I'm using PHPUnit to test a function which downloads a file. I want to test that the correct file is downloaded and so my idea was to check the output of the function. I'm trying to use output buffering:
ob_start();
$viewer->downloadById($fileId);
$output = ob_get_flush();
$this->assertEquals($expectedFileContents,$output);
The test passes/fails when it should, which is good. My issue is that the contents of the output buffer is also printed to the console. How do I hide this?
Use ob_get_clean() instead of ob_get_flush(). The former will remove the buffer without printing it and return its contents. The latter will do the same and print the contents of the buffer.
Related
When we say that a function's result is sent to output buffer, it means that the result is not visible until echoed. And for functions that output directly, we use ob_start to direct the result to the output buffer (before it hits the browser as plain html) so that we may manipulate it, and then if desired, echo it.
The result of the function readfile() is directly visible, which is the contents of a certain text file, for example. then my question is:
Why it is mentioned in php documentation that readfile() sends the contents to the output buffer ?! (while in fact it is displayed directly).
Am I missing something?
When we say that a function's result is sent to output buffer, it means that the result is not visible until echoed. No it doesn't mean that!
Because it is sent to the output buffer, which (unless you've explicitly executed an ob_start() to buffer the output before sending it to the browser) is sent directly to the browser (or whatever).
All output is sent to the output buffer, but unless you've set the buffer to hold output before sending it, it gets sent.
EDIT
Of course, a webserver may be configured to cache output until a certain volume of data has been sent, but that isn't the same as PHP output buffering
Well, when the readfile() is executed, the output goes directly to stdout.
it is useful to know this behavior when php is used as a bash script:
#!/usr/bin/php
<?php
readfile("cool.txt");
// Output cool.txt whole content
It behave differently to file_get_contents from this view.
#!/usr/bin/php
<?php
file_get_contents("js.txt");
// No output!
$cool = file_get_contents("js.txt");
echo $cool;
// Output cool.txt
I'm having a hard time figuring out the problem in the following code, I really need a solution to this.
Consider the following code :
<?php
//starting a new output buffer, with a GZIP compression
ob_start("ob_gzhandler");
//this goes into the buffer
echo "Hi";
//grabbing the buffer's content
$content = ob_get_contents();
//cleaning the buffer
ob_clean();
//we're still inside the buffer, show the content again
echo $content;
This code fails to output "Hi", instead I see "‹óÈM", what have done that broke correct buffering? Knowing that once I remove "ob_gzhandler", the buffering is correct and everything is fine. I don't want to create another buffer and destroy the current one. I just want to clean the current one using ob_clean.
Any ideas? Thanks in advance.
Thank you for your answer, I figured out why, GZIP is insalled on my machine by the way, it's that when setting ob_gzhandler, the buffer is compressed chunk by chunk, so when using ob_get_contents(), parts of the last chunck are missing, and I end up getting weird output.
To correct that behaviour (or at least to bypass it), open a second output buffer, and leave the one with gzhandler() alone.
Like this
ob_start("ob_gzhandler");
ob_start();
Now the second one isn't compressed, I can do whatever I want with it (hence get its content, clean it etc). The content will be compressed anyway given that a higher level output buffer with gzhandler is opened.
Maybe you don't have gzip compression enabled/installed on your machine.
Tried your code and got something like that. I don't have gzip installed on my machine, try this:
It's your code but with a condition, if gzip doesn't start, the buffer starts.
//starting a new output buffer, with a GZIP compression
if (!ob_start("ob_gzhandler")) ob_start();
//this goes into the buffer
echo "Hi";
//grabbing the buffer's content
$content = ob_get_contents();
//cleaning the buffer
ob_clean();
//we're still inside the buffer, show the content again
echo "<pre>"; echo $content; echo "</pre>";
ob_end_flush();
If you get "Hi", maybe gzip is not installed.
I want to copy the file http://searchr.us/Testing/web-search.phtml?search=SEARCHED+TEXT to
http://searchr.us/Testing/search/SEARCHED+TEXT.html
How do i do this?
NOTE:The source of http://searchr.us/Testing/search/SEARCHED+TEXT.html should be the same as http://searchr.us/Testing/web-search.phtml?search=SEARCHED+TEXT
Indirectly I'm just saving a query so that I can keep a track of them!
Hope i've get you right: you want to store output of any query into file. You can manage this with output buffering.
In the begining of script wright:
ob_start(); // start buffering
This turns buffering on.
At the eng of page wright something like this ($query is text of query):
$html = ob_get_contents();
ob_end_flush(); // this turns off buffering and sends buffered content to output
$fp = fopen("{$query}.html","w");
fwrite($fp,$html);
fclose($fp);
I am having a php file which executes some code to generate a html file.Its like I m having a form from which some data will be posted to x.php file, which gives a output(a webpage). I want to save that output in a html file.What the most efficient way of doing this.?
EDIT
I want to save it on sever side. Actually the thing is i want to create pdf file for that.. I wrote everything else.Now the thing is i want to save the output in a html page.So that i can convert it into pdf file..
Try something like this:
// Start output buffering
ob_start();
// run code in x.php file
// ...
// saving captured output to file
file_put_contents('filename.htm', ob_get_contents());
// end buffering and displaying page
ob_end_flush();
If you cannot use the ob_* functions, you can also write the form to a variable and then save that variable.
Look at ob functions (see http://php.net/manual/en/function.ob-start.php) that allows you to capture every output (echo, print, etc...) from the page.
using ob_* functions such as ob_get_contents(), a php script can catch it's output.
probably with ob_start and output_callback see http://php.net/manual/en/function.ob-start.php
I have a php that makes some maintenance operations in my web and I need that the last operation it'll do is to save into a file the content of the screen. I mean, self content.
If the screen shows: "OP1 - OK ..." it has to save into a file this: "OP1 - OK ...".
Saving all the results of my operations into a variable will very hard for me. That's why I need to get the content of the self screen.
Is there any way to do this?
I think you can use an output buffer.
The following is from ob_start's php manual page:
This function will turn output buffering on. While output buffering is active no output is sent from the script (other than headers), instead the output is stored in an internal buffer.
The contents of this internal buffer may be copied into a string variable using ob_get_contents(). To output what is stored in the internal buffer, use ob_end_flush(). Alternatively, ob_end_clean() will silently discard the buffer contents.