I am new to php & mysql and I'm trying to make a script that gets the distance walked with the player's name. I can get the player's walked distance with his id, but the value for the player_id is in a different table.
It looks like this:
Table1: player_id | foot (walked distance)
Table2: name | player_id
So I want to use the name by the player_id in my table.
Code
You require a simple join.
SELECT Table1.foot, Table2.name
FROM Table1
INNER JOIN Table2
ON Table1.player_id = Table2.player_id;
You just need to join both these table.
Just try this code:
$query = "SELECT T1.*, T2.name
FROM table1 T1
LEFT JOIN table2 T2 ON T1.player_id = T2.player_id
ORDER BY T2.name ASC";
For more details of JOIN: Link
Let me know for more help.
You can use
$query = "select t1.player_id, t2.name, t1.foot
from table1 t1
join table2 t2 on t1.player_id = t2.player_id"
If you want to order the player names in alphabetical order then you can additionally use order by clause
$query = "select t1.player_id, t2.name, t1.foot
from table1 t1
join table2 t2 on t1.player_id = t2.player_id
order by t2.name"
Use left join in mysql.
Suppose if you have two tables use this
SELECT T1.*,T2.walked distance
FROM table1 T1
LEFT JOIN table2 T2
ON T1.id=T2.player_id;
Click Here For more example
Related
I have tried the following syntax, which seems to work fine on SQL when I use Oracle SQL Developer. However, when I use the code in MySQL, I get ther error "Something went wrong!".
$result = mysqli_query($con, "SELECT * FROM Table1 NATURAL JOIN (SELECT ID, SUM(row2) FROM table2 GROUP BY ID) NATURAL JOIN (SELECT ID, COUNT(col1) FROM Table2 WHERE ID IS NOT NULL GROUP BY ID)")
or die("Something went wrong!");
Is there a difference in syntax in this case, or could it be anything else I'm doing wrong?
Thanks!
This is your query:
SELECT *
FROM Table1 NATURAL JOIN
(SELECT ID, SUM(row2) FROM table2 GROUP BY ID) NATURAL JOIN
(SELECT ID, COUNT(col1) FROM Table2 WHERE ID IS NOT NULL GROUP BY ID)
MySQL supports NATURAL JOIN (I don't recommend using it, but that is another matter). Unlike Oracle, you need to have table aliases on the tables, essentially names for them. You may also need column aliases. I always use them, so I don't know if they are needed.
Try this:
SELECT *
FROM Table1 t1 NATURAL JOIN
(SELECT ID, SUM(row2) as cnt_row2
FROM table2
GROUP BY ID
) t2row NATURAL JOIN
(SELECT ID, COUNT(col1) as cnt_col1
FROM Table2
WHERE ID IS NOT NULL
GROUP BY ID
) t2col1
You can actually simplify this query:
SELECT t1.*, t2.cnt_col1, t2.cnt_row2
FROM Table1 t1 INNER JOIN
(SELECT ID, COUNT(col1) as cnt_col1, SUM(row2) as cnt_row2
FROM Table2
GROUP BY ID
) t2
ON t1.id = t2.id
The filtering on ID IS NOT NULL has no effect, because a NULL value will not be included in the join.
In MySQL all the Sub queries that are used in the FROM part need an alias name. In your case its missing. And I don't use NATURAL JOIN because using other specific INNER JOIN or LEFT JOIN clarifies the condition and scenario. So may be you could rewrite your query like this to make it work:
SELECT * FROM Table1
INNER JOIN (SELECT ID, SUM(row2) FROM table2 GROUP BY ID) a
ON a.ID = Table1.ID
INNER JOIN (SELECT ID, COUNT(col1) FROM Table2 WHERE ID IS NOT NULL GROUP BY ID) b
ON b.ID = Table2.ID;
I am trying to get a query using fields from 2 tables.
I need to query Table1 but only Table2 has the variable venue_location that I need to query.
Basically I need to count all records on Table1 where Table1.venue_location = $MyVariable.
Here is what I've put together but I believe I need to use Joins for this?
Table1
- venue_id
Table2
- venue_id,
- venue_location
SELECT * FROM Table1 WHERE table1.venue_id = table2.venue_id and table2.location = '$MyVariable'
How can I do a query for this?
Use the power of join table
SELECT * FROM Table1
JOIN Table2 USING(venue_id)
WHERE table2.location = '$MyVariable'
You can get back the count of rows with mysqli_num_rows() in PHP, or change le select by SELECT COUNT(*) AS nbRow FROM ... and check of value in nbRow column
You can join two tables on venue_id and then group it by venue_id where location is your $MyVariable.
Your final query will look like:
SELECT count(table2.venue_id)
FROM Table1
JOIN Table2 ON table1.venue_id = table2.venue_id
WHERE table2.location = '$MyVariable'
GROUP BY table2.venue_id
try this
SELECT Table1.venue_id, Table2.venue_location FROM Table1 INNER JOIN Table2
ON Table1.venue_id='$MyVariable';
I can do the following in 2 queries but want to make it simpler. Can this be combined in one query? If so how more efficient is it than doing two queries vs one?
query1: SELECT page_id, coupon_id from table_1 WHERE key = :key
query2: SELECT folder from table_2 WHERE page_id = table_1.page_id
For my final result I need to have a coupon_id from table_1, and a folder from table_2.
In query2 I need to use the page_id result from query1 to get the folder
Is there a simpler way to do this?
Use JOIN (LEFT, RIGHT or INNER is up to your needs):
SELECT
t1.page_id,
t1.coupon_id,
t2.folder
FROM
table_1 AS t1
LEFT JOIN table_2 AS t2 ON
t2.page_id = t1.page_id
WHERE
t1.key = :key
You will want to JOIN the tables on the page_id:
SELECT t1.page_id,
t1.coupon_id,
t2.folder
from table_1 t1
inner join table_2 t2
on t1.page_id = t2.page_id
WHERE key = :key
If you need help learning join syntax, here is a great visual explanation of joins.
I used an INNER JOIN which will return all rows that match between the two tables. If you want to return all rows from table_1
even if it doesn't have a matching row in table_2, then you would use a LEFT JOIN
SELECT
table_1.coupon_id AS coupon_id,
table_2.folder AS folder
FROM
table_1
INNER JOIN table_2 ON table_2.page_id = table_1.page_id
WHERE
table_1.key = :key
SELECT t1.page_id, t1.coupon_id, t2.folder
FROM table_1 t1 LEFT JOIN table_2 t2 ON (t1.page_id = t2.page_id)
WHERE t1.key = :key
This will be faster than two queries, how much depends on your data.
Try this please:
SELECT a.page_id, a.coupon_id, b.folder_id
from table_1 a
join table_2 b
ON a.page_id = b.page_id
WHERE a.key = :key
group by a.page_id
;
I have a problem...I have 2 tables, Table1 and Table2.
Table1:
id,int(11)
text,varchar(11)
Table2:
id,int(11)
agentid,int(11)
unique(id,agentid)
Table2 has many id and agent ids in it. The data for the id in table 2 came from table 1.
I have an agentid say $aid. This has many id's associated with it in table 2.
I am trying to get the set of text values out from table 1 associated with all ids which are related to agentid $aid from table 2.
Does that make sense?!
Any ideas?
select text from table1 where id in
(
select id from table2 where agentid = <your aid>
)
This will give you all text rows for given agentid.
The same can be done using join too -
select t1.text from table1 t1
inner join table2 t2
on t1.id = t2.id
where t2.agentid = <your aid>
select * from table1 as t1 inner join table2 as t2
on t1.id = t2.id
where agentid = $aid
The query:
$sql = "select t1.text from table1 t1, table2 t2 where t2.id = t1.id and t2.agentid = {$aid}";
Try not to include the $aid directly in the query, but escape it and/or use prepared statements with query parameters.
I have to three table I need to gather data from in a search process:
Commissions Table - Table1: [affiliate_id]
Affiliates Table - Table2: [id][user_id]
Profiles Table - Table3: [ID][NickName]
The search input I'll have is someone searched for a username. I need to return the data from table 1 where the affiliate_id matches the user_id of Table2, that is like the nickname that will be searched for.
I hope that makes sense :)
Try this:
"select table1.* from table1
inner join table2 on table2.user_id = table1.affiliate_id
inner join table3 on table3.id = table2.user_id
where table3.nickname like '%".mysql_real_escape_string($searchtext)."%'"
SELECT t1.*, t3.nickname FROM Table1 t1
JOIN Table2 t2 ON t2.id=t1.affiliate_id
JOIN Table3 t3 ON t2.user_id=t3.user_id
WHERE t2.user_id=?;