How do I update the values in the table using PHP [closed] - php

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How do i actually update the values of table using PHP ? This code is not showing any error and its not updating either.
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'DB';
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if(mysqli_connect_error())
{
die("couldn't connect" . $conn->connect_error());
}
echo ("connected successfully");
$id = $_POST['Id'];
$name = $_POST['Name'];
$dept = $_POST['Department'];
$update = "update info set Name='$name', Department='$dept' where Id='$id'";
if($conn->query(update) === TRUE) {
echo ("Data updated successfully");
}
else
{
echo ("Data cant be updated" . $conn->error());
}
$conn->close();
?>

Answer 1

Hope this one help you!
$update = "update info set Name='".$name."', Department='".$dept."' where Id='".$id."'";

Answer 2

Check this part of your code:
if($conn->query(update) === TRUE) {
where it should be:
if($conn->query($update) === TRUE) {
Make sure that you are using the correct credentials (host, username, password, database name) according to your MySQL database.
Also your table name and column name should be correct which are being used in your query.
Make sure that there is a match with your condition part of your query (... WHERE Id='$id'). Check it by running a query in your PhpMyAdmin page, or Search the ID, which is also the one you try to input in your form.
Make sure that the name of the passed variables ($_POST[]) are correct.
Be case sensitive.
Try changing your connection into:
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
/* CHECK CONNECTION */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
Other way to execute your query is to simply:
mysqli_query($conn,$update);
Recommendation:
You should escape the values of your variables before using them into your query by using mysqli_real_escape_string() function:
$name = mysqli_real_escape_string($conn,$_POST["Name"]);
Or better, so you won't need to worry about binding variables into your query and as well prevent SQL injections, you should move to mysqli_* prepared statement:
if($stmt = $conn->prepare("UPDATE info SET Name=?, Department=? WHERE Id=?")){
$stmt->bind_param("ssi",$_POST['Name'],$_POST['Department'],$_POST['Id']);
$stmt->execute();
$stmt->close();
}

Answer 3

$update = "update info set Name='".$name."', Department='".$dept."' where Id='".$id."'";
mysql_query($update);

Answer 4

$update = "update info set Name='".$name."',set Department='".$dept."' where Id='".$id."'";
if this is not help please provide form code.

Answer 5

Try this
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'DB';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
if(!$conn)
{
die("ERROR CONNECTING TO DATABASE!");
}
echo "Connected Successfully";
$id = $_POST['Id'];
$name = $_POST['Name'];
$dept = $_POST['Department'];
$update = "update info set Name='$name', Department='$dept' where Id='$id'";
$qry = mysqli_query($conn,$update);
if(!$qry) {
echo "Error Updating Details".mysqli_error($conn);
}
else
{
echo "Data updated successfully";
}
mysqli_close($conn);
?>
(Optional) Use secure things. Change to this for more secure.
$id = mysqli_real_escape_string($conn,$_POST['Id']);
$name = mysqli_real_escape_string($conn,$_POST['Name']);
$dept = mysqli_real_escape_string($conn,$_POST['Department']);