I'm try to display two data of one query using codeigniter.
$query = "SELECT count(distinct p.id_paciente), count(c.pacientes_id_paciente) FROM paciente p, cita c WHERE p.id_paciente=c.pacientes_id_paciente AND p.usuarios_id_usuario=43 AND p.aseguradoras_id_aseguradora=8 AND c.dia_cita>='2015-04-16' AND c.dia_cita<='2015-04-16'";
$sql = $this->db->query($query);
How can I to show the two results of count(distinct p.id_paciente) and the count(c.pacientes_id_paciente)
I try using
foreach ($sql->result_array() as $row)
{
echo $row['id_paciente'];
echo $row['pacientes_id_paciente'];
}
But only display the content of the array...
Thanks
There are several issues with your code:
Use aliases to name columns in the resultset to be able to address them later by name
SELECT COUNT(distinct p.id_paciente) AS count1, ...
^^^^^^
Don't interpolate query strings yourself. Use Codeigniter's query bindings
This may not be relevant to you but if dia_cita has time component to it (i.e. is of type datetime) you may want to change your WHERE condition to
c.dia_cita >= ? AND c.dia_cita < ? + INTERVAL 1 DAY
There is no need for foreach loop. You always get only one row with this query. Therefore use Codeigniter's row() or row_array().
That being said your code may look like
$sql = "
SELECT COUNT(DISTINCT p.id_paciente) AS count1,
COUNT(c.pacientes_id_paciente) AS count2
FROM paciente p JOIN cita c
ON p.id_paciente = c.pacientes_id_paciente
WHERE p.usuarios_id_usuario = ?
AND p.aseguradoras_id_aseguradora = ?
AND c.dia_cita >= ?
AND c.dia_cita < ? + INTERVAL 1 DAY
";
$bindings = array(43, 8, '2015-04-16', '2015-04-16')
$row = $this->db
->query($sql, $bindings)
->row_array();
echo $row['count1'], $row['count2'];
Related
This is 4 queries put into one. This is really old code and once I can make this work we can update it later to PDO for security. What I am trying to do is count rows from
select count(*) from dialogue_employees d_e,
dialogue_leaders d_l where
d_l.leader_group_id = d_e.leader_group_id
and use it in a formula where I also count how many rows from dialogue.status = 1.
The formula is on the bottom to create a percentage total from the results. This is PHP and MySQL and I wasn't sure the best way to count the rows and put them as a variable in php to be used in the formula on the bottom?
function calculate_site_score($start_date, $end_date, $status){
while($rows=mysql_fetch_array($sqls)){
$query = "
SELECT
dialogue.cycle_id,
$completecount = sum(dialogue.status) AS calculation,
$total_employees = count(dialogue_employees AND dialogue_leaders), dialogue_list.*,
FROM dialogue,
(SELECT * FROM dialogue_list WHERE status =1) AS status,
dialogue_employees d_e,
u.fname, u.lname, d_e.*
user u,
dialogue_list,
dialogue_leaders d_l
LEFT JOIN dialogue_list d_list
ON d_e.employee_id = d_list.employee_id,
WHERE
d_l.leader_group_id = d_e.leader_group_id
AND d_l.cycle_id = dialogue.cycle_id
AND u.userID = d_e.employee_id
AND dialogue_list.employee_id
AND site_id='$_SESSION[siteID]'
AND start_date >= '$start_date'
AND start_date <= '$end_date'";
$sqls=mysql_query($query) or die(mysql_error());
}
$sitescore=($completecount/$total_employees)*100;
return round($sitescore,2);
}
If you separate out your queries you will gain more control over your data. You have to be careful what your counting. It's pretty crowded in there.
If you just wanted to clean up your function you can stack your queries like this so they make more sense, that function is very crowded.
function calculate_site_score($start_date, $end_date, $status){
$query="select * from dialogue;";
if ($result = $mysqli->query($query))) {
//iterate your result
$neededElem = $result['elem'];
$query="select * from dialogue_list where status =1 and otherElem = " . $neededElem . ";";
//give it a name other than $sqls, something that makes sense.
$list = $mysqli->query($query);
//iterate list, and parse results for what you need
foreach($list as $k => $v){
//go a level deeper, or calculate, rinse and repeat
}
}
Then do your counts separately.
So it would help if you separate queries each on their own.
Here is a count example How do I count columns of a table
I got a little problem, I've got a database, in that database are different names, id, and coins. I want to show people their rank, so your rank has to be 1 if you have the most coins, and 78172 as example when your number 78172 with coins.
I know I can do something like this:
SELECT `naam` , `coins`
FROM `gebruikers`
ORDER BY `coins` DESC
But how can I get the rank you are, in PHP :S ?
You can use a loop and a counter. The first row from MySql is going the first rank,I.e first in the list.
I presume you want something like:
1st - John Doe
2nd - Jane Doe
..
..
right?
See: http://www.if-not-true-then-false.com/2010/php-1st-2nd-3rd-4th-5th-6th-php-add-ordinal-number-suffix
Helped me a while ago.
You could use a new varariable
$i = "1";
pe care o poti folosi in structura ta foreach,while,for,repeat si o incrementezi mereu.
and you use it in structures like foreach,while,for,repeat and increment it
$i++;
this is the simplest way
No code samples above... so here it is in PHP
// Your SQL query above, with limits, in this case it starts from the 11th ranking (0 is the starting index) up to the 20th
$start = 10; // 0-based index
$page_size = 10;
$stmt = $pdo->query("SELECT `naam` , `coins` FROM `gebruikers` ORDER BY `coins` DESC LIMIT {$start}, {$page_size}");
$data = $stmt->fetchAll();
// In your template or whatever you use to output
foreach ($data as $rank => $row) {
// array index is 0-based, so add 1 and where you wanted to started to get rank
echo ($rank + 1 + $start) . ": {$row['naam']}<br />";
}
Note: I'm too lazy to put in a prepared statement, but please look it up and use prepared statements.
If you have a session table, you would pull the records from that, then use those values to get the coin values, and sort descending.
If we assume your Session table is sessions(session_id int not null auto_increment, user_id int not null, session_time,...) and we assume that only users who are logged in would have a session value, then your SQL would look something like this: (Note:I am assuming that you also have a user_id column on your gebruikers table)
SELECT g.*
FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id
ORDER BY g.coins DESC
You would then use a row iterator to loop through the results and display "1", "2", "3", etc. The short version of which would look like
//Connect to database using whatever method you like, I will assume mysql_connect()
$sql = "SELECT g.* FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id ORDER BY g.coins DESC";
$result = mysql_query($sql,$con); //Where $con is your mysql_connect() variable;
$i = 0;
while($row = mysql_fetch_assoc($result,$con)){
$row['rank'] = $i;
$i++;
//Whatever else you need to do;
}
EDIT
In messing around with a SQLFiddle found at http://sqlfiddle.com/#!2/8faa9/6
I came accross something that works there; I don't know if it will work when given in php, but I figured I would show it to you either way
SET #rank = 0; SELECT *,(#rank := #rank+1) as rank FROM something order by coins DESC
EDIT 2
This works in a php query from a file.
SELECT #rank:=#rank as rank,
g.*
FROM
(SELECT #rank:=0) as z,
gebruikers as g
ORDER BY coins DESC
If you want to get the rank of one specific user, you can do that in mysql directly by counting the number of users that have more coins that the user you want to rank:
SELECT COUNT(*)
FROM `gebruikers`
WHERE `coins` > (SELECT `coins` FROM `gebruikers` WHERE `naam` = :some_name)
(assuming a search by name)
Now the rank will be the count returned + 1.
Or you do SELECT COUNT(*) + 1 in mysql...
Hi i have such table information:
what i want to do with php with while or just in mysql, is to SUM (time_used) of the rows with status 44 until its reached row with status 55. after that it should begin from start with new summing.
first query should return 37, second 76 (keep in mind it should be universal, for unlimited occurrences of 55 status row)
i thought of a way with time/date filtering and have this:
select sum(time_used) as sumed
from timelog
where start_time > (select end_time from timelog where (status='55')
ORDER BY id DESC LIMIT 1) ORDER BY id DESC
but this works only for last combination of 44 and 55
i know i will need two way filtering( < end_time and > end_time) so it will work for all cases, but cant think of a way to do it in php
can anyone help me?
EDIT:
sqlfiddle whoever want it:
http://sqlfiddle.com/#!2/33820/2/0
There are two ways to do it: Plain SQL or PHP. If you treat thousands of rows, it may be interresting to choose between the two by testing performance.
Plain SQL
select project_id, task_id, user_id, sum(time_used) as time_used,
min(start_time) as start_time, max(end_time) as end_time, max(comment) as comment from
(select t.id, t.project_id, t.task_id, t.user_id, t.time_used,
count(t2.id) as count55, t.start_time, t.end_time, t.comment
from timelog t
left join timelog t2 on t.id>t2.id and t2.status=55 and t.task_id=t2.task_id
group by t.id) as t
group by count55;
I assume here that a task can belong to one user only
SQL and PHP
$link = mysqli_connect( ... );
$query = "select id, project_id, task_id, user_id, time_used, start_time, end_time, status
from timelog order by id";
$result = mysqli_query($link, $query);
$table = array();
$time_used = 0;
$start_sum = true;
$i = 0;
while($row = mysqli_fetch_assoc ($result)){
if($start_sum){
$table[$i] = $row;
$start_sum = false;
} else {
$table[$i]['time_used'] += $row['time_used'];
$table[$i]['end_time'] += $row['end_time'];
}
if($row['state'] == 55){
$i++;
$start_sum = true;
}
}
If two tasks can run in simultaneously, solution 1 will work, but solution 2 will need to be adapted in order to take this in account.
here is my intepretation:
http://sqlfiddle.com/#!2/33820/45
set #n=0;
select project_id, task_id, user_id,sum(time_used) from (
SELECT time_used,project_id, task_id, user_id,
#n:=if(status=55,#n+1,#n),
if(status=55,-1,#n) as grouper FROM timelog
) as t
where grouper>-1
group by grouper;
I'm neither a php nor MySQL programmer, but I can explain the logic you want to follow. You can then code it.
First, query your db and return the results to php.
Next, set two sum variables to 0.
Start looping through your query results. Increment the first sum variable until you reach the first row that has status 55. Once you do, start incrementing the second variable.
The tricky part will be to sort your query by the row number of the table. Here is a link that will help you with that part.
I have a query that uses PostgreSQL generate_series function but when it comes to large amounts of data, the query can be slow. An example of code the generates the query is below:
$yesterday = date('Y-m-d',(strtotime ( '-1 day' ) ));
$query = "
WITH interval_step AS (
SELECT gs::date AS interval_dt, random() AS r
FROM generate_series('$yesterday'::timestamp, '2015-01-01', '1 day') AS gs)
SELECT articles.article_id, article_title, article_excerpt, article_author, article_link, article_default_image, article_date_published, article_bias_avg, article_rating_avg
FROM development.articles JOIN interval_step ON articles.article_date_added::date=interval_step.interval_dt ";
if (isset($this -> registry -> get['category'])) {
$query .= "
JOIN development.feed_articles ON articles.article_id = feed_articles.article_id
JOIN development.rss_feeds ON feed_articles.rss_feed_id = rss_feeds.rss_feed_id
JOIN development.news_categories ON rss_feeds.news_category_id = news_categories.news_category_id
WHERE news_category_name = $1";
$params = array($category_name);
$query_name = 'browse_category';
}
$query .= " ORDER BY interval_step.interval_dt DESC, RANDOM() LIMIT 20;";
This series looks for only content that goes one day back and sorts the results in random order. My question is what are was that generate_series can be optimized to improve performance?
You don't need that generate_series at all. And do not concatenate query strings. Avoid it by making the parameter an empty string (or null) if it is not set:
if (!isset($this -> registry -> get['category']))
$category_name = '';
$query = "
select articles.article_id, article_title, article_excerpt, article_author, article_link, article_default_image, article_date_published, article_bias_avg, article_rating_avg
from
development.articles
inner join
development.feed_articles using (article_id)
inner join
development.rss_feeds using (rss_feed_id)
inner join
development.news_categories using (news_category_id)
where
(news_category_name = $1 or $1 = '')
and articles.article_date_added >= current_date - 1
order by
date_trunc('day', articles.article_date_added) desc,
random()
limit 20;
";
$params = array($category_name);
Passing $yesterday to the query is also not necessary as it can be done entirely in SQL.
If $category_name is empty it will return all categories:
(news_category_name = $1 or $1 = '')
Imho, try removing that random() in your order by statement. It probably has a much larger performance impact than you think. As things are it's probably ordering the entire set by interval_dt desc, random(), and then picking the top 20. Not advisable...
Try fetching e.g. 100 rows ordered by interval_dt desc instead, then shuffle them per the same logic, and pick 20 in your app. Or wrap the entire thing in a subquery limit 100, and re-order accordingly along the same lines.
How can I make the following queries done in one single query and get the result just the way it is in below?
// Begining of January
$ob = mysql_query(" SELECT SUM(salary_amount) AS total FROM teacherexpense WHERE month(disburse_date)='01' AND year(disburse_date)='$year' ");
$nt = mysql_fetch_assoc($ob);
$salaryamount= $nt['total'];
$ob = mysql_query(" SELECT SUM(other_expense_amount) AS expenseamount FROM otherexpense WHERE month(other_expense_date)='01' AND year(other_expense_date)='$year' ");
$nt = mysql_fetch_assoc($ob);
$expenseamount= $nt['expenseamount'];
$jk = mysql_query(" SELECT SUM(amountpaid) AS revenue FROM studentpayment1 WHERE month(received_date)='01' AND year(received_date)='$year' ");
$t = mysql_fetch_assoc($jk);
$revenue= $t['revenue'];
$ob = mysql_query(" SELECT SUM(other_earning_amount) AS otherearningamount FROM otherearning WHERE month(other_earning_date)='01' AND year(other_earning_date)='$year' ");
$nt = mysql_fetch_assoc($ob);
$otherearningamount= $nt['otherearningamount'];
$January= ($revenue+$otherearningamount)-($salaryamount+$expenseamount);
// End of January
Stuff it in a Stored Procedure?
The database drivers for PHP won't let you run several queries separated with ; for security reasons.
Have you tried mysqli drivers instead of mysql?
Take a look at: mysqli_multi_query
Executes one or multiple queries which are concatenated by a semicolon.
SELECT 'withdrawals' t, SUM( amount ) sum
FROM withdrawals
UNION
SELECT 'statement' t, SUM( amount ) sum
FROM statement
while($row = mysql_fetch_assoc($result))
{
$total[$row['t']] = $row['sum'];
}
echo $total['withdrawals']; # 100
echo $total['statement']; # 624.x
You could use MySQL UNION - but you'll have to iterate over the resultset, because in that case you will get 4 records instead of one/statement group