HTML search field always echoeing zero results - php

Question

So basically I'm thinking that adding a search field to my website is out of my league, but internet has so much information that I decided to give it a go.
I started by adding a form to my index pagina, and this is the code I'm using:
<form method="get" action="search.php">
<table cellpadding="0px" cellspacing="0px">
<tr>
<td style="border-style:solid none solid solid;border-color:#4B7B9F;border-width:1px;">
<input type="text" name="q" style="width:100px; border:0px solid; height:17px; padding:0px 3px; position:relative;">
</td>
<td style="border-style:solid;border-color:#4B7B9F;border-width:1px;">
<input type="submit" value="" style="border-style: none; background: url('images/searchicon.gif') no-repeat; width: 24px; height: 19px;">
</td>
</tr>
</table>
</form>
Next up, my search.php code:
<?php
ini_set('display_errors', 0);
$search = $_GET ['q'];
mysql_connect("localhost", "root", "");
mysql_select_db("release");
$query = mysql_query("SELECT * FROM game WHERE name LIKE '%" . $queryString . "%'");
$foundnum = mysql_num_rows($query);
if ($foundnum == 0) {
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else {
echo "$foundnum results found !<p>";
$row = mysql_fetch_assoc($query);
{
echo '<p>'.$row['game_name'].'</p>';
}
}
?>
The query continuously echoes the $foundnum == 0 message even though the data I search for is in the game table.
However, when I try this code:
$query = mysql_query("SELECT game_name FROM game WHERE game_name LIKE '%" . $queryString . "%'");
The query prints '35 results found' on my screen. I have 35 entries in the database, but that doesn't make sense (to me) since I'm searching for one game name which is only entered once...

Answer 1

First of all you are using deprecated version mysql_* need to use mysqli_*. Please check below.
<?php
ini_set('display_errors', 2);
$search = $_GET ['q'];
// see changes from below line
$conn = mysqli_connect("localhost", "root", "","release");
$query = mysqli_query($conn,"SELECT game_name FROM game WHERE game_name LIKE '%". $search ."%'");
$foundnum = mysqli_fetch_array($query);
$count = count($foundnum['game_name']);
if ($foundnum == 0) {
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else {
echo "$count results found !<p>";
echo"<pre/>";print_r($foundnum['game_name']);
}
?>
Note:- remove include code from both index and search file that you write on upside.

Answer 2

From your second code it seems like there is a typo.
Try changing $query to
$query = mysql_query("SELECT * FROM game WHERE game_name LIKE '%" . $queryString . "%'");
and let me know if it works or not :)