Any Echo value how to direct store in database - php

Question

I have created a simple Business Management setup for office work. First I fetch all information from database. All is going well except the quantity input.
In this all payment doing calculate sum and do Echo. But I want that this echo value detect automatic store in database in another table.
so how to complete this?
This is the code of program.
<tbody>
<?php
$respectivestud = mysql_query("select * from client where client_id");
$i = 1;
while($r_client = mysql_fetch_array($respectivestud))
{
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $r_client['name']; ?></td>
<td><?php echo $r_client['project_name']; ?></td>
<td><?php echo $r_client['cost']; ?></td>
<td><?php echo $r_client['payment_1']; ?></td>
<td><?php echo $r_client['payment_2']; ?></td>
<td><?php echo $r_client['payment_3']; ?></td>
<td><?php echo $r_client['payment_4']; ?></td>
<td><?php echo $r_client['payment_5']; ?></td>
<?php $total = $r_client['payment_1'] + $r_client['payment_2'] + $r_client['payment_3'] + $r_client['payment_4'] + $r_client['payment_5'];?>
<td> <?php echo $total ; ?></td>
<?php $remain = $r_client['cost'] - $total;?>
<td><?php echo $remain; ?></td>
**<td>**

Answer 1

Please make sure you write valid PHP code. You are not closing your while and you are not closing tags correctly. This should be correct.
<tbody>
<?php
$respectivestud = mysql_query("select * from client where client_id");
$i = 1;
while($r_client = mysql_fetch_array($respectivestud))
{
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $r_client['name']; ?></td>
<td><?php echo $r_client['project_name']; ?></td>
<td><?php echo $r_client['cost']; ?></td>
<td><?php echo $r_client['payment_1']; ?></td>
<td><?php echo $r_client['payment_2']; ?></td>
<td><?php echo $r_client['payment_3']; ?></td>
<td><?php echo $r_client['payment_4']; ?></td>
<td><?php echo $r_client['payment_5']; ?></td>
<?php $total = $r_client['payment_1'] + $r_client['payment_2'] + $r_client['payment_3'] + $r_client['payment_4'] + $r_client['payment_5'];?>
<td> <?php echo $total ; ?></td>
<?php $remain = $r_client['cost'] - $total;?>
<td><?php echo $remain; ?></td>
</tr>
<?php
}
?>
</tbody>
To save data you could use this:
$sql=mysqli_query($connection,"insert into `tablename`(`columnname`)values('".$total."')");

Answer 2

foirst off all replace mysql_* with mysqli_* or Pdo statement. as mysql_* is depricated now . here is the reference mysqli and pdo
store the remaining ammount in a variable. then use this variable in update query . like
<td><?php echo $remaining_amount=$remain; ?></td>
then update in db
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE MyGuests SET tablename='".$remaining_amount."' WHERE id=yprimarykey";
if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $conn->error;
}

Answer 3

<td><?php echo $r_client['payment_5']; ?></td>
<?php $total = $r_client['payment_1'] + $r_client['payment_2'] +$r_client['payment_3'] + $r_client['payment_4'] + $r_client['payment_5'];?>
<td> $sql=mysqli_query($connection,"insert into `tablename`(`columnname`)values('".$total."')");</td>
you can do like this whatever the value you want to insert...