My numbers is this;
$input =array{1,2,3,4,6,8,11}
I want to make it;
$input =array{1,2,3,4,5,6,7}
*changing 6 to 5, 8 to 6 and 11 to 7
I hope you are getting what I am trying to say.
try this
EDIT
$input =array(1,2,3,4,6,8,11);
for($i=0;$i<count($input);$i++)
{
if($input[$i]!=($i+1))
{
$input[$i] = ($i+1);
}
}
print_r($input);
use this
$input = array_values($input);
array_values() returns all the values from the array and indexes the array numerically.
to make it a base one array:
array_unshift($input, "dummy");
unset($input[0]);
EDIT:
I see, I may have misunderstood the question. try this:
$input_ = array();
for($i=1; $i <= count($input); $i++) {
$input_[] = $i;
}
print_r($input_);
This is an odd request and i'm not sure what the logic or reasoning behind it is. Nethertheless just flipping the array keys with the array values will produce this result. We insert an empty value and then remove it to give the index start of 1.
$input = array(1,2,3,4,6,8,11);
array_unshift($input,"");
unset($input[0]);
$flipped = array_flip($input);
try this
$input =array(1,2,3,4,6,8,11);
array_push($input,1);
$res = array_keys(array_values($input));
$data = array_shift($res);
echo "<pre>";
print_r($res);
result array
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
)
Related
I have a little problem. Here is the code:
$arr = explode(',', $odluka);
$arr2 = array($arr[0], $arr[1], $arr[2], $arr[3], $arr[4], $arr[5], $arr[6], $arr[7], $arr[8], $arr[9]);
while ($arrk = current($arr2)) {
if ($arrk == '1') {
$ark = key($arr2);
//print_r($ark);
//echo $arr2[$ark];
$arop = explode(',', $utroseno);
$aropk = array($arop[0], $arop[1], $arop[2], $arop[3], $arop[4], $arop[5], $arop[6], $arop[7], $arop[8], $arop[9]);
$array = array($aropk[$ark]);
print_r($array);
}
next($arr2);
}
Output of $array is
Array ( [0] => 1 ) Array ( [0] => 5 ) Array ( [0] => 10 ) Array ( [0] => 4 ) Array ( [0] => 4 ) Array ( [0] => 1 ) Array ( [0] => 1 )
How can I merge this values and sum them. I want sum of 1+5+10+4+4+1+1. Thanks!
declare a variable to store sum
iterate over array
-> add value to sum
Here is a simple example how to deal with your output array:
$data = [
[1], [5], [10], [4]
];
$sum = array_sum(array_map(function($elem) { return $elem[0]; }, $data));
var_dump($sum);
You don't need to assign them to another array and loop..you can just sum everything after explode. You just need one line of code for that:
array_sum(explode(',', $odluka));
Then you'll get the sum of all the numbers
Not need using any array and loop.You are using only "array_sum ()" php building function.Like
<?php
$foo[] = "12";
$foo[] = 10;
$foo[] = "bar";
$foo[] = "summer";
echo array_sum ($foo); //same as echo "22";
?>
For more information Read Php Manual link
Use this function
array_sum ($arr);
I'm probably [super]overthinking this. I'm trying to analyze an array with values like [1,9], [4,6] [5,5], [6,4], [9,1] and duplicate digits (I'm having a super brain fart and can't even remember the term for numbers like this) remove (the last two) so that only [1,9], [4,6] [5,5] are printed.
I was thinking that turning this array into a string and using preg_match, but I'm pretty sure this wouldn't work even if I had the correct regex.
If you have an array of pairs like this:
$x = array(
array(1,9),
array(4,6),
array(5,5),
array(6,4),
array(9,1)
);
Here is one way to get the unique pairs:
foreach ($x as $pair) {
sort($pair);
$unique_pairs[implode(',', $pair)] = $pair;
}
This uses string representations of each sorted pair as keys in a new array, so the result will have distinct values by definition.
As far as the printing them out part of your question, once you have the unique values you can loop over them and print them out in whichever format you like, for example:
foreach ($unique_pairs as $pair) { vprintf("[%d,%d]<br>", $pair); }
It looks like elements are distributed symmetrically.
We can cut the array in two halves and get only the first half with array_slice():
$array = array(
array(1,9),
array(4,6),
array(5,5),
array(6,4),
array(9,1),
);
print_r(array_slice($array, 0, ceil(count($array) / 2)));
Result:
Array(
[0] => Array(
[0] => 1
[1] => 9
)
[1] => Array(
[0] => 4
[1] => 6
)
[2] => Array(
[0] => 5
[1] => 5
)
)
Demo at Codepad.
ceil() is used to round the number up to the next highest integer if there is an even number of items in the array. Example: if there is 3 items in the array, 5 / 2 will return 2.5, we want 3 items so we use ceil(2.5) which gives 3.
Example with 3 items:
$array = array(
array(1,9),
array(5,5),
array(9,1),
);
print_r(array_slice($array, 0, ceil(count($array) / 2)));
Result:
Array(
[0] => Array(
[0] => 1
[1] => 9
)
[1] => Array(
[0] => 5
[1] => 5
)
)
Example with 4 items:
$array = array(
array(1,9),
array(7,7),
array(7,7),
array(9,1),
);
print_r(array_slice($array, 0, ceil(count($array) / 2)));
Result:
Array(
[0] => Array(
[0] => 1
[1] => 9
)
[1] => Array(
[0] => 7
[1] => 7
)
)
If I'm correct in understanding what you are trying to do, you want to remove the final 2 elements from the array?
There is a function in PHP called array_pop that removes the final element from the array.
$array = array_pop($array);
So if you run this twice, you will remove the final 2 elements from the array.
This is how I'd do it (and I hope I am not overthinking this :))
$stringArray = array();
$stringArray[] = '1,9';
$stringArray[] = '4,6';
$stringArray[] = '5,5';
$stringArray[] = '6,4';
$stringArray[] = '9,1';
foreach($stringArray as &$numString) {
$numString = explode(',', $numString);
usort($numString, function($a, $b) {return $a - $b;});
$numString = implode(',', $numString);
}
$a = array_unique($a);
print_r($a);
You basically explode every element into a subarray, sort it and then implode it back. After calling the array_unique, you're left with unique values in the array.
The output would be
Array
(
[0] => 1,9
[1] => 4,6
[2] => 5,5
)
The result you suggest treats [a,b] as equivalent to [b,a] which makes the problem a lot more complex. The code below gives the result you asked for, but without really understanding what the problem is that you are trying to fix and whether [1,9] is equivalent to [9,1] in the solution:
$a=array(array(1,9),array(4,6),...
$dup=array();
for ($i=0; $i<count($a) -1; $i++) {
for ($j=$i+1; $j<count($a); $j++) {
if (($a[$i][0]==$a[$j[0] && $a[$i][1]==$a[$j[1])
|| ($a[$i][0]==$a[$j[1] && $a[$i][1]==$a[$j[0])) {
$dup[]=$j;
}
}
}
foreach ($dup as $i) {
unset($a[$i]);
}
So I'm actually going to assume your question to have a different meaning than everyone else did. I believe what you're asking is:
How do you filter out array items where a reverse of the item has already been used?
<?php
// The example set you gave
$numberSets = [[1, 9], [4, 6], [5, 5], [6, 4], [9, 1]];
// Initialize an empty array to keep track of what we've seen
$keys = [];
// We use array filter to get rid of items we don't want
// (Notice that we use & on $keys, so that we can update the variable in the global scope)
$numberSets = array_filter($numberSets, function($set) use(&$keys) {
// Reverse the array
$set = array_reverse($set);
// Create a string of the items
$key = implode('', $set);
// Get the reverse of the numbers
$reversedKey = strrev($key);
// If the palindrome of our string was used, return false to filter
if (isset($keys[$reversedKey])) {
return false;
}
// Set the key so it's not used again
// Since $keys is being passed by reference it is updated in global scope
$keys[$key] = true;
// Return true to NOT filter this item, since it or it's reverse were not matched
return true;
});
var_dump($numberSets);
I have the array:
$total =array();
Array (
[0] => Array
(
[0] => 1
[1] => 3
)
[1] => Array
(
[0] => 6
[1] => 7
[2] => 8
)
[2] => Array
(
[0] => 9
[1] => 10
)
)
I need to dynamically change each array into an indexed array for a Cartesian function.
Here is how I need the code to look for the function to work correctly:
$count = cartesian(
Array(1,3),
Array(6,7,8),
Array(9,10)
);
Any help would be greatly appreciated! I have tried flattening, looping, using array_values, using just the array itself and I keep falling short.
Thanks
Nick
function cartesian() {
$_ = func_get_args();
if(count($_) == 0)
return array(array());
$a = array_shift($_);
$c = call_user_func_array(__FUNCTION__, $_);
$r = array();
foreach($a as $v)
foreach($c as $p)
$r[] = array_merge(array($v), $p);
return $r;
}
$count = call_user_func('cartesian', array($total));
print_r($count);
Your arrays already look exactly the way you want them to. array(1,3) is the same as array(0 => 1, 1 => 3) and both are an array with the value 1 at key 0 and 3 at key 1. Exactly what the debug output shows you.
It seems you just need to pass them as separate arguments to the function. E.g.:
cartesian($total[0], $total[1], $total[2])
For dynamic lengths of arrays, do:
call_user_func_array('cartesian', $total)
I believe that your $total array is multi-dimensional array with numeric indexed. So yo can try like this
$count = cartesian($total[0], $total[1], $total[2]);
I have an array in php like
array(1,3,0,6,0,6,9,0);
I want to remove '0' elements from this array. and get array like that array(1,3,6,6,9)
I am new user i cannot tell my question very well so sorry in advance please.
Filters out all 0.
$array = array_filter($array);
Another approach could be:
$arr = array(1,3,0,6,0,6,9,0);
$arr = array_filter($arr, function($el) { return $el != 0; });
Do like this
<?php
$arr = array(1,3,0,6,0,6,9,0);
foreach($arr as $k=>$v)
{
if($v==0)
{
unset($arr[$k]);
}
}
print_r($arr);
OUTPUT :
Array
(
[0] => 1
[1] => 3
[3] => 6
[5] => 6
[6] => 9
)
Is it possible to divide a number into an array based on its value?
For example:
$val = 3;
// do something here to convert the number 3 into 1's
Array
(
[0] => 1
[1] => 1
[2] => 1
)
$array = array_fill(0, $val, 1);
array_fill(0, $val, 1);
will create an array
Array
(
[0] => 1
[1] => 1
[2] => 1
)
Do something like this:
$arr = Array();
for ($i=0;$i<$val;$i++) {
$arr[] = 1;
}
But with larger numbers you may need something different.
Another slightly shorter solution is to use range()
$val = 3;
$array = range(1, $val);
print_r($array);
// Output:
// Array
// (
// [0] => 1
// [1] => 2
// [2] => 3
// )
It's not possible for the value to be negative, or zero.
That's good, because all of these solutions (including loops) won't work with a zero or negative. However, range() will give you a different result (the 5 digit range of 1 to -3, for example).