How to use PSR-4 in methods with PHP - php

Excuse me guys I am trying to use PSR-4 into my PHP project until now I have only one problem; If I only use classes
<?php namespace backend\controllers;
class Conexion
{
public function __construct() {
echo "hi";
}
}
and after in other file I put this it works fine
<?php
require_once __DIR__.'/vendor/autoload.php';
use backend\controllers\Conexion as Conexion;
$user = new backend\controllers\Conexion;
but if I try to change in the first block code by this:
<?php namespace backend\controllers;
class Conexion
{
public function __construct() {
$conexion = new mysqli('localhost','mysql','root','');
if($conexion) {
echo "1";
} else {
echo "0";
}
}
}
I get that following error
Fatal error: Class 'backend\controllers\mysqli' not found in
C:\xampp\htdocs\master-pure-php\app\backend\controllers\DataBaseController.php
on line 9
But I need to use a named method inside a class but I don't know how to do it.
Thanks in advance

As you can see - it's looking for mysqli under 'backend\controllers\mysqli'
A Quick fix...
Change
$conexion = new mysqli('localhost','mysql','root','');
to
$conexion = new \mysqli('localhost','mysql','root','');

The mysqli class is defined in the global namespace; in order to use it you could put this in your source code (at the top of your script):
use mysqli;

Related

How to extend PHP class in mulitple files and mark every extend in namespace?

I have the following code:
File: class.engine.php (The Main Engine of the website)
<?php
namespace Core;
class Engine {
}
File class.errors.php (The Error trigger if something happens, customized errors)
<?php
namespace Core\Errors;
class Errors {
public function TrigerError($e)
{
die($e);
}
}
File class.mysqli.php (The database connector)
<?php
namespace Core\MySQLiDrv;
class MySQLiDrv {
public $db = null;
public function __construct($database) {
$connector = mysqli_connect($database[0], $database[1], $database[2], $database[3]);
if(!$connector)
{
return new TrigerError("1");
}
}
}
File index.php (Where everything runs)
<?php
include("engine/class.engine.php");
include("engine/class.errors.php");
include("engine/class.mysqli.php");
$engine = new Engine();
$db = new MySQLiDrv(array("localhost", "user", "pass", "db"));
I want to extend Engine class with many multiple files and I want them to be in namespace, how can I do that properly, because I can't trigger the error in this case of the code.
And is it important in this case of code to use namespaces defined as something for easy use?
Your main issue as I see it is the lack of the USE statement and the fact that TrigerError is a method and not a class.
To fix these:
namespace Core\MySQLiDrv;
use Core\Errors\Errors;
class MySQLiDrv {
public $db = null;
public function __construct($database) {
$connector = mysqli_connect($database[0], $database[1], $database[2], $database[3]);
if(!$connector)
{
return (new Errors)->TrigerError("1");
}
}
}
Full working code:
namespace Core{
class Engine {
}
}
namespace Core\Errors{
class Errors {
public function TrigerError($e)
{
die($e);
}
}
}
namespace Core\MySQLiDrv{
use Core\Errors\Errors;
class MySQLiDrv {
public $db = null;
public function __construct($database) {
//$connector = mysqli_connect($database[0], $database[1], $database[2], $database[3]);
//if(!$connector)
//{
return (new Errors)->TrigerError("1");
//}
}
}
}
//default global namesapce
namespace {
use Core\Engine;
use Core\MySQLiDrv\MySQLiDrv;
$engine = new Engine();
$db = new MySQLiDrv(array("localhost", "user", "pass", "db"));
}
Output
1
Sandbox
The only real difference here is that when you use multiple namespaces in a single file (sandbox) you have to enclose the code with {}. You can remove those if these are separate files. Well that and I cant use the DB functions in the sandbox, but that is irrelevant in this example because we want to trigger the error.
However as said in the comments, I would look into Autoloading and Exceptions both of which will help you here.
I have an autoloader on github you can play around with if you want, it's similar to what Composer uses/does. Composer is just more standardized.
Autoloadig basically uses a combination of the namespace and class to find the file at run time (when the class is instantiated). So there are some naming conventions to be aware of, for example take your class Core\Errors\Errors this should be located in Core/Errors/Errors.php The namespace and the file path should be the same. What this does is you can eliminate all the include statements and this loads the files only when needed auto-magically.

How can I use HTMLPurifier inside a PHP class?

As the title states; how can I use the HTMLPurifier library inside my class?
I'm trying to get to grips with OOP and PHP classes for the first time and have successfully built a class that connects to my database using my database class and returns a blog article.
I would now like to parse the HTML markup for the blog article using HTMLPurifier but I would like to achieve this inside my blog class and I'm wondering how it can be achieved, as HTMLPurifier is a class.
My class so far:
namespace Blog\Reader;
use PDO;
use HTMLPurifier_Config; <--- trying to include it here
use \Database\Connect;
class BlogReader {
private static $instance = null;
private static $article = null;
private static $config = null;
private static $db = null;
private static function InitDB() {
if (self::$db) return;
try {
$connect = Connect::getInstance(self::$config['database']);
self::$db = $connect->getConnection();
} catch (Throwable $t) {}
}
private function __construct($config) {
self::$config = $config;
}
public static function getInstance($config) {
if (!self::$instance) {
self::$instance = new BlogReader($config);
}
return self::$instance;
}
public static function getArticle($id) {
self::InitDB();
try {
if (self::$db) {
$q = self::$db->prepare("
// sql
");
$q->bindValue(':id', (int) $id, PDO::PARAM_INT);
$q->execute();
self::$article = $q->fetchAll(PDO::FETCH_ASSOC);
//////////// <----- and trying to use it here
$HTMLPurifier_Config = HTMLPurifier_Config::createDefault();
$purifier = new HTMLPurifier($HTMLPurifier_Config);
///////////
} else {
throw new Exception("No database connection found.");
self::$article = null;
}
} catch (Throwable $t) {
self::$article = null;
}
return self::$article;
}
private function __clone() {}
private function __sleep() {}
private function __wakeup() {}
}
However, I get the following error log when trying anything like this:
Uncaught Error: Class 'HTMLPurifier_Config' not found in
....../php/classes/blog/reader/blogreader.class.php
And the line number of the error is on this line:
$HTMLPurifier_Config = HTMLPurifier_Config::createDefault();
My class directory structure:
[root]
[blog]
blog.php <--- using classes here
[php]
afs-autoload.php
[classes]
[blog]
[database]
[vendor]
[htmlpurifier-4.10.0]
[library]
HTMLPurifier.auto.php <--- this is what I used to `include` on blog.php to autoload HTMLPurifier_Config::createDefault() and new HTMLPurifier($purifier_config).
My Autoloader (afs-autoload.php) file:
define('CLASS_ROOT', dirname(__FILE__));
spl_autoload_register(function ($class) {
$file = CLASS_ROOT . '/classes/' . str_replace('\\', '/', strtolower($class)) . '.class.php';
if (file_exists($file)) {
require $file;
}
});
I literally started learning classes today, so I'm really baffled as to how I can achieve this, especially with the namespace system I used.
I hope somebody with better experience can guide me in the right direction.
Rewritten answer:
1) Your auto loader is looking for <class>.class.php files; but your HTMLPurifier_Config is in a HTMLPurifier.auto.php file.
2) Still in your autoloader: str_replace('\\' You do not need to escape characters when in single quotes, so this should be: str_replace('\'.
3) This excellent answer should help you learn when and how to use the use PHP keyword.
4) Your issue is not the scope of your use (I don't think you even need to use use). But is that your autoloader is looking for the wrong type of files. Try manually loading the class using require and seeing if it works properly.
Original Answer
namespace Blog\Reader;
use PDO;
use HTMLPurifier_Config;
What you're actually doing here is using the values within the defined namespace; so you're using:
Blog\Reader\HTMLPurifier_Config
If you're HTMLPurifier_Config file is within its own namespace you need to specify that so that the "use" grabs the right data!
If its not in its own namespace then it will be in the global namespace which is identified with a slash:
namespace Blog\Reader;
use PDO;
use \HTMLPurifier_Config;
If it is in the namespace HTMLPurifier, for example:
namespace Blog\Reader;
use PDO;
use \HTMLPurifier\HTMLPurifier_Config;
to load the correct data reference.
Just to wrap this up, if you are using namespaces inside a class which as been placed in a namespace, this is how you create your purifier objects:
$config = \HTMLPurifier_Config::createDefault();
$purifier = new \HTMLPurifier($config);
$clean_html = $purifier->purify($dirty_html);
You do not have to use a use command since the HTMLPurifier classes themselves are not in a namespace. But when your code is in a namespace, you need to pre-pend '\' to non-namespaced classes.
namespace \Tdiscus; // This is the line that makes the difference.
use \Tsugi\Util\Net;
class Threads {
...
$config = \HTMLPurifier_Config::createDefault();
...
$retval = new \stdClass();
...
$dbh = new \PDO($dsn, $user, $password);
}
Because you placed the class in a namespace, any "non-namespaced" classes need a "" prefix - like PDO and stdClass in the above example.
The HTMLPurifier folks could have put their classes in a namespace - but they chose not to do that.
Using namespaces is a common practice when developing libraries intended for use with composer. But HTMLPurifier existed before composer was in common use and their classes have a nice unique prefix because they started out in a global class namespace - so they decided to leave well enough alone and not break the non-dynamic loading / non-namespace legacy adopters of their library.

PHP namespace Error (the name is already in use)

I'm trying to run this code on the same file:
namespace Foo1\Bar\SubBar;
class SubBarClass {
public function __construct() {
echo 'From Foo1';
}
}
namespace Foo2\Bar\SubBar;
class SubBarClass {
public function __construct() {
echo 'From Foo2';
}
}
use Foo1\Bar\SubBar;
$foo1 = new SubBarClass;
use Foo2\Bar\SubBar;
$foo2 = new SubBarClass;
The ideia is to change namespaces and echo the related value.
But it's returning the following error:
( ! ) Fatal error: Cannot use Foo2\Bar\SubBar as SubBar because the name is already in use in C:\wamp\www\xxx\namespaces.php on line 30
Line 30: use Foo2\Bar\SubBar;
How can I interchange namespaces on the same file?
Thks!
use keyword is used to import that namespace to be accessed in your current file scope. It does not act as a namespace "instance constructor".
You're current under Foo2\Bar\SubBar namespace. Like a directory of classes, while you're here, you should access other namespaces from the root (\):
$foo2 = new SubBarClass;
$foo1 = new \Foo1\Bar\SubBar\SubBarClass;
There is no need to use use for those namespaces (although you can, specially when they share parent namespaces), they are already declared in the same file you're using them.
For more information about this, consider reading the manual, where it describes using multiple namespaces in the same file.
This happens because the last defined namespace is the one currently active.
So, when I type:
use Foo1\Bar\SubBar;
I'm still on the last defined namespace: Foo2\Bar\SubBar.
Hence, when I type:
use Foo2\Bar\SubBar;
I'm trying to use the currently active namespace. That's why the Fatal error is returned.
On possible solution is:
namespace Foo1\Bar\SubBar;
class SubBarClass {
public function __construct() {
echo 'From Foo1';
}
}
namespace Foo2\Bar\SubBar;
class SubBarClass {
public function __construct() {
echo 'From Foo2';
}
}
use Foo1\Bar\SubBar;
$foo1 = new SubBar\SubBarClass;
echo '<br>';
$foo2 = new SubBarClass;
Cheers!

Included class inside another class is not declared PHP

I have the following __construct of a selfmade class;
public function __construct($ip, $user, $pass, $product) {
$this->_ip = $ip;
$this->_user = $user;
$this->_pass = $pass;
$this->_product = $product;
$this->ssh = new Net_SSH2($this->_ip);
if (!$this->ssh->login($this->_user, $this->_pass)) {
return 'Login Failed';
}
$this->sftp = new Net_SFTP($this->_ip);
if (!$this->sftp->login($this->_user, $this->_pass)) {
return 'Login Failed';
}
}
Now the problem is that it says Net_SSH2 and Net_SFTP is not declared, but I have included those classes at the page, im not sure, but can it be that I have to pass those classes into this class instead of just calling them?
If yes, how do I do that?
A better solution is to use autoload.
function __autoload($class_name) {
require_once $class_name . '.php';
}
Now, when you ask for a new class, it will be auto loaded.
Try this.
Have you included those classes using a require, include or an autoload function?
If you haven't, make sure the files in which those classes are defined are loaded.
Now, we need to check for the namespace.
At the top of the Net_SFTP, is there a namespace [SOMETHING]? If there is, you must refer to the fully qualified class name, or use this class.
An example:
<?php
namespace VendorName\BundleName;
class Net_SFTP {
....
}
?>
Now, in order to use this class, we must do one of the following:
<?php
use VendorName\BundleName\Net_SFTP;
...
$this->ssh = new Net_SFTP(...);
...
?>
Or, directly:
<?php
...
$this->ssh = new VendorName\BundleName\Net_SFTP(...);
...
?>

Cannot find Class with PHP Namespace

I posted some questions previously regarding the use of Namespaces in PHP and from what I got, this example code I have below should be working.
However I am getting errors when I try to use Namespace in PHP like this. Here is the first error when running the code below as is...
Fatal error: Class 'Controller' not found in E:\Controllers\testing.php on line 6
E:\Controller\testing.php File
<?php
use \Controller;
include('testcontroller.php');
$controller = new Controller;
$controller->show();
?>
E:\Controller\testcontroller.php File
<?php
use \Library\Registry;
namespace Controller
{
class Controller
{
public $registry;
function __construct()
{
include('E:\Library\Registry.class.php');
$this->registry = new Registry;
}
function show()
{
echo $this->registry;
echo '<br>Registry was ran inside testcontroller.php<br>';
}
}
}
?>
E:\Library\Registry.class.php File
<?php
namespace Library\Registry
{
class Registry
{
function __construct()
{
return 'Registry.class.php Constructor was ran';
}
}
}
?>
As you can see I tried to make it as simple as possible just to get the Namespace part working. I have tried different variations and cannot seem to figure it out.
Even when using use statement, you need to specify the namespace of the class you are trying to instantiate. There are a lot of examples here: http://www.php.net/manual/en/language.namespaces.importing.php
To understand it better, I will describe to you how it works. In your case, when you do use \Controller, the whole Controller namespace becomes available to you, but not the classes that are in this namespace. So, for example:
<?php
include('testcontroller.php');
use \Controller;
// Desired class is in namespace!
$controller = new Controller\Controller();
// Error, because in current scope there is no such class
$controller = new Controller();
$controller->show();
?>
Another example:
testcontoller.php:
<?php
namespace Some\Path\To\Controller;
class Controller
{
function __construct()
{
}
function show()
{
echo '<br>Was run inside testcontroller.php<br>';
}
}
?>
testing.php:
<?php
include('testcontroller.php');
use \Some\Path\To\Controller;
// We now can access Controller using only Controller namespace,
// not Some\Path\To\Controller
$controller = new Controller\Controller();
// Error, because, again, in current scope there is no such class
$controller = new Controller();
$controller->show();
?>
If you wish to import exactly the Controller class, you need to do use Controller\Controller - then this class will be accessible in your current scope.
Its not that good idea to name the namespace, like the class, because it is confusing (and I think this is what happens here). There moment you define the alias via use Controller this referenes to either a class \Controller, or the namespace \Controller, but your class, because it is within the namespace, is named \Controller\Controller 1
use Controller;
$class = new Controller\Controller;
or
$class = new \Controller\Controller;
or
use Controller\Controller;
$class = new Controller;
The idea is, that the moment you try to access a class with its relative name it tries to map the "first part" against any alias defined using use (remeber use MyClass is the same as use MyClass as MyClass. The thing after as is the alias).
namespace MyNamespace\MyPackage\SomeComponent\And\So\On {
class MyClass {}
}
namespace Another {
use MyNamespace\MyPackage\SomeComponent; // as SomeComponent
$class = new SomeComponent\An\So\On\MyClass;
}
As you can see PHP finds SomeComponent as the first part and maps it against the SomeComponent-alias the line above.
You can read more about it in the manual about namespaces.
1 Its called "Full-qualified classname", if you name a class with its complete name.
When you put a class Controller in the namespace Controller, then you have to reference it that way:
$controller = new Controller\Controller();
\Controller would be a class in the global (default) namespace, i.e. as if you used no namespace at all.
Strangely I have found that in my example code from the Question above, if I change all the Namespace's that are defined to something like MyLibrary so it would be like this code below...
E:\Library\Registry.class.php File
<?php
namespace MyLibrary
{
class Registry
{
function __construct()
{
echo 'Registry.class.php Constructor was ran';
}
}
}
?>
Then when I use use MyLibrary\Registry; in another file, I am able to access it how I had planned...
$this->registry = new Registry;
The reason this is very strange to me is this now makes a class name appear to be a Namespace as well. So I would not need to set a Namespace to 'MyLibrary\Library' to access the Registry instead I would do it like I showed in this answer to be able to access it with just calling the name of the class.
I hope this makes sense and helps someone else. I will not accept this as the answer as I am hoping someone with more know-how will come in and post a better Answer with explanation
try
<?php
use \Library\Registry;
namespace Controller;
class Controller
{
public $registry;
function __construct()
{
include('E:\Library\Registry.class.php');
$this->registry = new Registry;
}
function show()
{
echo $this->registry;
echo '<br>Registry was ran inside testcontroller.php<br>';
}
}
?>
and
<?php
namespace Library\Registry;
class Registry
{
function __construct()
{
return 'Registry.class.php Constructor was ran';
}
}
?>
First off, I believe you are using composer or composer is initialised in your project. If so, check composer.json file for your autoload, psr-4 definition. For example, if the root of your application is "App", then in your psr-4, you should be doing "autoload": { "psr-4": { "App\\": "./" } },
Furthermore, remember to clear composer cache and dump-autoload from the terminal as follows:
composer clear-cache
composer dump-autoload

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