Php loop not showing me result of operation but no errors - php

for ($i= count($words); $i < count($words) -1 ; $i++) {
$w = strtolower(array_values($words)[$i]);
$s = array_map('strtolower',$string_to_search);
if (in_array($s , $w)) {
echo $w;
echo "im here";
}
}
The code above is supposed to check if a word is in an array and if so count it. Im not getting errors but I cant see results please help
Ive tried the foreach loop but its not working aswell
Can someone please tell me where im messing up im a noob in php

start this loop with for ($i = 0; because when you start from count, it is not iterating at all:
for ($i= 0; $i <= count($words) -1 ; $i++) {

Change your code to be as follows:
for ($i= 0; $i < count($words) -1 ; $i++) {
$w = strtolower(array_values($words)[$i]);
$s = array_map('strtolower',$string_to_search);
if (in_array($s , $w)) {
echo $w;
echo "im here";
}
}

Related

how to display cycles in php added elements to each cycle in php?

I need your help to solve this problem, I am trying to write the necessary code so that the output is as follows:
PHP! PHP!! PHP!!! PHP!!!! PHP!!!!!
<?php
$y = ['!'];
for($i = 1; $i <= 5; $i++)
{
print "PHP!"."$y\t";
if($y+1 <5)
$y="!";
$y+'!';
}
?>
Until the second word, it adds one more exclamation point and in the rest of the repetitions it has the same number, that is two exclamation points.
How can I solve this problem?
Try this:
<?php
for ($i = 0; $i < 5; $i++) {
echo "PHP".str_repeat ("!", $i);
}
?>
You can try it:
<?php
for($i = 1; $i <= 5; $i++)
{
echo "PHP";
for($j = 1; $j <= $i; $j++){
echo "!";
}
}
?>
You can also use str_repeat():
<?php
for ($i = 1; $i <= 5; $i++) {
echo "PHP".str_repeat ("!", $i);
}
?>
Output will be: PHP!PHP!!PHP!!!PHP!!!!PHP!!!!!

For loop (php) that results in this: 12345678910987654321

My niece is trying to create one for-loop (php), that results in this:
* 12345678910987654321
example for loop she tried:
for ($i = 1; $i <= 10; $i++ , $i = 10; $i <= 1; $i--) {
echo $i . ' ';
}
She can only use if's and elseif's. I'm not a programmer and can't really help her. Any ideas how this could be achieved in php?
Any information would be greatly appreciated.
The key is to add a variable instead of a number, then reverse that number when $i hits 10.
for($i = 1, $j = 1; $i> 0; $i+=$j) // Start i at 1, and j at 1
{
echo $i;
if($i == 10)
$j = -1; // i has hit 10, so use -1 to start subtracting
}
Another possibility is to loop up to 20, printing $i for the ascending part and 20 - $i for the descending.
for ($i = 1; $i < 20; $i++) {
if ($i <= 10) {
echo $i;
} else {
echo 20 - $i;
}
}

warning occuring in php word occurence

I have written the following code to count the number of string occurrences in a given file.
PHP
<?php
$p = fopen("g.txt", "r");
$q = fread($p, filesize("g.txt"));
$t = explode(" ", $q);
$m = explode(" ", $q);
$i = 0;
$j = 0;
$r = 0;
$count = 0;
$c = count($t);
$d = array();
echo "count of".
"<br/>";
for ($i = 0; $i < $c; $i++) {
for ($j = $i; $j < $c; $j++) {
if ($t[$i] == $t[$j]) {
$count = $count + 1;
}
}
for ($r = $i + 1; $r < $c; $r++) {
if ($t[$i] == $t[$r])
unset($t[$r]);
}
echo $t[$i].
"=".$count.
"<br/>";
$count = 0;
}
?>
I am getting a notice of undefined offset on line numbers 17 and 24, though my output is coming out to be correct. Can you please help me in rectifying the above problem?
The problem is that you are deleting items from the array $t. You saved the count in $c, but the actual count will change by your last inner loop.
Even if you replace $c by count($t) everywhere, it will go wrong, because the last loop should be in reverse order, otherwise you skip items. For instance if you have the list 'a', 'b', 'c'. then when you delete 'b' and increment $r, you will not check 'c' at all.
So, if I fix those things, your code becomes as below. Although I didn't really check it for other issues. Frankly, I don't really get what is should do. ;-)
<?php
$p=fopen("g.txt","r");
$q=fread($p,filesize("g.txt"));
$t=explode(" ",$q);
$m=explode(" ",$q);
$i=0;
$j=0;
$r=0;
$count=0;
$d=array();
echo "count of"."<br/>";
for($i=0; $i<count($t); $i++)
{
for($j=$i; $j<count($t); $j++)
{
if($t[$i]==$t[$j])
{
$count=$count+1;
}
}
for($r=count($t) - 1; $r > $i; $r--)
{
if($t[$i]==$t[$r])
unset($t[$r]);
}
echo $t[$i]."=".$count."<br/>";
$count=0;
}
?>
In conclusion, you should do more tests. If the outcome of this script was okay, then it was by accident.

php array is printed infinite time using while loop

I know i Can easily do this with a for loop but i am trying to do it in while loop and I get Google infinite times. Why is this? I Knew something was wrong however because i was going over a tutorial on tuts+ I thought it was my mistake. Then I read the comments section of the video and the instructor says sorry I forgot to increment the I.
$month = array('google', 'html5nurse' , 'facebook');
$i = 0;
while ( $i < 10) {
echo "<li>$month[$i]</li>";
}
?>
Add i++ after the echo statement.
$month = array('google', 'html5nurse' , 'facebook');
$i = 0;
while ( $i < 10) {
echo "<li>$month[$i]</li>";
$i++;
}
It happens because $i is always equal to 0 in your code.
You need to increment it (as stated in the other solution) for instance using $i++ in the loop.
Note that it's generally better to use foreach which will iterate over each element of the array:
$months = array('google', 'html5nurse' , 'facebook');
foreach($months as $month){
echo $month."<br/>";
}
$month = array('google', 'html5nurse' , 'facebook');
$i = 0;
while ( $i++ < 10)
{
echo "<li>$month[$i]</li>";
}
?>
You should be using $i++ to increment $i and also using count so that the loop does not continue after there are no more results in the array.
<?php
$month = array('google', 'html5nurse' , 'facebook');
$i = 0;
$count = count($month);
while ($i < $count)
{
echo "<li>$month[$i]</li>";
$i++;
}
?>

add in loop in multi dimensional array

i am facing a problem
can some one suggest me
for ($i = 1; $i <= 2; $i++) {
$r2 = 0;
for ($t = 1; $t <= 2; $t++) {
echo $r2;
$r2++
}
}
output is 0101;
can i get output 0123 ??? please
if
for ($i = 1; $i <= 3; $i++) {
$r2 = 0;
for ($t = 1; $t <= 3; $t++) {
echo $r2;
$r2++
}
}
output is 010101;
can output 012345678 ??? please
and if
for ($i = 1; $i <= 4; $i++) {
$r2 = 0;
for ($t = 1; $t <= 4; $t++) {
echo $r2;
$r2++
}
}
output is 01010101;
can output 0123456789101112131415 ??? please
i think you understand
thanks
In all of these cases you are initializing $r2=0; in the inner loop. It should be outside the loop.
$r2=0;
for($i=1;$i<=2;$i++){
for($t=1;$t<=2;$t++){
echo $r2;
$r2++
}
}
This would produce "1234".
why are you using two nested for loops ?
why not just use one:
for ($i=0; $i<=15; $i++) echo $i . " ";
Try this:
$r2 = 10;
for($t = 0; $t <= $r2; $t++){
echo $r2;
}
Oh wait.. I get it now, why you have the two nested loops, you want to essentially raise a number to the power of 2 in order to control the number of values output. In that case, what you want is simply this:
// this is the variable you need to change to affect the number of values outputed
$n = 2;
// Square $n
$m = $n * $n;
// Loop $m times
for ($i = 0; $i < $m; $i++) {
echo $i;
}

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