PHP string compare and search in a multiple table column - php

Question

its my first post and I have a problem with a PHP search.
Here,
$searchq = $_POST['searchq'];
so far when a single word is supplied for searchq like naresh, google, lamgade then it search in a db but when there is a multiple search like
naresh lamgade at a same time then there is error for these word because it only search in a first_name column and what i want to search naresh in a first_name column and lamgade in a last_name column
Here is the code
<pre> $searchq = $_POST['searchq'];
$conn = mysqli_connect('localhost','root','','std_info') or die("Cant' Connect to db");
$query = mysqli_query($conn,"select * from student_details where first_name like '%$searchq%' or last_name like '%$searchq%'");
$count = mysqli_num_rows($query);
if($count == 0) {
echo "<br>";
echo "Can't find, try entering only first name or last name";
}
else {
do something`</pre>
}
The problem is
In a search bar, when i try entering naresh lamgade and search then
searchq =naresh+lamgade
and it search in both first_name and last_name column with a naresh+lamgade so there is no result.
I want to know , how to break these two words and search in a different column with these words.

Answer 1

The problem is
In a search bar, when i try entering naresh lamgade and search then
searchq =naresh+lamgade"
I guess that you put the textfield inside a form without method="post".
If you did, try like this in searchq:
... WHERE first_name LIKE "'%'.$searchq.'%'" or last_name like "'%'.$searchq.'%');

Answer 2

Use explode to split query.
Also your code is dangerous. Use mysqli_escape_real_string to escape special characters in a query:
<?php
$searchq = explode(" ", $_POST['searchq']);
$conn = mysqli_connect('localhost', 'root', '', 'std_info') or die("Cant' Connect to db");
$query = mysqli_query($conn, "select * from student_details where (first_name like '%" . mysqli_real_escape_string($searchq[0]) . "%' OR first_name like '%" . mysqli_real_escape_string($searchq[1]) . "%') OR (last_name like '%" . mysqli_real_escape_string($searchq[1]) . "%' OR last_name like '%" . mysqli_real_escape_string($searchq[0]) . "%'");
$count = mysqli_num_rows($query);
if ($count == 0)
{
echo "
";
echo "Can't find, try entering only first name or last name";
}
else
{
do something`

Answer 3

Thanks everyone for the answer but I have used this query and it's working perfectly as I wanted.
$query = mysqli_query($conn, "SELECT * FROM student_details WHERE CONCAT(first_name,' ',last_name) like '%$searchq%'");