call a function in themes in yii - php

Question

I have a file in my yii first project. my project has a new theme with this path
first_proj\themes\project\views\layouts\main.php
and i want to call a function in it like below
<?php
if($is_project_manager){
?>
<div class="each-pop-el" style="cursor:pointer" ng-click="showAllMemberTask()">show tasks</div>
<?php } ?>
and have function in
first_proj\protected\controllers\project.php
this is
public function actionIsProjectmanager(){
$project_manager = false;
$crt = new CDbCriteria;
$crt->condition = 'user_id=:uid and role=1';
$crt->params = array('uid'=>Yii::app()->user->id);
$project_manager= projectMember::model()->findAll($crt);
// $model_result = MyModel::model()->test();
$this->render('the url to theme and main.php file', array('is_project_manager' => $project_manager));
}
how can i reach to that main.php file ? what i must write instead of
the url to theme and main.php file in my function ?

Answer 1

You set the controllers layout to the file. So it would look like this:
$this->layout = 'main';
Layouts must be rendered with a view file as well though.
$this->render('index', array('is_project_manager' => $project_manager));
Then place an index.php file in your views/project folder with the actions content.
This assumes you've setup your config to have the theme as project

Answer 2

First thing you need to know is: No need to pass layout file to the view. When you use render() function, yii automatically add layout to your view. Then, For specifying the layout, you need to use $this->layout = '//layouts/main in your action.

Answer 3

use this in your view
<?php
if($this->isProjectmanager){
?>
<div class="each-pop-el" style="cursor:pointer" ng-click="showAllMemberTask()">show tasks</div>
<?php } ?>
and create a helper function (not an action!) in your controller
public function IsProjectmanager(){
if ($someConditon) {
return true;
}
else {
return false;
}
}