I use PHP to encode json data from my MySQL table, the output comes like this
[
{
"Copra_Crushed_MT": "2306.01851",
"Oil_Extracted_MT": "1454.9442"
},
{
"Copra_Crushed_MT": "1234",
"Oil_Extracted_MT": "5678"
},
{
"Copra_Crushed_MT": "1907",
"Oil_Extracted_MT": "4605"
}
]
But i want the structure to be this way, how should i proceed to get this
[
[2306.01851,1454.9442],
[1234,5678],
[1907,4605]
]
my PHP code used to encode JSON
private function productionhourlys(){
if($this->get_request_method() != "GET"){
$this->response('',406);
}
$query="SELECT distinct c.Copra_Crushed_MT, c.Oil_Extracted_MT FROM productionhourlys c order by c.productionhourlyNumber desc";
$r = $this->mysqli->query($query) or die($this->mysqli->error.__LINE__);
if($r->num_rows > 0){
$result = array();
while($row = $r->fetch_assoc()){
$result[] = $row;
}
$this->response($this->json($result), 200); // send user details
}
$this->response('',204); // If no records "No Content" status
}
private function json($data){
if(is_array($data)){
return json_encode($data);
}
}
Put array_values around your row:
$result[] = array_values($row);
(array_values docs)
Alternatively (and probably the better way) - You can use mysqli_result::fetch_row instead of fetch_assoc
while($row = $r->fetch_row()) {
(fetch_row docs)
json_encode in php will automatically turn associative arrays into json object (the curly brace syntax). You can use array values to remove keys and then json_encode will turn the arrays into JSON arrays (the square bracket syntax).
Related
I'm trying to write a function in php that will allow me to return an array of objects (in my case the objects are the rows in my database(MySQL) from phpMyAdmin) into a Json format.
Here is my function:
public function getAllCases()
{
$stmt = $this->conn->prepare("SELECT * FROM mycase ");
$stmt->execute();
$arr = []
$result = $stmt->get_result();
while($row = $result->fetch_object()) {
$arr[] = $row;
}
return $arr;
}
I couldn't find anything else online and this function is not working.
For example if my table has 4 rows, I want to be able to get 4 objects and each one of those 4 objects should represent a row from the table and it's columns.
Any help would be appreciated.
You can use json_encode and json_decode to convert array to JSON and vice versa.
return json_encode($arr)
To convert a php array into json , Use json_encode() function. And in your code, You mixed up Normal and Prepared Statements.
public function getAllCases()
{
$data = array();
$result = $this->conn->query("SELECT * FROM `mycase`");
$num_rows = $result->num_rows;
if ($num_rows > 0) {
while($row = $result->fetch_assoc()) {
$data[] = $row;
}
}
return json_encode($data);
}
I'm trying to GET a JSON format back when I POST a specific ID to my database. As I get more than one result I have multiple rows, which I want to get back. I do get different arrays back, but it is not a valid JSON Format. Instead of
[{...},{...},{...}]
it comes back as
{...}{...}{...}
Therefore the [...] are missing and the arrays are not separated by commas.
My code is down below. The function "getUserBookingsKl" is defined in a different php.
//get user bookings
public function getUserBookingsKl($id) {
//sql command
$sql = "SELECT * FROM `***` WHERE `hf_id`=$id AND `alloc_to`>DATE(NOW()) AND NOT `confirmation`=0000-00-00 ORDER BY `alloc_from`";
//assign result we got from $sql to $result var
$result = $this->conn->query($sql);
// at least one result
if ($result !=null && (mysqli_num_rows($result) >= 1 ))
{
while ($row = $result->fetch_array())
{
$returArray[] = $row;
}
}
return $returArray;
}
...
...
foreach($userdb as $dataset)
{
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
echo json_encode($returnArray);
# return;
}
// Close connection after registration
$access->disconnect();
It looks like you're sequentially emitting the values, not pushing into an array. You need to make an array, push into it, then call json_encode on the resulting structure:
$final = [ ];
foreach ($userdb as $dataset)
{
$returnArray = [ ];
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
$final[] = $returnArray;
}
echo json_encode($final);
Note that it's important here to not use the same variable inside the loop each time through or you're just pushing the same array in multiple times.
I'm writing a PHP code for inserting the work order name in a spinner.
I need a JSON String called success = 1 along with JSON Array.
I want to use that JSON string in the android spinner.
I'm getting only JSON array.
here is my code:
<?PHP
require_once('connection.php');
$workName = "SELECT workorder_name FROM workorder_category";
$con=mysqli_connect($server_name,$user_name,$password,$db);
$r = mysqli_query($con,$workName);
$result = array();
$resultArr = array('success' => true);
while($row = mysqli_fetch_array($r)){
array_push($result,array('$workOrderName'=>$row['workorder_name']));
}
echo json_encode(array('result'=>$result));
mysqli_close($con);
?>
I want an output as like this:
{"success":1,result":[{"$workOrderName":"electrician"},{"$workOrderName":"plumber"},{"$workOrderName":"carpenter"}]}
currently, I am getting the output like
{
"result": [
{
"$workOrderName": "electrician"
},
{
"$workOrderName": "plumber"
},
{
"$workOrderName": "carpenter"
}
]
}
Instead of creating two arrays, one for the result and one for the success, define the structure in just one array and append to that:
// The main structure
$result = [
'success' => 1,
'result' => [],
];
while($row = mysqli_fetch_array($r)){
// Append to the sub key "result" (which we already defined as an array)
$result['result'][] = ['$workOrderName'=>$row['workorder_name']];
}
// Just encode the complete array
echo json_encode($result);
Note: This example uses the short array syntax [] (introduced in PHP 5.4) instead of the long syntax: array(). They do the exact same thing.
I also changed array_push() to a shorter version: $someArray[] =.
$result = array();
$resultArr['success'] =true;
while($row = mysqli_fetch_array($r))
{
array_push($result,array('$workOrderName'=>$row['workorder_name']));
}
$resultArr['result'] = $result;
echo json_encode($resultArr);
This will work fine.
I need json response in different array, but below code not give all the result.
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
}
echo json_encode($data,true);
You need to save your items into some array, e.g $dataArray at the end of each iteration and after cycle use this array to create json
$dataArray = array();
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
$dataArray[] = $data;
}
echo json_encode($dataArray,true);
This question already has answers here:
JSON encode MySQL results
(16 answers)
Closed 1 year ago.
I've spent a couple of hours looking through several the similar answers before posting my problem.
I'm retrieving data from a table in my database, and I want to encode it into a JSON. However, the output of json_encode() is only valid when the table has one single row. If there is more than one row, the test at http://jsonlint.com/ returns an error.
This is my query:
$result = mysql_query($query);
$rows = array();
//retrieve and print every record
while($r = mysql_fetch_assoc($result)){
$rows['data'] = $r;
//echo result as json
echo json_encode($rows);
}
That gets me the following JSON:
{
"data":
{
"entry_id":"2",
"entry_type":"Information Relevant to the Subject",
"entry":"This is my second entry."
}
}
{
"data":{
"entry_id":"1",
"entry_type":"My Opinion About What Happened",
"entry":"This is my first entry."
}
}
When I run the test at http://jsonlint.com/, it returns this error:
Parse error on line 29:
..."No comment" }}{ "data": {
---------------------^
Expecting 'EOF', '}', ',', ']'
However, if I only use this first half of the JSON...
{
"data":
{
"entry_id":"2",
"entry_type":"Information Relevant to the Subject",
"entry":"This is my second entry."
}
}
... or if I only test the second half...
{
"data":{
"entry_id":"1",
"entry_type":"My Opinion About What Happened",
"entry":"This is my first entry."
}
}
... the same test will return "Valid JSON".
What I want is to be able to output in one single [valid] JSON every row in the table.
Any suggestion will be very much appreciated.
The problem is you're spitting out separate JSON for each row, as opposed to doing it all at once.
$result = mysql_query($query);
$rows = array();
//retrieve and print every record
while($r = mysql_fetch_assoc($result)){
// $rows[] = $r; has the same effect, without the superfluous data attribute
$rows[] = array('data' => $r);
}
// now all the rows have been fetched, it can be encoded
echo json_encode($rows);
The minor change I've made is to store each row of the database as a new value in the $rows array. This means that when it's done, your $rows array contains all of the rows from your query, and thus you can get the correct result once it's finished.
The problem with your solution is that you're echoing valid JSON for one row of the database, but json_encode() doesn't know about all the other rows, so you're getting a succession of individual JSON objects, as opposed to a single one containing an array.
You need to change your PHP code into something like this:
$result = mysql_query($query);
$rows = array();
//retrieve every record and put it into an array that we can later turn into JSON
while($r = mysql_fetch_assoc($result)){
$rows[]['data'] = $r;
}
//echo result as json
echo json_encode($rows);
I think you should do
$rows = array();
while($r = mysql_fetch_assoc($result)){
$rows[]['data'] = $r;
}
echo json_encode($rows);
echo should be placed outside of the loop.
I was trying the same in my PHP, so I came whit this...
$find = mysql_query("SELECT Id,nombre, appaterno, apmaterno, semestre, seccion, carrera FROM Alumno");
//check that records exist
if(mysql_num_rows($find)>0) {
$response= array();
$response["success"] = 1;
while($line = mysql_fetch_assoc($find)){}
$response[] = $line; //This worked for me
}
echo json_encode($response);
} else {
//Return error
$response["success"] = 0;
$response["error"] = 1;
$response["error_msg"] = "Alumno could not be found";
echo json_encode($response);
}
And, in my Android Class...
if (Integer.parseInt(json.getString("success")) == 1) {
Iterator<String> iter = json.keys();
while (iter.hasNext()) {
String key = iter.next();
try {
Object value = json.get(key);
if (!value.equals(1)) {
JSONObject jsonArray = (JSONObject) value;
int id = jsonArray.getInt("Id");
if (!db.ExisteAlumo(id)) {
Log.e("DB EXISTE:","INN");
Alumno a = new Alumno();
int carrera=0;
a.setId_alumno(id);
a.setNombre(jsonArray.getString("nombre"));
a.setAp_paterno(jsonArray.getString("appaterno"));
a.setAp_materno(jsonArray.getString("apmaterno"));
a.setSemestre(Integer.valueOf(jsonArray.getString("semestre")));
a.setSeccion(jsonArray.getString("seccion"));
if(jsonArray.getString("carrera").equals("C"))
carrera=1;
if(jsonArray.getString("carrera").equals("E"))
carrera=2;
if(jsonArray.getString("carrera").equals("M"))
carrera=3;
if(jsonArray.getString("carrera").equals("S"))
carrera=4;
a.setCarrera(carrera);
db.addAlumno(a);
}
}
} catch (JSONException e) {
// Something went wrong!
}
}
I must have spent 15 hours on this issue. Every variation discussed above was tried. Finally I was able to get the 'standard solution' working. The issue, very oddly, appears to be this:
When the interval is set beyond 14 hours, json appears to be unable to parse it. There must be a limit to JSON.
$sql= "SELECT cpu_name, used, timestamp FROM tbl_cpu_use WHERE timestamp>(NOW() - INTERVAL 14 HOUR) ORDER BY id";
$result=mysql_query($sql);
if ($result){
$i=0;
$return =[];
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$rows[] = $row;
}
echo json_encode($rows);
}else{
echo "ERROR";
}