Pass $_FILE data to $.getJSON - php

Question

I want to pass the $_FILES array to .getJSON.
Here is my jquery:
$.getJSON(link+'api/images/upload.php',{action:'image.upload',id:id,img:img}, function (response){
var url = this.url;
var result = response.message;
if(response.status == 200){
var data = response.data;
console.log(data);
try_print('Data',data,try_dbg);
}
else{
alert(response.message);
}
});
Here is my api:
switch($_REQUEST['action']){
case 'image.upload':
$id = $_REQUEST['id'];
$img = $_FILES['img']['name']; //echo $img;
$temp = explode(".", $_FILES["img"]["name"]);
$extension = end($temp);
$error = $_FILES["img"]["error"];
if(!empty($id)){
if(!empty($img)){
if(is_writable($original)){
if(in_array($extension, $allowedExts)){
if($error == 0){
$filename = $_FILES["img"]["tmp_name"];
list($width, $height) = getimagesize($filename);
$a = apiPicture($original, $id, $_FILES["img"]);
$return['status'] = 'success';
$return['url'] = $original.$_FILES["img"]["name"];
$return['width'] = $width;
$return['height'] = $height;
$return['status'] = 200;
$return['message'] = 'Success.';
}
else{
$return['status'] = 400;
$return['message'] = 'Error: '.$error;
}
.... the rest of the error codes
break;
default:
$return['message'] = 'Unknown Request';
}
Is there a solution for this, can I pass an image through .getJSON?