which object is missing? - php

Question

I am unable to understand why this error is popping up. I do know that the obvious reason why these kind of errors come up but I did look and re-look into my code and cannot understand why!
The error is:
Fatal error: Call to a member function prepare() on a non-object
Here are the code snippets.
db_connect.php
<?php
include_once 'psl-config.php'; // As functions.php is not included
$mysqli = new mysqli(HOST, USER, PASSWORD, DATABASE);
customer.php
include_once 'includes/db_connect.php';
include_once 'includes/functions.php';
.
.
.
function myCallBackFunction($array) {
//echo ".";
// print_r($array);
$amount=$array['amount'];
$date=$array['date'];
if(transaction($mysqli, $date, $amount))
{
echo "Transaction table Updated";
}
}
functions.php
//Function to insert transactions
function transaction($mysqli, $date, $amount) {
if($smt = $mysqli->prepare("INSERT INTO `tbltransaction` (entry_date,income) VALUES (?,?)
ON DUPLICATE KEY UPDATE income=income+?;"));
{
$stmt->bind_param('sii', $date, $amount, $amount); // Bind "$date" and "$amount" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
if ($stmt->num_rows == 1) {
return true;
} else {
return false;
}
}
}
tbltransaction
Column Type Null Default Comments MIME
entry_date date No
income int(11) No
P.S: another function in the functions.php file is working just fine, here is the function and the way I am calling it
function
//Function to display notice
function notice($mysqli) {
$notice = null;
if ($stmt = $mysqli->prepare("SELECT notice FROM tblnotice ORDER BY ID DESC LIMIT 1")) {
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
// get variables from result.
$stmt->bind_result($notice);
$stmt->fetch();
return $notice;
}
}
calling the function
<?php echo notice($mysqli); ?>

Answer 1

This is a variable scope issue - you need to pass the $mysqli object in to the myCallBackFunction function as a second parameter or it won't be set inside that function.
Like this:
function myCallBackFunction($array, $mysqli) {
Then where you call that function you'll need to pass in the $mysqli object:
myCallBackFunction($array, $mysqli);

Answer 2

you do alternatively
function notice() {
global $mysqli;
$notice = null;
if ($stmt = $mysqli->prepare("SELECT notice FROM tblnotice ORDER BY ID DESC LIMIT 1")) {
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
// get variables from result.
$stmt->bind_result($notice);
$stmt->fetch();
return $notice;
}
}