Double if with database query - php

Question

I have this code
while ($row = mysql_fetch_assoc($wynik)) {
echo '<tr class="ad"> ';
foreach ($row as $key => $value) {
if ($value != null){
if ($value<=1){
$wymiar = $key."x".$first;
$wynik3 = mysql_query("SELECT * FROM `".$nazwa2."` where `tak` = '".$wymiar."' ");
while ($row = mysql_fetch_array($wynik3)) {
if ($row["tak"] == $wymiar){
echo $row["id"];
echo '<td width=25px; style="background-color: red; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
}
unset($wymiar);
}
echo '<td width=25px; style="background-color: green; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
} else {
echo '<td width=25px; style="background-color: yellow; border-color: blue;" border="1">'.$value."</td>";
$first = $value;
}
} else {
echo '<td width=25px; style="background-color: magenta; border-color: blue;" border="1">'.$value."</td>";
}
} echo "</tr>";
}
How to correctly use "if ... else" statement, Now is something wrong. It adds a red cell but also leaves a record with the green cell and moves the entire row

Answer 1

Try this. It only queries for 1 row in the $wynik3 query, by using LIMIT 1. Then it tests whether that query was successful; if it was, it displays a red cell, otherwise it displays a green cell.
while ($row = mysql_fetch_assoc($wynik)) {
echo '<tr class="ad"> ';
foreach ($row as $key => $value) {
if ($value != null){
if ($value<=1){
$wymiar = $key."x".$first;
$wynik3 = mysql_query("SELECT * FROM `".$nazwa2."` where `tak` = '".$wymiar."' LIMIT 1");
if ($row = mysql_fetch_array($wynik3)) {
echo $row["id"];
echo '<td width=25px; style="background-color: red; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
} else {
echo '<td width=25px; style="background-color: green; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
}
} else {
echo '<td width=25px; style="background-color: yellow; border-color: blue;" border="1">'.$value."</td>";
$first = $value;
}
} else {
echo '<td width=25px; style="background-color: magenta; border-color: blue;" border="1">'.$value."</td>";
}
} echo "</tr>";
}
BTW, it's echoing $row["id"] outside the <td>, which isn't valid HTML. I'm assuming that's just there for debugging, not part of the production table.

Answer 2

Try this
while ($row = mysql_fetch_assoc($wynik)) {
echo '<tr class="ad"> ';
foreach ($row as $key => $value) {
if (!empty($value)){
if ($value<=1){
$wymiar = $key."x".$first;
$wynik3 = mysql_query("SELECT * FROM `".$nazwa2."` where `tak` = '".$wymiar."' ");
if(mysql_num_rows($wynik3)== 0){
echo '<td width=25px; style="background-color: green; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
} else {
while ($row = mysql_fetch_array($wynik3)) {
if ($row["tak"] == $wymiar){
echo $row["id"];
echo '<td width=25px; style="background-color: red; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
}
unset($wymiar);
}
}
} else {
echo '<td width=25px; style="background-color: yellow; border-color: blue;" border="1">'.$value."</td>";
$first = $value;
}
} else {
echo '<td width=25px; style="background-color: magenta; border-color: blue;" border="1">'.$value."</td>";
}
} echo "</tr>";
}

Answer 3

Try this,
while ($row = mysql_fetch_assoc($wynik))
{
foreach ($row as $key => $value)
{
$arrTableTD = array();
if ($value != null)
{
if ($value<=1)
{
$wymiar = $key."x".$first;
$wynik3 = mysql_query("SELECT * FROM `".$nazwa2."` where `tak` = '".$wymiar."' ");
while ($row = mysql_fetch_array($wynik3))
{
if ($row["tak"] == $wymiar)
{
$arrTableTD[] = $row["id"];
$arrTableTD[] = '<td width=25px; style="background-color: red; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
}
unset($wymiar);
}
$arrTableTD[] = '<td width=25px; style="background-color: green; border-color: blue;" border="1"><p style="display:block;">'.$key.'x'.$first.'</p></td>';
} else {
$arrTableTD[] = '<td width=25px; style="background-color: yellow; border-color: blue;" border="1">'.$value."</td>";
$first = $value;
}
} else {
$arrTableTD[]= '<td width=25px; style="background-color: magenta; border-color: blue;" border="1">'.$value."</td>";
}
}
echo $tablerow = '<tr class="ad">'.implode("",$arrTableTD).'</tr>';
}

Answer 4

You might have an issue because you're using the variable $row two times in you code.
Here
foreach ($row as $key => $value)
And here
while ($row = mysql_fetch_array($wynik3))
The second use of it create a problem true renaming it.
I don't know if it will solve your problem, but is it definitely a first correction to make