"oldID":3,"oldMain":"Construction"}]}{"results":[{"oldID":2,"oldMain":"Banking Files"}]}{"results":[{"oldID":1,"oldMain":"Technologies"}]}
Can some please help?.... Thanks
A little bit late to the party, but #igniz87 and #Benjamin James Kippax's answers open your website to security issues, and it is so dangerous to follow their example.
As Owasp reads,
ALWAYS RETURN JSON WITH AN OBJECT ON THE OUTSIDE
Hence, so as to be a layer protected from the barbarism of hackers, you need to ALWAYS have the outside primitive be an object for JSON strings. As you can clearly see, the mentioned people's answers do not follow this crucial security rule.
Owasp, moreover, brings an example and says that a JSON like the following is EXPLOITABLE:
[{"object": "inside an array"}]
Yet, the following JSONs are not,
{"object": "not inside an array"}
{"result": [{"object": "inside an array"}]}
You need to remove the duplicate key element and change it in the following way so you will have an object on the outside.
{
"results": [{
"oldID": 5,
"oldMain": "News papers"
}],
"resultss": [{
"oldID": 3,
"oldMain": "Construction"
}]}
Here, actually you should have brought you php code, as the problem is with that php code which is sending the JSON. When you want to send the JSON try to make an array of your data. I do the following way.
$data = [];
foreach ($results as $res) {
$t = [];
$t['oldID'] = $res['oldID'];
$t['oldMain'] = $res['oldMain'];
$data[] = $t;
}
echo json_encode(['results' => $data]);
You'd better send your php code which is lacking here. My php script does not contain all of your code, but it gives you idea how to do it.
I have had the same problem for the past several years.
Sometimes the problem is not related to invalid JSON .. like me now.. the problem is that I must use stringify before JSON.parse
var db = JSON.stringify(data);
var db = JSON.parse(db);
And sometimes in php you must use json_encode($data) correctly.
And sometimes your JSON is not valid ( Online JSON Validator )
The JSON is not valid. If it is possible, you can update the JSON as following
{
"results": [{
"oldID": 5,
"oldMain": "News papers"
}],
"resultss": [{
"oldID": 3,
"oldMain": "Construction"
}]}
And also JSON should not contain duplicate key elements. Also you can club the JSON to JSONArray like this
[{
"results": [{
"oldID": 5,
"oldMain": "News papers"
}]
},
{
"results": [{
"oldID": 3,
"oldMain": "Construction"
}]
}]
it's not a valid json, you must wrap it in array. the valid json is like this
[{
"results": [{
"oldID": 5,
"oldMain": "News papers"
}]
}, {
"results": [{
"oldID": 3,
"oldMain": "Construction"
}]
}, {
"results": [{
"oldID": 2,
"oldMain": "Banking Files"
}]
}, {
"results": [{
"oldID": 1,
"oldMain": "Technologies"
}]
}]
take a look at the bracket [ ] at the start and the end of string , and the , to split the object.
this some online json linter here to check if your json is valid.
Your code is invalid.
Your code;
{"results":[{"oldID":5,"oldMain":"News papers"}]}{"results":[{"oldID":3,"oldMain":"Construction"}]}{"results":[{"oldID":2,"oldMain":"Banking Files"}]}{"results":[{"oldID":1,"oldMain":"Technologies"}]}
Your code validated;
[{"results":[{"oldID":5,"oldMain":"News papers"}]},
{"results":[{"oldID":3,"oldMain":"Construction"}]},
{"results":[{"oldID":2,"oldMain":"Banking Files"}]},
{"results":[{"oldID":1,"oldMain":"Technologies"}]}]
The problem is that you had multiple JSON root elements. These also weren't comma separated. They also need wrapping in [], which will turn it into an object. If you don't want to wrap your response in [], you can return the string without the [] and instead do this;
JSON.parse('['+yourreponse+']') which will parse the JSON correctly.
Above answer are correct i.e. your json syntax is incorrect. Correcting your syntax would solved the problem (as suggested)
My case was a little different. I was returning json in response to ajax calls. Those jsons where returned by php using a if else construct. Where I mistakenly omitted one else;
if (!empty($_GET['arg1']))
echo getTrainings($filter, 'arg1');
elseif (!empty($_GET['arg2']))
echo getTrainings($filter, 'arg2');
if (empty($_GET['arg3']))
echo getTrainings($filter, 'arg3');
elseif (empty($_GET['arg4']))
echo getTrainings($filter, 'arg4');
So in fact two json where being returned instead of one, that caused problem for $.parseJSON(result);
var par = $.parseJSON(result);
From MySQL row, I have this json formatted data:
$row['details'] =
{
"previous_employer":[
{"employer":"string1","address":"address1"},
{"employer":"string2","address":"address2"},
{"employer":"string3","address":"address3"}],
"profile":[
"firstname":"John",
"lastname":"Adams",
"gender":"male",
"age":"35",
"contact":"123456789"]
}
I want to extract employer and address on the previous_employer array of objects,
but when I do this:
$json = json_decode($row['details'],true); //decode into array
foreach($json['previous_employer'] as $d){
echo "employer:".$d['employer']."<br>address:". $d['address']."<br>";
}
it gives me an error of
Warning: Invalid argument supplied for foreach()
How can I fix this? Pls advise.. thanks!
You JSON is invalid, "profile" must be
An Object:
"profile": {
"firstname": "John",
"lastname": "Adams",
"gender": "male",
"age": "35",
"contact": "123456789"
}
or an Array of Object (here his length == 1)
"profile": [{
"John",
"Adams",
"male",
"35",
"123456789"
}]
or a Simple Array (not associative array/map)
"profile": [
"John",
"Adams",
"male",
"35",
"123456789"
]
Now, your posted code will work as a charm without any modifications ... :)
json_decode() does not necessarily succeed (just imagine you feed it with complete garbage, why should it return something?). You need to do the following error checking:
Verify its return value:
Returns the value encoded in json in appropriate PHP type. Values
true, false and null are returned as TRUE, FALSE and NULL
respectively. NULL is returned if the json cannot be decoded or if the
encoded data is deeper than the recursion limit.
If valid data can be expected to return null some times, call json_last_error() and check whether it's JSON_ERROR_NONE.
Last but not least, you can explore any variable with var_dump(). You don't need to make assumptions about its content.
I want to decode gallery array JSON objects in Laravel 5.1. my JSON is:
{
"title": "aaaaaaaaaaaaaaaa",
"category_id": "1",
"user_id": "1",
"gallery": "[{name: \"XCB808tvXNpqXKqekA2HlkJ8H.jpg\",size:5112},{name: \"s6kA6B0e5m1sdSAjPXqNwtiy4.jpg\", size: 13135}]"
}
When I use this code, return me null:
public function store(Request $request)
{
$json = json_decode($request['gallery'],true);
return $json;
}
}
and this is dd($request['gallery']) result
[{'name': "XCB808tvXNpqXKqekA2HlkJ8H.jpg",'size':5112},{'name': "s6kA6B0e5m1sdSAjPXqNwtiy4.jpg", 'size': 13135}]
The decoding process is right. I think your problem is you could have a malformed JSON string.
Replace the single quotes around property names with double quotes:
[{"name": "XCB808tvXNpqXKqekA2HlkJ8H.jpg","size":5112},{"name": "s6kA6B0e5m1sdSAjPXqNwtiy4.jpg", "size": 13135}]
I am not pretty sure about your program flow but as you are injecting Request dependency to the store function, I assume the JSON object is a part of your request. In that case, you can try,
$input = $request->json()->all();
Just print_r($input) and see what you are getting.
If JSON object is not a part of your request, you missed passing $json to your function. This is a wild guess, though!
Just dropping by for having the same issue of trying to get the json formatted response (Laravel 8.8.0). The way I was able to get it working was using:
$jsonFormattedResult = json_decode ($response->content(), true);
Hope it helps someone out. ( '-')/
you can use Response::json($value);
I want to decode json string including array and object in PHP. When i decoded with
$array = json_decode($json, true);
print_r($array);
it return NULL. Let me know, the way to decode json in PHP. This is my json string.
{
success: 1,
message: "Successful!",
save_date: "2013-09-11 04:09:26",
test: [
{
test_id: "1",
test_date: "2013-09-12",
test_name: "Test 1"
},
{
test_id: "2",
test_date: "2013-09-11",
test_name: "Test 2"
}
]
}
That's not a valid JSON object. JSON objects must enclose all property names in double quotes:
{ "success": 1, "message": "Successful!" }
PHP provides the handy json_last_error_msg function to tell you that.
There's also the online tool JSONLint to validate JSON strings.
Your JSON is invalid, the property names need to be in quotes too.
Like this:
{
"success": 1,
"message": "Successful!",
"save_date": "2013-09-11 04:09:26",
"test": []
}
Hint: use JSONLint to validate your JSON.
your json string should be like the following :
$sJson = '{"success": 1,"message": "Successful!","save_date": "2013-09-11 04:09:26",
"test": [ {"test_id": "1","test_date": "2013-09-12","test_name": "Test 1"},
{"test_id": "2","test_date": "2013-09-11","test_name": "Test 2"}]}';
Use this
$result=(array)json_decode('your json string');
I think it's working for you
I have passed JSON encoded parameters by POST which we have captured and decoded in another PHP file. I have used the following code to do that.
$entityBody = file_get_contents('php://input');
$entityBody = json_decode($entityBody, true);
I have passed the JSON encoded parameters as follows:
{
"id": "5",
"name": "abcd",
"imei": "1234"
}
Here my code works perfectly fine. However, I want to get all the parameters into a single object so that we can store them efficiently because otherwise there will be too many ifs and elses to get each parameter. So I have encoded the parameters as follows:
device = {
"id": "5",
"name": "abcd",
"imei": "1234"
}
But it is not working. Being new to JSON and PHP I do not know how to handle such cases. How can I achieve this?
use json_decode($_POST['device'], true) since your actually passing a parameter called 'device' to the php file.
You should pass json objects as follow:
{"device" : {
"id": "5",
"name": "abcd",
"imei": "1234"
}}
or if you have an array of devices
{"device" : [{
"id": "5",
"name": "abcd",
"imei": "1234"}
]}