Display data from 3 tables - php

Question

I have messed with this query for 3 days now and no matter what I cannot get the right result. I'm working on a small database for a friend of mine for his mechanic shop.
I got 3 tables car, jobs and invoices. Everything start with "cars" if you add a car you get car_id for it. Next step would be to add a job to this car. Of course job goes to jobs table and also records car_id. After the job is done you can create an invoice out of it which goes to invoices table and again records car_id.
cars jobs invoices
=======================================================
cID, make, model | jID,cID,job1 | iID,jID,cID,amount
1 audi a6 | 1 1 check | 1 1 1 99.99
2 bmw 750 | 1 2 oil | 2 2 2 56.97
3 saab 95 | 3 3 oil | 3 3 3 30.22
1 audi a6 | 4 1 oli | 4 4 1 22.33
Small draft what the tables look like. And the outcome what I'd like to get should look like this:
ID make model
--------------------------
1. audi a6
Job 1 Invoice 1
Job 4 Invoice 4
2. bmw 750
Job 2 Invoice 2
3. Saab 95
Job 3 Invoice 3
Basically when I click my client list I get a table rows with clients and underneath client I'd like to print links to jobs and invoices.
Quite long post but I hope you understand what I mean.
I've tried different JOINs, the latest that I tried was
SELECT * FROM cars
RIGHT JOIN jobs ON cars.car_id=jobs.car_id
RIGHT JOIN invoices ON cars.car_id=invoices.car_id
ORDER BY cars.car_id;
It kind a worked but it gave me separate rows for each job with same client info. May I'm printing the result wrong. I just don't know any more. Can anybody offer a solution for this? right SQL command html for printing.

Answer 1

Why don't you just make it in a single table with fields like this:
id car job invoices
===============+===============+==============+==============+
1 + fastCar + works + 99.99 +
+ + + +
+ + + +
With statement like this:
CREATE TABLE cars (id int(11) AUTO_INCREMENT, car text(50) default '', job text(50) default '', invoices int(5) default NULL);
Then you can get all car attributes using a query like:
SELECT job FROM cars WHERE car='fastCar';
and pass desired values with another query to a teble that contains
details for the job for example, where you can have job id as needed.