Insert and update database with php mysql - php

Question

I want to insert and update customer data by clicking on insert and update button using functions but when I click on insert or update button no data is inserted or updated whats the problem with my code??
<form action="Customer.php" method="post">
<div>
<form>
Phone No <input type="number" placeholder="Search" name="phoneno" />
First Name <input type="text" name="FirstName" />
Last Name<input type="text" name="LastName" />
Phone No<input type="number" name="CustomerPhoneNo" />
Address<input type="text" name="Address" />
Customer ID<input type="number" name="CustomerID" />
<input type="Submit" value="Add Customer" style="font-size:20px" onClick="insert()">
<input type="Submit" value="Update Customer" style="font-size:20px" onClick="update()">
</form>
</div>
"Customer.php"
<?php
$dbhost="127.0.0.1";
$dbname="root";
$dbuser="info";
$dbpsd="";
$link = mysqli_connect("$dbhost", "$dbuser", "$dbpsd", "$dbname");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$phoneno = mysqli_real_escape_string($link, $_POST['phoneno']);
$FirstName = mysqli_real_escape_string($link, $_POST['FirstName']);
$LastName = mysqli_real_escape_string($link, $_POST['LastName']);
$CustomerPhoneNo = mysqli_real_escape_string($link, $_POST['CustomerPhoneNo']);
$Address=mysqli_real_escape_string($link, $_POST['Address']);
$CustomerID = mysqli_real_escape_string($link, $_POST['CustomerID']);
function insert(){
$sql = "INSERT INTO clientinfo(phoneno, FirstName, LastName,CustomerPhoneNo,Address,CustomerID) VALUES ('$phoneno', '$FirstName', '$LastName','$CustomerPhoneNo','$Address','$CustomerID')";
echo "<span>Data Inserted successfully...!!</span>";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
function update(){
$sql="UPDATE clientinfo SET FirstName='$FirstName', LastName='$LastName',Address='$Address',CustomerID='$CustomerID WHERE phoneno='$phoneno' ";
if (mysqli_query($link, $sql)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($link);
}
}
close connection
mysqli_close($link);
?>

Answer 1

you can't use onclick tag to determine of requested page PHP function .
a easy way to do it . replace below codes at the customer.php file.
Replace :
function insert()
with :
if($_POST['Submit'] == 'Add Customer')
and replace :
function update()
with :
if($_POST['Submit'] == 'Update Customer')

Answer 2

Try this:
Delete the second tag and put the first one in that place.
Other thing, is that you need to review the code.
Review this Tutorial
PHP Tutorial

Answer 3

You are calling php function like js functions. They dont work like that. Define them like -
function insert($link, $post){
$phoneno = mysqli_real_escape_string($link, $post['phoneno']);
$FirstName = mysqli_real_escape_string($link, $post['FirstName']);
$LastName = mysqli_real_escape_string($link, $post['LastName']);
$CustomerPhoneNo = mysqli_real_escape_string($link, $post['CustomerPhoneNo']);
$Address=mysqli_real_escape_string($link, $post['Address']);
$CustomerID = mysqli_real_escape_string($link, $post['CustomerID']);
$sql = "INSERT INTO clientinfo(phoneno, FirstName, LastName,CustomerPhoneNo,Address,CustomerID) VALUES ('$phoneno', '$FirstName', '$LastName','$CustomerPhoneNo','$Address','$CustomerID')";
echo "<span>Data Inserted successfully...!!</span>";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
And cal them like -
insert($link, $_POST); // if it is inserting